Physics for Scientists and Engineers with Modern Physics
10th Edition
ISBN: 9781337553292
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
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Chapter 36.5, Problem 36.3QQ
One microscope slide is placed on top of another with their left edges in contact and a human hair under the right edge of the upper slide. As a result, a wedge of air exists between the slides. An interference pattern results when monochromatic light is incident on the wedge. What is at the left edges of the slides? (a) a dark fringe (b) a bright fringe (c) impossible to determine
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Chapter 36 Solutions
Physics for Scientists and Engineers with Modern Physics
Ch. 36.2 - Which of the following causes the fringes in a...Ch. 36.3 - Using Figure 36.6 as a model, sketch the...Ch. 36.5 - One microscope slide is placed on top of another...Ch. 36 - Two slits are separated by 0.320 mm. A beam of...Ch. 36 - Prob. 2PCh. 36 - A laser beam is incident on two slits with a...Ch. 36 - Prob. 4PCh. 36 - Prob. 5PCh. 36 - Light with wavelength 442 nm passes through a...Ch. 36 - Prob. 7P
Ch. 36 - A student holds a laser that emits light of...Ch. 36 - Coherent light rays of wavelength strike a pair...Ch. 36 - In Figure P36.10 (not to scale), let L = 1.20 m...Ch. 36 - Prob. 11PCh. 36 - Prob. 12PCh. 36 - In the double-slit arrangement of Figure P36.13, d...Ch. 36 - Monochromatic light of wavelength is incident on...Ch. 36 - Prob. 15PCh. 36 - Show that the distribution of intensity in a...Ch. 36 - Prob. 17PCh. 36 - Monochromatic coherent light of amplitude E0 and...Ch. 36 - Prob. 19PCh. 36 - Prob. 20PCh. 36 - Prob. 21PCh. 36 - Prob. 22PCh. 36 - When a liquid is introduced into the air space...Ch. 36 - Prob. 24PCh. 36 - Prob. 25PCh. 36 - Prob. 26PCh. 36 - Prob. 27PCh. 36 - Prob. 28APCh. 36 - Prob. 29APCh. 36 - Prob. 30APCh. 36 - Prob. 31APCh. 36 - Prob. 32APCh. 36 - In a Youngs double-slit experiment using light of...Ch. 36 - Prob. 34APCh. 36 - Figure P36.35 shows a radio-wave transmitter and a...Ch. 36 - Prob. 36APCh. 36 - In a Newtons-rings experiment, a plano-convex...Ch. 36 - Prob. 38APCh. 36 - A plano-concave lens having index of refraction...Ch. 36 - Prob. 40APCh. 36 - Interference fringes are produced using Lloyds...Ch. 36 - A plano-convex lens has index of refraction n. The...Ch. 36 - Prob. 43APCh. 36 - Prob. 44APCh. 36 - Prob. 45APCh. 36 - Prob. 46CPCh. 36 - Prob. 47CPCh. 36 - Prob. 48CPCh. 36 - Prob. 49CPCh. 36 - Prob. 50CP
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- A Fraunhofer diffraction pattern is produced on a screen located 1.00 m from a single slit. If a light source of wavelength 5.00 107 m is used and the distance from the center of the central bright fringe to the first dark fringe is 5.00 103 m, what is the slit width? (a) 0.010 0 mm (b) 0.100 mm (c) 0.200 mm (d) 1.00 mm (e) 0.005 00 mmarrow_forwardInterference fringes are produced using Lloyds mirror and a source S of wavelength = 606 nm as shown in Figure P36.41. Fringes separated by y = 1.20 mm are formed on a screen a distance L = 2.00 m from the source. Find the vertical distance h of the source above the reflecting surface. Figure P36.41arrow_forwardBoth sides of a uniform film that has index of refraction n and thickness d are in contact with air. For normal incidence of light, an intensity minimum is observed in the reflected light at λ2 and an intensity maximum is observed at λ1, where λ1 > λ2. (a) Assuming no intensity minima are observed between λ1 and λ2, find an expression for the integer m in Equations 27.13 and 27.14 in terms of the wavelengths λ1 and λ2. (b) Assuming n = 1.40, λ1 = 500 nm, and λ2 = 370 nm, determine the best estimate for the thickness of the film.arrow_forward
- In Figure P36.10 (not to scale), let L = 1.20 m and d = 0.120 mm and assume the slit system is illuminated with monochromatic 500-nm light. Calculate the phase difference between the two wave fronts arriving at P when (a) = 0.500 and (b) y = 5.00 mm. (c) What is the value of for which the phase difference is 0.333 rad? (d) What is the value of for which the path difference is /4? Figure P36.10arrow_forwardA monochromatic light of unknown wavelength is incident on a slit of width 20 m. A diffraction pattern is seen at a screen 2.5 m away where the central maximum is spread over a distance of 10.0 cm. Find the wavelength.arrow_forwardThe condition for constructive interference by reflection from a thin film in air as developed in Section 36.5 assumes nearly normal incidence. What If? Suppose the light is incident on the film at a nonzero angle 1 (relative to the normal). The index of refraction of the film is n, and the film is surrounded by vacuum. Find the condition for constructive interference that relates the thickness t of the film, the index of refraction n of the film, the wavelength of the light, and the angle of incidence 1.arrow_forward
- Into one arm of a Michelson interferometer, a plastic sheet of thickness 75 m is inserted, which causes a shift in the interference pattern by 86 fringes. The light source has wavelength of 610 nm in air. What is the index of refraction of this plastic?arrow_forwardAn effect analogous to two-slit interference can occur with sound waves, instead of light. In an open field, two speakers placed 1.30 m apart are powered by a single-function generator producing sine waves at 1200-Hz frequency. A student walks along a line 12.5 m away and parallel to the line between the speakers. She hears an alternating pattern of loud and quiet, due to constructive and destructive interference. What is (a) the wavelength of this sound and (b) the distance between the central maximum and the first maximum (loud) position along this line?arrow_forwardShow that the distribution of intensity in a double-slit pattern is given by Equation 36.9. Begin by assuming that the total magnitude of the electric field at point P on the screen in Figure 36.4 is the superposition of two waves, with electric field magnitudes E1=E0sintE2=E0sin(t+) The phase angle in in E2 is due to the extra path length traveled by the lower beam in Figure 36.4. Recall from Equation 33.27 that the intensity of light is proportional to the square of the amplitude of the electric field. In addition, the apparent intensity of the pattern is the time-averaged intensity of the electromagnetic wave. You will need to evaluate the integral of the square of the sine function over one period. Refer to Figure 32.5 for an easy way to perform this evaluation. You will also need the trigonometric identity sinA+sinB=2sin(A+B2)cos(AB2)arrow_forward
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