Principles of Geotechnical Engineering (MindTap Course List)
9th Edition
ISBN: 9781305970939
Author: Braja M. Das, Khaled Sobhan
Publisher: Cengage Learning
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Chapter 4, Problem 4.12P
To determine
Find the shrinkage limit of the soil.
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Problem 3:
In a shrinkage limit test, a sample of saturated clay was dried in the oven. The dry mass of the soil was 22.5 g.
when the moisture content is at the shrinkage limit, the soil reaches a constant total volume, Vf= 10.3 cm³.
calculate the shrinkage limit of the soil. (Given: G,=2.72)
Following are the results of a shrinkage limit test:
Initial volume of soil in saturated state = 29.60 cc
Final volume of soil in a dry state = 19.90 cc
Initial mass in a saturated state = 50 g
Final mass in a dry state = 33 g
Determine the shrinkage limit of the soil.
A SOIL SAMPLE WAS TAKEN FROM A SITE AND WAS PLACED IN A CUBICAL
CONTAINER WITH ONE SIDE EQUAL TO 0.1m. THE NET WEIGHT OF THE SOIL IS
FOUND OUT TO BE 2kN. AFTER OVEN DRYING, THE WEIGHT WAS REDUCED TO
53%. WHAT IS THE UNIT WEIGHT OF THE SOIL AFTER DRYING? *
Your answer
A SATURATED SOIL HAS VOID RATIO EQUAL TO 0.65 AND sg = 2.9. WHAT IS THE
SUBMERGED UNIT WEIGHT OF THE SOIL? *
Your answer
THE WEIGHT OF THE VOIDS OF ON SITE SOIL WAS MEASURED AND FOUND OUT
TO BE 1 kN. AFTER DRYING, THE WEIGHT OF THE SOLID WAS FOUND TO BE 1 kN.
IF THE VOLUME OF THE SOIL IS 0.099 m3, WHAT IS THE NATURAL UNIT WEIGHT
OF THE SOIL? *
Your answer
Chapter 4 Solutions
Principles of Geotechnical Engineering (MindTap Course List)
Ch. 4 - During Atterberg limit tests in the soil mechanics...Ch. 4 - Prob. 4.2PCh. 4 - Prob. 4.3PCh. 4 - Results from a liquid limit test conducted on a...Ch. 4 - The following data were obtained by conducting...Ch. 4 - Refer to the soil in Problem 4.5. Using the...Ch. 4 - Following results are obtained for a liquid limit...Ch. 4 - Prob. 4.8PCh. 4 - Prob. 4.9PCh. 4 - Prob. 4.10P
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.Similar questions
- The following data were obtained from laboratory tests for a cohesive soil: moisture content = 22.5%, specific gravity = 2.60. To determine the approximate unit weight, a sample having a mass of 224 g was placed in a 500 cm container with 382 cm of water required to fill the container. What is the void ratio? Select one: a. 0.68 b. 0.89 c. 0.57 d. 0.70arrow_forwardPROBLEM No. 5 Shrinkage Limit Following are the results of a shrinkage limit test: = 26 cm3 19 cm3 Initial volume of soil in saturated state = Final volume of soil in a dry state 46 g Initial mass in a saturated state = Final mass in a dry state = 32 g Determine the shrinkage limit of the soil Determine the shrinkage ratio Determine the specific gravity of the solids d. If the soil at natural state has a moisture content of 25%, estimate the maximum volumetric shrinkage. Estimate the linear shrinkage. а. b. С. е.arrow_forwardA saturated 100 cm^3 clay sample has a natural water content of 30%. It is found that the shrinkage limit occurs when the water content is 19%. The specific gravity of the soil is 2.70. a. What is the initial mass of the soil in grams? b. What is the dry mass of the soil in grams? c. What is the final volume of the soil in cm^3 after drying? d. What is the volume of the sample in cm^3 when the water content is 15%?arrow_forward
- Example 2.21:The liquid limit and plastic limit of a soil are 50 % and 25 %, respectively When the soil was dried from its state at liquid limit, the decrease in volume was 40 pe cent of the volume at liquid limit. When it was dried from its state at plastic limit, the volume decrease was 20 per cent of the volume at plastic limit. Determine the shrinkag limit and shrinkage ratio.arrow_forwardPROBLEM No. 5 Following are the results of a shrinkage limit test: 26.4 cm3 Final volume of soil in a dry state = 19.5 cm³ 45.6 g Initial volume of soil in saturated state = Initial mass in a saturated state = Final mass in a dry state 31.5 g Determine the shrinkage limit of the soil Describe the quality of the soil based on the shrinkage а. b. limit. Determine the shrinkage ratio d. Determine the specific gravity of the solids If the soil at natural state has a moisture content of 30%, estimate the maximum volumetric shrinkage. Estimate the linear shrinkage. С. е. f.arrow_forward100 cm3 saturated sample of quartz sand is weighed, gravity drained, weighed, oven dried, and weighed again. The saturated, gravity-drained, and oven-dried weights are 130g, 110 g, and 105 g, respectively. Given that the soil sample above has porosity of 35%. i. Determine the void ratio of this soil. ii. If 50% of the void space is filled with water, with the remaining 50% filled with air, determine the volumetric water content, θ. iii. and the degree of saturation, S.arrow_forward
- The consistency limits of a given soil are LL=60%, PL= 45 % and SL= 25% . The specific gravity of the soil solids is 2.67. A sample of this soil at liquid has a volume of 20 cc. What will be its final volume in cm3 if the sample is brought to its shrinkage limit? a.2.67 b.7.18 c.12.82 d.1.602arrow_forwardSituation 3 - Following are the results of a shrinkage limit test: Initial volume of soil in saturated state 25.7 cm3 Final volume of soil in dry state 19.6 cm3 Initial mass in saturated state 47.0 g Final mass in dry state 33.0 g Determine the shrinkage ratio of the soil. Round off to two decimal places.arrow_forwardA Cylindrical soil sample of 7.5 cm height and 3.75 cm diameter has been prepared at the shrinkage limit. If the sample is now allowed to absorb water so that its water content reaches the liquid limit, what will be its volume? Given LL=62%, PL=34%, SL=21%, and Gs=2.68.arrow_forward
- A Cylindrical soil sample of 7.5 cm height and 3.75 cm diameter has been prepared at the shrinkage limit. If the sample is now allowed to absorb water so that its water content reaches the liquid limit, what will be its volume? Given LL = 62%, PL= 34%, SL = 21%, and ?s = 2.68.arrow_forward. A shrinkage limit test on a clay soil gave the following data. Compute the shrinkage limit. Assuming that the total volume of dry soil cake is equal to its total volume at the shrinkage limit, what is the degree of shrinkage? Comment on the nature of soil. Mass of shrinkage dish and saturated soil M1 = 38.78 g Mass of shrinkage dish and oven dry soil M2 = 30.46 g Mass of shrinkage dish M3 = 10.65 g Volume of shrinkage dish Vo = 16.29 cm3 Total volume of oven dry soil cake Vd = 10.00 cm3arrow_forwardInitial volume of soil in a saturated state = 24.6 cm³ Final volume of soil in a dry state = 15.9 cm³ Initial mass in a saturated state = 44.0 g Final mass in a dry state = 30.1 g Calculate the moisture content of the sample. Determine the shrinkage limit of the soil.arrow_forward
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