a.
To find the absolute maximum and absolute minimum.
a.
Answer to Problem 49E
The absolute maximum is
Explanation of Solution
Given:
0 | 1 | 2 | 3 | |
0 | 2 | 0 | -2 | |
3 | 0 | Does not exist | -3 | |
0 | -1 | Does not exist | 0 |
0<x<1 | 1<x<2 | 2<x<3 | |
+ | + | - | |
+ | - | - | |
- | - | - |
Calculation:
The absolute maximum is where the
From the given information,
The absolute maximum is
b.
To find the point of inflection .
b.
Answer to Problem 49E
There is no point of inflection.
Explanation of Solution
Given:
0 | 1 | 2 | 3 | |
0 | 2 | 0 | -2 | |
3 | 0 | Does not exist | -3 | |
0 | -1 | Does not exist | 0 |
0<x<1 | 1<x<2 | 2<x<3 | |
+ | + | - | |
+ | - | - | |
- | - | - |
Calculation:
The point of inflection is the point where
From the given information,
There is no point of inflection.
c.
The find the graph
c.
Answer to Problem 49E
The graph is
Explanation of Solution
Given:
0 | 1 | 2 | 3 | |
0 | 2 | 0 | -2 | |
3 | 0 | Does not exist | -3 | |
0 | -1 | Does not exist | 0 |
0<x<1 | 1<x<2 | 2<x<3 | |
+ | + | - | |
+ | - | - | |
- | - | - |
Calculation:
From the graph is
The end points are
There is no straight line in the graph.
The resulting graph will be
Chapter 4 Solutions
Advanced Placement Calculus Graphical Numerical Algebraic Sixth Edition High School Binding Copyright 2020
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