Holt Mcdougal Larson Algebra 2: Student Edition 2012
Holt Mcdougal Larson Algebra 2: Student Edition 2012
1st Edition
ISBN: 9780547647159
Author: HOLT MCDOUGAL
Publisher: HOLT MCDOUGAL
Expert Solution & Answer
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Chapter 4.1, Problem 42PS
Solution

(A)

To find: Write a model giving the number n of breeding pairs of bald eagle in t years.

The a model giving the number n of breeding pairs of bald eagle in t years is n=411.089t .

Given information:

Given that there were 41 breeding pairs over the next 24 years, the number of breeding pairs increased by about 8.9% each year.

Calculation:

Exponential growth model will be used here which is p=a1+rt here, a is initial value 1+r is is the growth factor.

Given a=41years , r=8.9100 .

Substitute the given values in p=a1+rt :

  n=411+.089tn=411.089t

(B)

To find: Write table values for model.

The table is given.

Given information:

Given that there were 41 breeding pairs over the next 24 years, the number of breeding pairs increased by about 8.9% each year.

Calculation:

The table for the population after t years will be calculated by substituting t=1,2,3......24 in

  n=411.089t

  n=411.0891n=44.689

Similarly, other values can be found

The table is given below:

    Time (t) Population
    144.689
    248.62
    352.92
    457.66
    562.79
    668.38
    774.47
    881.10
    988.32
    1096.18
    11104.73
    12114.06
    13124.21
    14135.26
    15147.30
    16160.41
    17174.69
    18190.23
    19207.16
    20225.60
    21245.68
    22267.88
    23291.36
    24317.29

(c)

To find: Draw the graph of the model

Given information:

Given that there were 41 breeding pairs over the next 24 years, the number of breeding pairs increased by about 8.9% each year.

Calculation:

Plot the point which are found in the table in part B .

The graph of the model will be:

  Holt Mcdougal Larson Algebra 2: Student Edition 2012, Chapter 4.1, Problem 42PS , additional homework tip  1

(c)

To find: Find from the graph How many breeding pair of bald eagle in 2001.

It can be observe from the graph that the number of breeding pair will be 350.

Given information:

Given that there were 41 breeding pairs over the next 24 years, the number of breeding pairs increased by about 8.9% each year

  Holt Mcdougal Larson Algebra 2: Student Edition 2012, Chapter 4.1, Problem 42PS , additional homework tip  2

Calculation:

Starting from 0=1 for 1977 for year 2001 t=24

It can be observe from the graph that the number of breeding pair will be 350.

