(a)
To find a scanner plot of data.
(a)
Answer to Problem 87E
Graph
Explanation of Solution
Given Information :
Calculations:
The
The model is a good fit for the actual data.
(b)
To determine trigonometric model for the data.
(b)
Answer to Problem 87E
y =
Explanation of Solution
Given Information :
Calculations:
Use a cosine function in the form:
y = a cos (bx - c) + d
To determine a (amplitude), find the difference of the highest & lowest value of y & divide by 2:
a =
Since we are dealing with days, let period be 30 (30 days)
Since period =
Consider to be the left endpoint,
To determine d, the vertical shift, find the average of the highest & lowest value of I:
d =
The equation is:
y =
(c)
To find the graph of your model.
(c)
Answer to Problem 87E
Graph
Explanation of Solution
Given Information :
Calculations:
The scatter plot & model will be:
The model is a good fit for the actual data.
(d)
To find period of model.
(d)
Answer to Problem 87E
period = 30 which corresponds to 30 days in a month
Explanation of Solution
Given Information :
Calculations:
From (b), period = 30 which corresponds to 30 days in a month.
(e)
To find percent illuminate of the moon on June 21, 2017.
(e)
Answer to Problem 87E
y ˜ 0.835 = 83.5%
Explanation of Solution
Given Information :
Calculations:
June 21, 2017 is the 172ndday in 2017.
Therefore, x = 366 + 172 = 538
Using the model,
y =
y ˜ 0.835 = 83.5%
Chapter 4 Solutions
Precalculus with Limits: A Graphing Approach
- A tank contains 60 kg of salt and 2000 L of water. Pure water enters a tank at the rate 8 L/min. The solution is mixed and drains from the tank at the rate 11 L/min. Let y be the number of kg of salt in the tank after t minutes. The differential equation for this situation would be: dy dt y(0) =arrow_forwardSolve the initial value problem: y= 0.05y + 5 y(0) = 100 y(t) =arrow_forwardy=f'(x) 1 8 The function f is defined on the closed interval [0,8]. The graph of its derivative f' is shown above. How many relative minima are there for f(x)? O 2 6 4 00arrow_forward
- 60! 5!.7!.15!.33!arrow_forward• • Let > be a potential for the vector field F = (−2 y³, −6 xy² − 4 z³, −12 yz² + 4 2). Then the value of sin((-1.63, 2.06, 0.57) – (0,0,0)) is - 0.336 -0.931 -0.587 0.440 0.902 0.607 -0.609 0.146arrow_forwardThe value of cos(4M) where M is the magnitude of the vector field with potential ƒ = e² sin(лy) cos(π²) at x = 1, y = 1/4, z = 1/3 is 0.602 -0.323 0.712 -0.816 0.781 0.102 0.075 0.013arrow_forward
- There is exactly number a and one number b such that the vector field F = conservative. For those values of a and b, the value of cos(a) + sin(b) is (3ay + z, 3ayz + 3x, −by² + x) is -0.961 -0.772 -1.645 0.057 -0.961 1.764 -0.457 0.201arrow_forwardA: Tan Latitude / Tan P A = Tan 04° 30'/ Tan 77° 50.3' A= 0.016960 803 S CA named opposite to latitude, except when hour angle between 090° and 270°) B: Tan Declination | Sin P B Tan 052° 42.1'/ Sin 77° 50.3' B = 1.34 2905601 SCB is alway named same as declination) C = A + B = 1.35 9866404 S CC correction, A+/- B: if A and B have same name - add, If different name- subtract) = Tan Azimuth 1/Ccx cos Latitude) Tan Azimuth = 0.737640253 Azimuth = S 36.4° E CAzimuth takes combined name of C correction and Hour Angle - If LHA is between 0° and 180°, it is named "west", if LHA is between 180° and 360° it is named "east" True Azimuth= 143.6° Compass Azimuth = 145.0° Compass Error = 1.4° West Variation 4.0 East Deviation: 5.4 Westarrow_forwardds 5. Find a solution to this initial value problem: 3t2, s(0) = 5. dt 6. Find a solution to this initial value problem: A' = 0.03A, A(0) = 100.arrow_forward
- 2) Drive the frequency responses of the following rotor system with Non-Symmetric Stator. The system contains both external and internal damping. Show that the system loses the reciprocity property.arrow_forward1) Show that the force response of a MDOF system with general damping can be written as: X liax) -Σ = ral iw-s, + {0} iw-s,arrow_forward3) Prove that in extracting real mode ø, from a complex measured mode o, by maximizing the function: maz | ቀÇቃ | ||.|| ||.||2 is equivalent to the solution obtained from the followings: max Real(e)||2arrow_forward
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning