Chapter 4, Problem 10RE

To determine

To sketch: The standard position of $-{135}^{\circ }$ .

Explanation of Solution

Given: $-{135}^{\circ }$

This is in degree. Now draw the standard position of $-{135}^{\circ }$

  

To determine

To find: The quadrant of $-{135}^{\circ }$ .

Answer to Problem 10RE

III quadrant

Explanation of Solution

Given: $-{135}^{\circ }$

This is in degree. Now draw the standard position of $-{135}^{\circ }$

  

In graph seen, It lies in III quadrant.

To determine

To find: One negative and one positive co-terminal of $-{135}^{\circ }$ .

Answer to Problem 10RE

Positive co-terminal of $-{135}^{\circ }\Rightarrow {360}^{\circ }-{135}^{\circ }={225}^{\circ }$

Negative co-terminal of $-{135}^{\circ }\Rightarrow -{360}^{\circ }-{135}^{\circ }={495}^{\circ }$

Explanation of Solution

Given: $-{135}^{\circ }$

This is in degree. Now draw the standard position of $-{135}^{\circ }$

Now find the positive co-terminal of $-{135}^{\circ }\Rightarrow {360}^{\circ }-{135}^{\circ }={225}^{\circ }$

For negative co-terminal of $-{135}^{\circ }\Rightarrow -{360}^{\circ }-{135}^{\circ }={495}^{\circ }$