Fundamentals of Physics Extended
10th Edition
ISBN: 9781118230725
Author: David Halliday, Robert Resnick, Jearl Walker
Publisher: Wiley, John & Sons, Incorporated
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Chapter 38, Problem 61P
To determine
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Eq.38-27 is a solution of Schrödinger’s equation, with
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Find the angular momentum and kinetic energy in the z axis for the
(cos(30))*e(iΦ)+(sin(30))*e(-iΦ) wave function.
*24 Figure 39-30 shows a two-dimen-
sional, infinite-potential well lying in an
xy plane that contains an electron. We
probe for the electron along a line that
bisects L, and find three points at which
the detection probability is maximum. Figure 39-30 Problem 24.
Those points are separated by 2.00 nm.
Then we probe along a line that bisects L, and find five points at
which the detection probability is maximum. Those points are sep-
arated by 3.00 nm. What is the energy of the electron?
22 A particle is confined to the one-dimensional infinite poten-
tial well of Fig. 39-2. If the particle is in its ground state, what
is its probability of detection between (a) x = 0 and x = 0.30L.
(b) x = 0.70L and x = L, and (c) x = 0.30L and x = 0.70L?
U(x)
Fig 39-2
Chapter 38 Solutions
Fundamentals of Physics Extended
Ch. 38 - Prob. 1QCh. 38 - Prob. 2QCh. 38 - Prob. 3QCh. 38 - Prob. 4QCh. 38 - Prob. 5QCh. 38 - Prob. 6QCh. 38 - Prob. 7QCh. 38 - Prob. 8QCh. 38 - Prob. 9QCh. 38 - Prob. 10Q
Ch. 38 - Prob. 11QCh. 38 - Prob. 12QCh. 38 - Prob. 13QCh. 38 - Prob. 14QCh. 38 - Prob. 15QCh. 38 - Prob. 16QCh. 38 - Prob. 1PCh. 38 - Prob. 2PCh. 38 - Prob. 3PCh. 38 - Prob. 4PCh. 38 - Prob. 5PCh. 38 - Prob. 6PCh. 38 - Prob. 7PCh. 38 - Prob. 8PCh. 38 - Prob. 9PCh. 38 - Prob. 10PCh. 38 - Prob. 11PCh. 38 - Prob. 12PCh. 38 - Prob. 13PCh. 38 - Prob. 14PCh. 38 - Prob. 15PCh. 38 - Prob. 16PCh. 38 - Prob. 17PCh. 38 - Prob. 18PCh. 38 - Prob. 19PCh. 38 - Prob. 20PCh. 38 - Prob. 21PCh. 38 - Prob. 22PCh. 38 - Prob. 23PCh. 38 - Prob. 24PCh. 38 - Prob. 25PCh. 38 - Prob. 26PCh. 38 - Prob. 27PCh. 38 - Prob. 28PCh. 38 - Prob. 29PCh. 38 - Prob. 30PCh. 38 - Prob. 31PCh. 38 - Prob. 32PCh. 38 - Prob. 33PCh. 38 - Prob. 34PCh. 38 - Prob. 35PCh. 38 - Prob. 36PCh. 38 - Prob. 37PCh. 38 - Prob. 38PCh. 38 - Prob. 39PCh. 38 - Prob. 40PCh. 38 - Prob. 41PCh. 38 - Prob. 42PCh. 38 - Prob. 43PCh. 38 - Prob. 44PCh. 38 - Prob. 45PCh. 38 - Prob. 46PCh. 38 - Prob. 47PCh. 38 - Prob. 48PCh. 38 - Prob. 49PCh. 38 - Prob. 50PCh. 38 - Prob. 51PCh. 38 - Prob. 52PCh. 38 - Prob. 53PCh. 38 - Prob. 54PCh. 38 - Prob. 55PCh. 38 - Prob. 56PCh. 38 - Prob. 57PCh. 38 - Prob. 58PCh. 38 - Prob. 59PCh. 38 - Prob. 60PCh. 38 - Prob. 61PCh. 38 - Prob. 62PCh. 38 - Prob. 63PCh. 38 - Prob. 64PCh. 38 - Prob. 65PCh. 38 - Prob. 66PCh. 38 - Prob. 67PCh. 38 - Prob. 68PCh. 38 - Prob. 69PCh. 38 - Prob. 70PCh. 38 - Prob. 71PCh. 38 - Prob. 72PCh. 38 - Prob. 73PCh. 38 - Prob. 74PCh. 38 - Prob. 75PCh. 38 - Prob. 76PCh. 38 - Prob. 77PCh. 38 - Prob. 78PCh. 38 - Prob. 79PCh. 38 - Prob. 80PCh. 38 - Prob. 81PCh. 38 - Prob. 82PCh. 38 - Prob. 83PCh. 38 - Prob. 84PCh. 38 - Prob. 85PCh. 38 - Prob. 86PCh. 38 - Prob. 87PCh. 38 - Prob. 88PCh. 38 - Prob. 89PCh. 38 - Prob. 90P
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- 16 For three experiments, Fig. 38-25 gives the transmission coefficient T for electron tunneling through a po- tential barrier, plotted versus barrier thickness L. The de Broglie wave- lengths of the electrons are identical in the three experiments. The only difference in the physical setups is the barrier heights U. Rank the three experiments according to U, greatest first. T: Figure 38-25 Question 16.arrow_forwardSolving the Schrödinger equation for a particle of energy E 0 Calculate the values of the constants D, C, B, and A if knownCalculate the values of the constants D, C, B, and A if known and 2mE 2m(Vo-E) a =arrow_forwardAn electron with initial kinetic energy 5.0 eV encounters a barrier with height U0 and width 0.60 nm. What is the transmission coefficient if (a) U0 = 7.0 eV; (b) U0 = 9.0 eV; (c) U0 = 13.0 eV?arrow_forward