Chapter 4 Solutions

Holt Mcdougal Larson Algebra 2: Student Edition 2012

Ch. 4.1 - Prob. 5ECh. 4.1 - Prob. 6ECh. 4.1 - Prob. 7ECh. 4.1 - Prob. 8ECh. 4.1 - Prob. 9ECh. 4.1 - Prob. 10ECh. 4.1 - Prob. 11ECh. 4.1 - Prob. 12ECh. 4.1 - Prob. 13ECh. 4.1 - Prob. 14ECh. 4.1 - Prob. 15ECh. 4.1 - Prob. 16ECh. 4.1 - Prob. 17ECh. 4.1 - Prob. 18ECh. 4.1 - Prob. 19ECh. 4.1 - Prob. 20ECh. 4.1 - Prob. 21ECh. 4.1 - Prob. 22ECh. 4.1 - Prob. 23ECh. 4.1 - Prob. 24ECh. 4.1 - Prob. 25ECh. 4.1 - Prob. 26ECh. 4.1 - Prob. 27ECh. 4.1 - Prob. 28ECh. 4.1 - Prob. 29ECh. 4.1 - Prob. 30ECh. 4.1 - Prob. 31ECh. 4.1 - Prob. 32ECh. 4.1 - Prob. 33ECh. 4.1 - Prob. 34ECh. 4.1 - Prob. 35PSCh. 4.1 - Prob. 36PSCh. 4.1 - Prob. 37PSCh. 4.1 - Prob. 38PSCh. 4.1 - Prob. 39PSCh. 4.1 - Prob. 40PSCh. 4.1 - Prob. 41PSCh. 4.1 - Prob. 42PSCh. 4.1 - Prob. 43PSCh. 4.1 - Prob. 44PSCh. 4.2 - Prob. 1GPCh. 4.2 - Prob. 2GPCh. 4.2 - Prob. 3GPCh. 4.2 - Prob. 4GPCh. 4.2 - Prob. 5GPCh. 4.2 - Prob. 6GPCh. 4.2 - Prob. 7GPCh. 4.2 - Prob. 8GPCh. 4.2 - Prob. 1ECh. 4.2 - Prob. 2ECh. 4.2 - Prob. 3ECh. 4.2 - Prob. 4ECh. 4.2 - Prob. 5ECh. 4.2 - 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Prob. 7MRPSCh. 4.5 - Prob. 1GPCh. 4.5 - Prob. 2GPCh. 4.5 - Prob. 3GPCh. 4.5 - Prob. 4GPCh. 4.5 - Prob. 5GPCh. 4.5 - Prob. 6GPCh. 4.5 - Prob. 7GPCh. 4.5 - Prob. 8GPCh. 4.5 - Prob. 9GPCh. 4.5 - Prob. 10GPCh. 4.5 - Prob. 11GPCh. 4.5 - Prob. 1ECh. 4.5 - Prob. 2ECh. 4.5 - Prob. 3ECh. 4.5 - Prob. 4ECh. 4.5 - Prob. 5ECh. 4.5 - Prob. 6ECh. 4.5 - Prob. 7ECh. 4.5 - Prob. 8ECh. 4.5 - Prob. 9ECh. 4.5 - Prob. 10ECh. 4.5 - Prob. 11ECh. 4.5 - Prob. 12ECh. 4.5 - Prob. 13ECh. 4.5 - Prob. 14ECh. 4.5 - Prob. 15ECh. 4.5 - Prob. 16ECh. 4.5 - Prob. 17ECh. 4.5 - Prob. 18ECh. 4.5 - Prob. 19ECh. 4.5 - Prob. 20ECh. 4.5 - Prob. 21ECh. 4.5 - Prob. 22ECh. 4.5 - Prob. 23ECh. 4.5 - Prob. 24ECh. 4.5 - Prob. 25ECh. 4.5 - Prob. 26ECh. 4.5 - Prob. 27ECh. 4.5 - Prob. 28ECh. 4.5 - Prob. 29ECh. 4.5 - Prob. 30ECh. 4.5 - Prob. 31ECh. 4.5 - Prob. 32ECh. 4.5 - Prob. 33ECh. 4.5 - Prob. 34ECh. 4.5 - Prob. 35ECh. 4.5 - Prob. 36ECh. 4.5 - Prob. 37ECh. 4.5 - Prob. 38ECh. 4.5 - Prob. 39ECh. 4.5 - Prob. 40ECh. 4.5 - Prob. 41ECh. 4.5 - Prob. 42ECh. 4.5 - Prob. 43ECh. 4.5 - Prob. 44ECh. 4.5 - Prob. 45ECh. 4.5 - Prob. 46ECh. 4.5 - Prob. 47ECh. 4.5 - Prob. 48ECh. 4.5 - Prob. 49ECh. 4.5 - Prob. 50ECh. 4.5 - Prob. 51ECh. 4.5 - Prob. 52ECh. 4.5 - Prob. 53ECh. 4.5 - Prob. 54ECh. 4.5 - Prob. 55ECh. 4.5 - Prob. 56ECh. 4.5 - Prob. 57ECh. 4.5 - Prob. 58ECh. 4.5 - Prob. 59ECh. 4.5 - Prob. 60ECh. 4.5 - Prob. 61ECh. 4.5 - Prob. 62ECh. 4.5 - Prob. 63ECh. 4.5 - Prob. 64ECh. 4.5 - Prob. 65ECh. 4.5 - Prob. 66ECh. 