Chapter 4, Problem 4.58QE

Interpretation Introduction

Interpretation:

The concentration of $\text{NaOH}$ in the second flask has to be calculated.

Concept introduction:

Molarity: Dividing moles of solute by the volume of solution in Liter.

  $\text{Molarity}\text{=}\frac{\text{Moles}\text{of}\text{solute}}{\text{Volume of solution in L}}$

Volumetric equation:

In the volumetric analysis the diluted solution is prepared using below formula,

$\begin{array}{l}{\text{V}}_{\text{1}}{\text{M}}_{\text{1}}\text{=}{\text{V}}_{\text{2}}{\text{M}}_{\text{2}}\\ \text{Where,}\\ {\text{V}}_{\text{1}}\text{-}\text{Initial}\text{volume}\\ {\text{M}}_{\text{1}}\text{-}\text{Initial}\text{molarity}\\ {\text{V}}_{\text{2}}\text{-}\text{Final}\text{volume}\\ {\text{M}}_{\text{2}}\text{-}\text{Final}\text{molarity}\end{array}$