- Harmonic oscillator eigenstates have the general form 1 μω ,1/4 μω AG)(√(-) n ħ In this formula, which part determines the number of nodes in the harmonic oscillator state? = y (x) 1 √(™ ћn 2"n! Holev 1/4 μω 1 2"n! exp(-1022²) 2ħ μω ħ 2"n! exp μω χ 2ħ 2arrow_forwardA thin solid barrier in the xy-plane has a 12.6µm diameter circular hole. An electron traveling in the z-direction with vx 0.00m/s passes through the hole. Afterward, within what range is vx likely to be?arrow_forwardA student in a physics laboratory observes a hydrogen spectrum with a diffraction grating for the purpose of measuring the wavelengths of the emitted radiation, hr the spectrum, she observes a yellow line and finds its wavelength to be 589 nm. (a) Assuming that this is part of the Balmer series, determine the principal quantum number of the initial state, (b) What is unreasonable about this result? (c) Which assumptions are unreasonable 01 inconsistent?arrow_forward
- For a particle in one dimension in a region of constant potential energy Vo, the angular frequency w and the wave number k of its associated wave function are related by h²k? ħw = + Vo 2m а) - Verify that, if a monochromatic wave of the form ý = ei(kz-wt) is substituted into the Schrödinger time dependent equation, the above relation is reproduced. b) - c) In which region(s) of space are you most likely to find this particle? Why do we demand that the wavefunction be identically zero outside of the "box" in the particle in a box model?arrow_forwardС 320 3.6 Consider the solution to the Schrödinger equation for the infinite square well with n 1 in Equation (3.20). 4xx =A, sin 12. a = 2 rather than n = rive V(x,t) for this case, and normalize this wave function.arrow_forwardConsider a potential energy barrier like that of Fig. 39-13a but whose height Enot is 5.9 eV and whose thickness L is 0.84 nm. What is the energy of an incident electron whose transmission probability is 0.0040? eV pot E Electron T (a) (8) Figure 39-13. Probability density 4 ( En ergyarrow_forward
- A particle with mass m is moving in three-dimensions under the potential energy U(r), where r is the radial distance from the origin. The state of the particle is given by the time-independent wavefunction, Y(r) = Ce-kr. Because it is in three dimensions, it is the solution of the following time-independent Schrodinger equation dıp r2 + U(r)µ(r). dr h2 d EÞ(r) = 2mr2 dr In addition, 00 1 = | 4ar?y? (r)dr, (A(r)) = | 4r²p²(r)A(r)dr. a. Using the fact that the particle has to be somewhere in space, determine C. Express your answer in terms of k. b. Remembering that E is a constant, and the fact that p(r) must satisfy the time-independent wave equation, what is the energy E of the particle and the potential energy U(r). (As usual, E and U(r) will be determined up to a constant.) Express your answer in terms of m, k, and ħ.arrow_forwardShow that the wave function ψ = Ae i(i-ωt) is a solution to the Schrödinger equation (as shown), where k = 2π/λ and U = 0.arrow_forward.8 O An electron is trapped in a one-dimensional infinite well and is in its first excited state. Figure 39-27 indicates the five longest wavelengths of light that the electron could absorb in transitions from this initial state via a single photon absorption: A, = 80.78 nm, A, = 33.66 nm, A = 19.23 nm, A, = 12.62 nm, and A, = 8.98 nm. What is the width of the potential well? %3D %3! 2 (nm) Figure 39-27 Problem 8.arrow_forward
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