Chapter 4.4, Problem 42E

To determine

To find the LCD

Answer to Problem 42E

  $\frac{3}{5}$ is greater than $\frac{6}{11}$ .

Explanation of Solution

Given information: $\frac{3}{5},\frac{6}{11}$

Formula Used: Factorisation

Calculation:

Convert these fractions to equivalent fractions with common denominator in order to compare them more easily.

LCM of 5 and 11 is 55

So ,denominator of both fractions 55.

  $\frac{3\times 11}{5\times 11}=\frac{33}{55}$

  $\frac{6\times 5}{11\times 5}=\frac{30}{55}$

  $\frac{33}{55}>\frac{30}{55}$

So, $\frac{3}{5}$ is greater than $\frac{6}{11}$ .