To compare: The heights of two projectiles: which projectile higher and how much higher.
The projectile- 1 goes higher at height 64 ft in 2 seconds.
Given data: The height h of projectile-1 fired straight up with initial velocity
Time ( t ) in seconds | 0.5 | 1.0 | 1.5 | 2.0 |
Height ( h ) in ft | 20 | 32 | 36 | 32 |
Formula used:
The height of the projectile at straight up height h is given by
Calculation:
The height h of projectile-1 fired straight up with initial velocity
Differentiating with respect to‘ t’
Thus, the velocity
The projectile will continue going up until its velocity becomes zero. At that time the height will be maximum.
Substitute 0 for
Thus after 2 second the projectile-1 will be at maximum height. Therefore, the maximum height of the projectile-1 is
Thus, the maximum height attain by the projectile-1 is 64 ft when
From table the maximum height of the projectile-2 is 36 ft when
Therefore, the projectile- 1 goes higher at height 64 ft in 2 seconds.
Chapter 4 Solutions
High School Math 2015 Common Core Algebra 2 Student Edition Grades 10/11
- Algebra and Trigonometry (6th Edition)AlgebraISBN:9780134463216Author:Robert F. BlitzerPublisher:PEARSONContemporary Abstract AlgebraAlgebraISBN:9781305657960Author:Joseph GallianPublisher:Cengage LearningLinear Algebra: A Modern IntroductionAlgebraISBN:9781285463247Author:David PoolePublisher:Cengage Learning
- Algebra And Trigonometry (11th Edition)AlgebraISBN:9780135163078Author:Michael SullivanPublisher:PEARSONIntroduction to Linear Algebra, Fifth EditionAlgebraISBN:9780980232776Author:Gilbert StrangPublisher:Wellesley-Cambridge PressCollege Algebra (Collegiate Math)AlgebraISBN:9780077836344Author:Julie Miller, Donna GerkenPublisher:McGraw-Hill Education