To choose: For which equation is 4 a solution of given choices?
An option(choice) (C) is correct.
Given: 4
Calculation:
Let us consider given the value x=4 .
(A)Now, substitute x=4 in the equation e2⋅x+1=17 ;
e2⋅4+1=17e8+1=172980+1≠17[e≈2.718e8≈2980]2981≠17
Here, the equation does not satisfy at x=4 .
(B)Similarly substitute x=4 in the equation log2(x+2)=log22x ;
log2(x+2)=log22xlog2(4+2)≠log22⋅4log26≠log28
Here, the equation does not satisfy at x=4 .
(C) Again, substitute x=4 in the equation 3x−2+1=10 ;
34−2+1=1032+1=109+1=1010=10
Here, the equation satisfies at x=4
(D) Again similarly substitute x=4 in the equation ln(x+2)+lnx=1 ;
ln(x+2)+lnx=1ln(4+2)+ln4≠1ln(6)+ln(4)≠1ln(24)≠1
Thus,
3.178≠1
Here, the equation does not satisfy at x=4 .
Conclusion:
Hence, these three options are wrong at the value of x=4 . Because only the equation 3x−2+1=10 is satisfied at that x=4 and an option (C) is true.
Chapter 4 Solutions
Holt Mcdougal Larson Algebra 2: Student Edition 2012
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