
To describe: the relationship between the graphs of f and g .

Explanation of Solution
Given information:
Given functions are
f(x)=cosxg(x)=cos(x+π)
Concept used:
For the standard equation is y=acosbx .
Amplitude is |a| and period is 2πb .
Calculation:
Comparing f(x)=cosx with the equation y=acosbx ,
a=1 and b=1
Thus,
Amplitude=|1|=1
And
Period=2πb=2π(1)=2π
The interval [0,2π] corresponds to one cycle on the graph.
The amplitude of y=asin(bx−c) and y=acos(bx−c) have following characteristics.
Amplitude=|a|Period=2πb
The left and right endpoints of one cycle interval can be determined by solving the equations
bx−c=0 and bx−c=2π
Comparing g(x)=cos(x+π) with the equation y=acos(bx−c) ,
a=1 and b=1
Thus,
Amplitude=|1|=1
And
Period=2πb=2π(1)=2π
The left end point is,
x+π=0x=−π
The right end point is,
x+π=2πx=π
So interval [−π,π] corresponds to one cycle on the graph.
Now plot the graphs of f(x) and g(x) :
By above graph it is seen that g(x) is a shift of f(x) π units to the left.
Chapter 4 Solutions
EBK PRECALCULUS W/LIMITS
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