To find : solution to the exponential equation algebraically.

Answer to Problem 39E
The solution to the equation 4x=5x2 is x=0 & x≈0.861 _
Explanation of Solution
Given information: 4x=5x2
Concept Involved:
The word “solve” means the process of finding the value of x that makes the equation true. In order to solve we need to undo whatever is done to x .
Formula Used
lnmn=n(lnm)
lne=1
Calculation:
Take natural logarithm on both sides of the equation
ln4x=ln5x2
Use the logarithmic property lnmn=n(lnm) on both sides of the equation to rewrite it
x⋅ln4=x2⋅ln5
Subtracting x⋅ln4 on both sides of the equation in order to get x alone in one side of the equation
x⋅ln4−x⋅ln4=x2⋅ln5−x⋅ln4
Simplify on both sides of the equation
0=x2⋅ln5−x⋅ln4
Use symmetric property of equality to rewrite the equation
x2⋅ln5−x⋅ln4=0
Factor x in left side of the equation
x(x⋅ln5−ln4)=0
Use the zero factor property which states that “if ab=0 , then a=0 or b=0 ” to set each factor equal to 0
x=0 ►1st equation
x⋅ln5−ln4=0 ►2nd equation
Solve the 2nd equation x⋅ln5−ln4=0
- By adding ln4 on both sides, then
- By Simplifying on both sides of the equation, then
- By dividing ln5 on both sides, and then
- By Simplifying fraction on both sides
x⋅ln5−ln4+ln4=0+ln4
x⋅ln5=ln4
x⋅ln5ln5=ln4ln5
x=ln4ln5
x≈0.861
Check for extraneous solution by substituting the result in the original equation.
Both x=0 & x≈0.861 makes the original equation TRUE
Conclusion:
The solution to the equation 4x=5x2 is x=0 & x≈0.861 _
Chapter 3 Solutions
EBK PRECALCULUS W/LIMITS
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