Concept explainers
To determine: Whether water will flow by osmosis from one plant cell with water potential of -1.5MPa to another plant cell with water potential of -1.8MPa.
Introduction: Water is the most crucial factor for a plant to perform its normal cellular functions. The water is absorbed by the roots. The movement of water from the roots to the leaves can be explained using cohesion tension theory of water transport. The water movement from the roots to the vascular tube (xylem) is facilitated by osmosis. Water potential plays an important role in understanding plant physiology because it helps to measure a cell’s ability to absorb water by osmosis.
To determine: The direction of water flow when a plant cell with a water potential water potential of -1.5MPa to another plant cell with water potential of -1.8MPa.
Introduction: Water is the most crucial factor for a plant to perform its normal cellular functions. The water is absorbed by the roots. The movement of water from the roots to the leaves can be explained using cohesion tension theory of water transport. The water movement from the roots to the vascular tube (xylem) is facilitated by osmosis. Water potential plays an important role in understanding plant physiology because it helps to measure a cell’s ability to absorb water by osmosis.
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Biology (MindTap Course List)
- You place a flaccid plant cell (Ψ = -0.7 MPa) into an environment (beaker) of sucrose solution (Ψ = -0.9 MPa). Compare the initial conditions of the flaccid cell and the environment (beaker of sucrose solution) in terms of: D) Water potential (high or low) of the cell E) Solute concentration (high or low) of the cell F) Tonicity (hypertonic, hypotonic, or isotonic) of the cell G) Predict the direction of water movement (into the cell, out of the cell, or no net movement)arrow_forwardYou place a flaccid plant cell (Ψ = -0.7 MPa) into an environment (beaker) of pure (deionized) water (Ψ = 0 MPa). Compare the initial conditions of the flaccid cell and the environment (beaker of pure water) in terms of: G) Predict the direction of water movement (into the cell, out of the cell, or no net movement) H) Predict the change in turgor pressor of the cell (increase turgor pressure or decrease turgor pressure) I) Predict the fate of the cell (plasmolyzed, turgid, or lysed)arrow_forwardYou place a flaccid plant cell (Ψ = -0.7 MPa) into an environment (beaker) of pure (deionized) water (Ψ = 0 MPa). Compare the initial conditions of the flaccid cell and the environment (beaker of pure water) in terms of: A) Water potential (high or low) of the environment B) Solute concentration (high or low) of the environment C) Tonicity (hypertonic, hypotonic, or isotonic) of the environment D) Water potential (high or low) of the cell E) Solute concentration (high or low) of the cell F) Tonicity (hypertonic, hypotonic, or isotonic) of the cell G) Predict the direction of water movement (into the cell, out of the cell, or no net movement) H) Predict the change in turgor pressor of the cell (increase turgor pressure or decrease turgor pressure) I) Predict the fate of the cell (plasmolyzed, turgid, or lysed)arrow_forward
- You place a flaccid plant cell (Ψ = -0.7 MPa) into an environment (beaker) of pure (deionized) water (Ψ = 0 MPa). Compare the initial conditions of the flaccid cell and the environment (beaker of pure water) in terms of: D) Water potential (high or low) of the cell E) Solute concentration (high or low) of the cell F) Tonicity (hypertonic, hypotonic, or isotonic) of the cellarrow_forwardThe water potential of three adjacent plant cells are as follows: X 0kPa Y -1000kPa Z -4000kPa In which direction will water move?arrow_forwardThe osmotic potential of the plant cell is -0.1 MPa and it is placed in an 9 mM sorbitol solution (21 °C). Calculate the turgor pressure of the cell when the water potential of the cell has equilibrated to the same as that of the solution.arrow_forward
- If you place a flaccid plant cell with ΨS = -0.4 MPa in pure water, which of the following will occur? A. Water will not enter the cell because the flaccid cell has solutes and low water potential. B. Water enters the cell because the flaccid cell has solutes and low water potential. C. Water enters the cell because the flaccid cell has solutes and high water potential. D. Water will not enter the cell because the flaccid cell has solutes and high water potential.arrow_forwardA of Y, = 0.2 Y, = -0.7 Y, = 0.8 Y, = -0.9 || Based on this diagram of two plant cells, what direction do you expect water to move? (Calculate the water potentials for each cell to determine the direction) Select one: O a. A to B O b. B to A O c. No movement O d. You cannot tell based on this information 口arrow_forwardSAMSUNG SCBIO124-Biology1-A X + qo2tZnoiFPc7w0Gpr1VyRRMpNInM/view QUESTION 1 Water potential is the pressure exerted by freely moving water molecules in a system. Describe the relationship between water potential with solute potential and pressure potential in plants. Plant cell P has a solute potential of-350 kPa and a pressure potential of 200 kPa. Besides, is plant cell Q which has a solute potential of -500 kPa and a pressure potential of 200 kPa. Determine the direction of net movement of water between the two cells by using the water potential equation. Explain the characteristics of water that make it such an important medium for life. If an athlete was heavily perspiring after an intense match game, suggest one type of replacement drink (with explanation) that he should take between hypertonic, isotonic and hypotonic drink to recover himself. 3:41 AM 81°F C ) ENG 14/8/2021arrow_forward
- Consider a plant cell. The value for solute concentration in a plant cell is -0.12 MPa and the turgor pressure is 0.12 MPa. 1- What is the water potential in this plant cell? 2- If this plant cell were placed in a solution with water potential of -0.1 MPa, what would happen to the cell? (Hint: explain where the water goes and what that does to the cell).arrow_forward1) A plant cell with a pressure potential of 5 bars and an osmotic potential of -9 bars is in equilibrium with a surrounding solution that is open to the air. What is the water potential of the surrounding solution? 2) A plant cell, when initially placed in pure water, has an osmotic potential of -4 bars and a pressure potential of +2 bars. a) Which way will water diffuse? b) When will net diffusion stop? c) When equilibrium is reached, what are the cell's osmotic potential and pressure potential values?arrow_forwardWater potential a) The value for Ψ in root tissue was found to be -3.3 bars. If you take the root tissue and place it in a 0.1 M solution of sucrose at 20°C in an open beaker, what is the Ψ of the solution, and in which direction would the net flow of water be? b) NaCl dissociates into 2 particles in water: Na+ and Cl-. If the solution in question 4 contained 0.1M NaCl instead of 0.1M sucrose, what is the Ψ of the solution, and in which direction would the net flow of water be? c) A plant cell with a Ψs of -7.5 bars keeps a constant volume when immersed in an open-beaker solution that has a Ψs of -4 bars. What is the cell’s ΨP?arrow_forward
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