Holt Mcdougal Larson Pre-algebra: Student Edition 2012

1st Edition

ISBN: 9780547587776

Author: HOLT MCDOUGAL

Publisher: HOLT MCDOUGAL

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Question

Chapter 4.2, Problem 66E

To determine

To find the greatest number of identical first aid kits that could be made out of given items..

Expert Solution & Answer

Answer to Problem 66E

3 kits; 16 bandages, 5 squares of gauze, 3 tubes of antibiotic ointments and 3 packs of ice for each first aid kit.

Explanation of Solution

Given Information: 48 bandages, 15 squares of gauze, 6 tubes of antibiotic ointment and 6 ice packs.

Formula used: Find the greatest prime factor of the four items using factorization method.

Calculation:

The factors of 6 tubes of ointment are: 1, 2, 3, 6

The factors of 6 ice packs are: 1, 2, 3, 6

The factors of 15 squares of gauze are: 1, 3, 5, 15

The factors of 48 bandages are: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48

Then the greatest common factor for the 4 items is 3.

Therefore, a maximum of 3 identical kits could be made out of 48 bandages, 15 squares of gauze, 6 tubes of antibiotic ointment and 6 ice packs.

Now, to find the number of items each kit will contain divide the total number of kits(i.e. GCF) with each number of items.

For bandages $bandageskits=483=16$

16 bandages.
For gauze: $gauzekits=153=5$

5 squares of gauze

For antibiotic ointment: $tubeskits=93=3$

3 tubes of antibiotic ointments

For ice packs: $icepackskits=63=2$

3 packs of ice

Chapter 4.2, Problem 65E

Chapter 4.3, Problem 1C

Chapter 4 Solutions

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

Ch. 4.1 - Prob. 1C Ch. 4.1 - Prob. 2C Ch. 4.1 - Prob. 3C Ch. 4.1 - Prob. 4C Ch. 4.1 - Prob. 5C Ch. 4.1 - Prob. 6C Ch. 4.1 - Prob. 7C Ch. 4.1 - Prob. 8C Ch. 4.1 - Prob. 9C Ch. 4.1 - Prob. 10C

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