4.5 - Prob. 67ECh. 4.5 - Prob. 68ECh. 4.5 - Prob. 69PSCh. 4.5 - Prob. 70PSCh. 4.5 - Prob. 71PSCh. 4.5 - Prob. 72PSCh. 4.5 - Prob. 73PSCh. 4.5 - Prob. 74PSCh. 4.5 - Prob. 1QCh. 4.5 - Prob. 2QCh. 4.5 - Prob. 3QCh. 4.5 - Prob. 4QCh. 4.5 - Prob. 5QCh. 4.5 - Prob. 6QCh. 4.5 - Prob. 7QCh. 4.5 - Prob. 8QCh. 4.5 - Prob. 9QCh. 4.5 - Prob. 10QCh. 4.5 - Prob. 11QCh. 4.5 - Prob. 12QCh. 4.5 - Prob. 13QCh. 4.5 - Prob. 14QCh. 4.5 - Prob. 15QCh. 4.5 - Prob. 16QCh. 4.5 - Prob. 17QCh. 4.5 - Prob. 18QCh. 4.5 - Prob. 19QCh. 4.5 - Prob. 20QCh. 4.5 - Prob. 1PCh. 4.5 - Prob. 2PCh. 4.5 - Prob. 3PCh. 4.5 - Prob. 4PCh. 4.5 - Prob. 5PCh. 4.5 - Prob. 6PCh. 4.5 - Prob. 7PCh. 4.5 - Prob. 8PCh. 4.5 - Prob. 9PCh. 4.5 - Prob. 10PCh. 4.5 - Prob. 11PCh. 4.5 - Prob. 12PCh. 4.5 - Prob. 13PCh. 4.6 - Prob. 1GPCh. 4.6 - Prob. 2GPCh. 4.6 - Prob. 3GPCh. 4.6 - Prob. 4GPCh. 4.6 - Prob. 5GPCh. 4.6 - Prob. 6GPCh. 4.6 - Prob. 7GPCh. 4.6 - Prob. 8GPCh. 4.6 - Prob. 9GPCh. 4.6 - Prob. 10GPCh. 4.6 - Prob. 11GPCh. 4.6 - Prob. 1ECh. 4.6 - Prob. 2ECh. 4.6 - Prob. 3ECh. 4.6 - Prob. 4ECh. 4.6 - Prob. 5ECh. 4.6 - Prob. 6ECh. 4.6 - Prob. 7ECh. 4.6 - Prob. 8ECh. 4.6 - Prob. 9ECh. 4.6 - Prob. 10ECh. 4.6 - Prob. 11ECh. 4.6 - Prob. 12ECh. 4.6 - Prob. 13ECh. 4.6 - Prob. 14ECh. 4.6 - Prob. 15ECh. 4.6 - Prob. 16ECh. 4.6 - Prob. 17ECh. 4.6 - Prob. 18ECh. 4.6 - Prob. 19ECh. 4.6 - Prob. 20ECh. 4.6 - Prob. 21ECh. 4.6 - Prob. 22ECh. 4.6 - Prob. 23ECh. 4.6 - Prob. 24ECh. 4.6 - Prob. 25ECh. 4.6 - Prob. 26ECh. 4.6 - Prob. 27ECh. 4.6 - Prob. 28ECh. 4.6 - Prob. 29ECh. 4.6 - Prob. 30ECh. 4.6 - Prob. 31ECh. 4.6 - Prob. 32ECh. 4.6 - Prob. 33ECh. 4.6 - Prob. 34ECh. 4.6 - Prob. 35ECh. 4.6 - Prob. 36ECh. 4.6 - Prob. 37ECh. 4.6 - Prob. 38ECh. 4.6 - Prob. 39ECh. 4.6 - Prob. 40ECh. 4.6 - Prob. 41ECh. 4.6 - Prob. 42ECh. 4.6 - Prob. 43ECh. 4.6 - Prob. 44ECh. 4.6 - Prob. 45ECh. 4.6 - Prob. 46ECh. 4.6 - Prob. 47ECh. 4.6 - Prob. 48ECh. 4.6 - Prob. 49ECh. 4.6 - Prob. 50ECh. 4.6 - Prob. 51ECh. 4.6 - Prob. 52ECh. 4.6 - Prob. 53ECh. 4.6 - Prob. 54PSCh. 4.6 - Prob. 55PSCh. 4.6 - Prob. 56PSCh. 4.6 - Prob. 57PSCh. 4.6 - Prob. 58PSCh. 4.6 - Prob. 59PSCh. 4.6 - Prob. 60PSCh. 4.6 - Prob. 61PSCh. 4.6 - Prob. 1PCh. 4.6 - Prob. 2PCh. 4.6 - Prob. 3PCh. 4.6 - Prob. 4PCh. 4.6 - Prob. 5PCh. 4.6 - Prob. 6PCh. 4.6 - Prob. 7PCh. 4.6 - Prob. 8PCh. 4.6 - Prob. 9PCh. 4.6 - Prob. 10PCh. 4.6 - Prob. 11PCh. 4.6 - Prob. 12PCh. 4.6 - Prob. 13PCh. 4.6 - Prob. 1.1PCh. 4.6 - Prob. 1.2PCh. 4.6 - Prob. 1.3PCh. 4.6 - Prob. 1.4PCh. 4.6 - Prob. 1.5PCh. 4.6 - Prob. 1.6PCh. 4.6 - Prob. 1.7PCh. 4.6 - Prob. 1.8PCh. 4.6 - Prob. 1.9PCh. 4.6 - 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