Concept explainers
In a compound microscope, the focal lengths of the objective and eyepiece are +0.50 cm and +2.0 cm, respectively. The instrument is focused on an object 0.52 cm from the objective lens. Compute the magnifying power of the microscope if the virtual image is viewed by the eye at a distance of 25 cm.
The magnifying power of the compound microscope, if the focal lengths of the objective and eye piece are
Answer to Problem 27SP
Solution:
Explanation of Solution
Given data:
The focal lengths of the objective and eye piece are
The instrument is focused on an object
The virtual image is viewed by the eye at a distance of
Formula used:
Write the expression of focal length of objective.
Here,
Write the expression of magnification of compound microscope.
Here,
Explanation:
Recall the expression of focal length of objective.
Substitute
Solve for
Recall the expression of focal length of eyepiece.
Substitute
Solve for
The expression of magnification of compound microscope.
The magnification of compound microscope is,
Conclusion:
Hence, the magnifying power of the microscope is
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Chapter 39 Solutions
Schaum's Outline of College Physics, Twelfth Edition (Schaum's Outlines)
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