Chemistry 2012 Student Edition (hard Cover) Grade 11
Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
Question
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Chapter 4.3, Problem 18SP

(a)

Interpretation Introduction

Interpretation : The number of neutrons present in each of the elements is to be identified.

Concept Introduction :

The formula to calculate the number of neutrons is given as:

  Number of neutrons=Mass numberNumber of protons

(a)

Expert Solution
Check Mark

Answer to Problem 18SP

The neutrons present in 3580Br is 45 .

Explanation of Solution

The count of protons present in the nucleus of the atom gives the atomic number (Z).

The count of protons and neutrons present in the nucleus of the atom gives the mass number (A).

The general representation symbol of an element is given as ZAX .

Where, X is the element, Z is the atomic number, and A is the atomic number.

The number of neutrons in an element is the difference between the mass number and the number of protons in an element.

The formula to calculate the number of neutrons is given as

  Number of neutrons=Mass numberNumber of protons

In the given element 3580Br , the mass number is 80 and the number of protons is 35 .

Substitute the values in the above formula to calculate the number of neutrons.

  Number of neutrons=Mass numberNumber of protons=8035=45

The number of neutrons in 3580Br is 45 .

(b)

Interpretation Introduction

Interpretation : The number of neutrons present in each of the elements is to be identified.

Concept Introduction :

The formula to calculate the number of neutrons is given as:

  Number of neutrons=Mass numberNumber of protons

(b)

Expert Solution
Check Mark

Answer to Problem 18SP

The neutrons present in 1632S is 16 .

Explanation of Solution

The count of protons present in the nucleus of the atom gives the atomic number (Z).

The count of protons and neutrons present in the nucleus of the atom gives the mass number (A).

The general representation symbol of an element is given as ZAX .

Where, X is the element, Z is the atomic number, and A is the atomic number.

The number of neutrons in an element is the difference between the mass number and the number of protons in an element.

The formula to calculate the number of neutrons is given as:

  Number of neutrons=Mass numberNumber of protons

In the given element 1632S , the mass number is 32 and the number of protons is 16 .

Substitute the values in the above formula to calculate the number of neutrons.

  Number of neutrons=Mass numberNumber of protons=3216=16

The number of neutrons in 1632S is 16 .

(c)

Interpretation Introduction

Interpretation : The number of neutrons present in each of the elements is to be identified.

Concept Introduction :

The formula to calculate the number of neutrons is given as:

  Number of neutrons=Mass numberNumber of protons

(c)

Expert Solution
Check Mark

Answer to Problem 18SP

The neutrons present in 47108Ag is 61 .

Explanation of Solution

The count of protons present in the nucleus of the atom gives the atomic number (Z).

The count of protons and neutrons present in the nucleus of the atom gives the mass number (A).

The general representation symbol of an element is given as ZAX .

Where, X is the element, Z is the atomic number, and A is the atomic number.

The number of neutrons in an element is the difference between the mass number and the number of protons in an element.

The formula to calculate the number of neutrons is given as:

  Number of neutrons=Mass numberNumber of protons

In the given element 47108Ag , the mass number is 108 and the number of protons is 47 .

Substitute the values in the above formula to calculate the number of neutrons.

  Number of neutrons=Mass numberNumber of protons=10847=61

The number of neutrons in 47108Ag is 61 .

(d)

Interpretation Introduction

Interpretation : The number of neutrons present in each of the elements is to be identified.

Concept Introduction :

The formula to calculate the number of neutrons is given as:

  Number of neutrons=Mass numberNumber of protons

(d)

Expert Solution
Check Mark

Answer to Problem 18SP

The neutrons present in 82207Pb is 125 .

Explanation of Solution

The count of protons present in the nucleus of the atom gives the atomic number (Z).

The count of protons and neutrons present in the nucleus of the atom gives the mass number (A).

The general representation symbol of an element is given as ZAX .

Where, X is the element, Z is the atomic number, and A is the atomic number.

The number of neutrons in an element is the difference between the mass number and the number of protons in an element.

The formula to calculate the number of neutrons is given as:

  Number of neutrons=Mass numberNumber of protons

In the given element 82207Pb , the mass number is 207 and the number of protons is 82 .

Substitute the values in the above formula to calculate the number of neutrons.

  Number of neutrons=Mass numberNumber of protons=20782=125

The number of neutrons in 82207Pb is 125 .

Chapter 4 Solutions

Chemistry 2012 Student Edition (hard Cover) Grade 11

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