The expression for sine of the angles at which minimum intensity occurs in single slit.

Question

Want to see the full answer?

Answer 1

Question

Chapter 37, Problem 2P

To determine

The expression for sine of the angles at which minimum intensity occurs in single slit.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Evaluate the formula xm= (L m 2) / D for single slit diffraction experiment.

In young's double slit experiment, the fringe width obtained by using monochromatic light of wavelength 6000 Å is 2 mm. If the whole apparatus is immersed in water of R. I. 1.33, then the change in fringe width will be

How much diffraction spreading does a light beam undergo? One quantitative answer is the full width at half maximum of the central maximum of the single-slit Fraunhofer diffraction pattern. You can evaluate this angle of spreading in this problem. (a) as shown, define φ = πa sin φ/λ and show that at the point where I = 0.5Imax we must have φ = √2 sin φ. (b) Let y1 = sin φ and y2 = φ = /√2. Plot y1 and y2 on the same set of axes over a range from φ = 1 rad to φ = π/2 rad. Determine φ from the point of intersection of the two curves. (c) Then show that if the fraction λ/a is notlarge, the angular full width at half maximum of the central diffraction maximum is θ = 0.885λ/a. (d) What If? Another method to solve the transcendental equation φ = √2 sin φ in part (a) is to guess a first value of φ, use a computer or calculator to see how nearly it fits, and continue to update your estimate until the equation balances. How many steps(iterations) does this process take?