Chapter 4, Problem 16CLR

To determine

To find: The value of the expression $w\left(3y+x\right)$ .

Answer to Problem 16CLR

The value of the expression $w\left(3y+x\right)$ is $-2$ .

Explanation of Solution

Given:

The value of $w=\frac{1}{5}$ , $x=-1$ , $y=-3$ and $z=2$ .

Calculation:

Substitute $w=\frac{1}{5}$ , $x=-1$ , $y=-3$ and $z=2$ in the expression $w\left(3y+x\right)$ as follows:

  $\begin{array}{c}\frac{1}{5}\left(3\times \left(-3\right)+\left(-1\right)\right)=\frac{1}{5}\left(-9-1\right)\\ =\frac{1}{5}\left(-10\right)\\ =-2\end{array}$

Thus, the value of the expression $w\left(3y+x\right)$ is $-2$ .