Schaum's Outline of College Physics, Twelfth Edition (Schaum's Outlines)
12th Edition
ISBN: 9781259587399
Author: Eugene Hecht
Publisher: McGraw-Hill Education
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Chapter 39, Problem 17SP
To determine
The prescription of the eyeglass needed by the nearsighted person, if he cannot see anything beyond
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length of -6.0 [cm]. Find (a) the image distance and (b) the magnification.
An object is placed 16 [cm] in front of a diverging lens with a focal
An object is placed 17 cm in front of a converging lens with focal length 10 cm. A second lens, with focal length -20 cm is behind the first lens by a distance x = 13 cm. What is the final magnification of the image when viewed through both lenses? Be sure to include a minus sign if it is appropriate, and express your answer with at least two decimal places.
A converging lens with a focal length of 40 cm and a
diverging lens with a focal length of -40 cm are
150 cm apart. A 3.0-cm-tall object is 60 cm in front of
the converging lens.
Calculate the image height.
Express your answer in centimeters to two significant figures.
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Chapter 39 Solutions
Schaum's Outline of College Physics, Twelfth Edition (Schaum's Outlines)
Ch. 39 - 39.14 [I] Two thin lenses having focal lengths of...Ch. 39 - 39.15 [I] A farsighted person who needs glasses...Ch. 39 - 39.16 [I] A farsighted person who needs glasses...Ch. 39 - Prob. 17SPCh. 39 - 39.18 [I] A farsighted person wears eyeglasses...Ch. 39 - Prob. 19SPCh. 39 - Prob. 20SPCh. 39 - 39.21 [II] A nearsighted man cannot see objects...Ch. 39 - 39.22 [II] A projection lens is employed to...Ch. 39 - 39.23 [II] A camera gives a life-size picture of a...
Ch. 39 - 39.24 [II] What is the maximum stop rating of a...Ch. 39 - Prob. 25SPCh. 39 - Prob. 26SPCh. 39 - 39.27 [II] In a compound microscope, the focal...Ch. 39 - 39.28 [II] A refracting astronomical telescope has...Ch. 39 - 39.29 [III] The large telescope at Mt. Palomar has...Ch. 39 - 39.30 [II] An astronomical telescope with an...Ch. 39 - 39.31 [II] A lens combination consists of two...Ch. 39 - 39.32 [II] Two lenses, of focal lengths +6.0 cm...Ch. 39 - 39.33 [II] A telephoto lens consists of a positive...Ch. 39 - 39.34 [II] An opera glass has an objective lens of...Ch. 39 - Prob. 35SPCh. 39 - Prob. 36SP
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- Two thin lenses of focal lengths f1 = 15.0 and f2 = 10.0 cm, respectively, are separated by 35.0 cm along a common axis. The f1 lens is located to the left of the f2 lens. An object is now placed 50.0 cm to the left of the f1 lens, and a final image due to light passing though both lenses forms. By what factor is the final image different in size from the object? (a) 0.600 (b) 1.20 (c) 2.40 (d) 3.60 (e) none of those answersarrow_forwardHow far should you hold a 2.1 cm-focal length magnifying glass from an object to obtain a magnification of 10 x ? Assume you place your eye 5.0 cm from the magnifying glass.arrow_forwardWhat is the angular size of the Moon if viewed from a binocular that has a focal length of 1.2 cm for the eyepiece and a focal length of 8 cm for the objective? Use the radius of the moon 1.74106 m and the distance of the moon from the observer to be 3.8108m .arrow_forward
- Unless otherwise stated, the lens-to-retina distance is 2.00 cm. People who do very detailed work close up, such as jewellers, often can see objects clearly at much closer distance than the normal 25 cm. What is the size of an image of a 1.00 mm object, such as lettering inside a ring, held at this distance?arrow_forwardA certain telescope has an objective of focal length 1 500 cm. If the Moon is used as an object, a 1.0-cm-long image formed by the objective corresponds to what distance, in miles, on the Moon? Assume 3.8 x 10 8 m for the Earth–Moon distance.arrow_forwardThis means (-0.333 = M6) if the magnification is for his lens The The image is upside down and one third the size of the original object. O The The image is moderate and its size is one third the size of the original body. The The image is inverted and three times the size of the original object. 0₁ The image is moderate and its size is three times the size of the original body.arrow_forward
- A diverging lens has a focal length of -22.9 cm. The image formed has a magnification of 55. What is the object distance? Express this numeric value in cm. (note) when I get to the very end at -12.595 = -q + 0.55 I get stuck.arrow_forwardif its mmage on the fim is to be in focus. What is the magnification? (b) An extension tube is added between the lens and the camera body so that the lens can be positioned 100 mm from film. How close can the object be now? What is the magnification? 5. The focal length of a diverging lens is negative. If ƒ= −20 cm for a particular diverging lens, where will the image be formed of an object located 50 cm to the left of the lens on the optical axis? What is the magnification of the image? 6. The equation connecting s, p, and ffor a simple lens can be employed for spherical mirrors, too. A concave mirror with a focal length of 8 cm forms an image of a small object placed 10 cm in front of the mirror. Where will this image be located? 17. If the mirror described in the previous problem is used to form an image of the same object now located 16 cm in front of the mirror, what would the new image position be? Assuming that the magnification equations developed forarrow_forwardA 40 cm tall trolley is placed at u cm from a mirror. The image formed by the mirror is an upright image with the height of its image is 80 cm.arrow_forward
- A thick lens has the following properties: Radius of the front surface: R₁ = 5.0 cm Radius of the back surface: R₂ = -5.0 cm Thickness: d = 0.5 cm Index of refraction: n = 1.52 Consider the effective focal length of this lens (feff). What would the percentage error for the focal length be (relative to feff) if you were to assume that this were a thin lens? Select one: O 1.7 2.5 0 O O O O 3.6arrow_forwardThe image of the Moon is formed by a concave mirror (aka telescope) whose radius of curvature is 9.62m at a time when the Moon's angular diameter is 0.523degrees. What is the diameter (magnitude only) of the image (cm) of the moon? HINT: What is the property of the rays coming from one point on the edge of the Moon (think of the moon as being infinitely far away)? Where do those rays converge to form an image of that point? Use the small angle approximation: sin(x)=tan(x)=x for |x|<<1, when x is measured in radians.arrow_forwardAn object of height 5.19cm is placed 45.4 cm from a converging lens of focal length 13.1 cm. How big is the image? (hint: you should find the image distance first) To continue, enter your answer in cm. Round your answer to 1 decimal place.arrow_forward
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