Algebra 1
Algebra 1
1st Edition
ISBN: 9780078884801
Author: McGraw-Hill/Glencoe
Publisher: Glencoe/McGraw-Hill School Pub Co
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Chapter 3.3, Problem 59SR
To determine

Graph the equation 0=12x−48 .

Expert Solution & Answer
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Explanation of Solution

Given:

The equation: 0=12x−48

Concept Used:

The  x -intercepts are where the graph crosses the  x -axis, and the  y -intercepts are where the graph crosses the  y -axis.

Then, algebraically,

  • an  x -intercept is a point on the graph where  y  is zero, and
  • a  y -intercept is a point on the graph where  x  is zero.

More specifically,

  • an  x -intercept is a point in the equation where the  y -value is zero, and
  • a  y -intercept is a point in the equation where the  x -value is zero.

Calculation:

The equation: 0=12x−48

We can graph the equation by using x and y − intercept method. First we find the x and y intercept from the equation and then plot the points on the grid and join then to complete the graph.

Find the x − intercept, plug in y = 0 in the equation.

  0=12x−480=12x−48 [Plug  in  y=0]48=12x−48+4848=12x4812=12x124=x⇒x=4 x − Intercept: x=4

Find the y − intercept, plug in x = 0 in the equation

  0=12x−480=12⋅0−48 [Plug  in  x=0]0 y − Intercept: y =0

Graph the line 0=12x−48 with x and y intercepts points are (4, 0) and (0, 0)

  Algebra 1, Chapter 3.3, Problem 59SR

Thus, x and y intercepts are x = 4 and y = 0

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Chapter 3.3, Problem 58SR
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Chapter 3.3, Problem 60SR

Chapter 3 Solutions

Algebra 1

Ch. 3.1 - Prob. 35PPSCh. 3.1 - Prob. 58PPSCh. 3.1 - Prob. 60HPCh. 3.1 - Prob. 68STPCh. 3.1 - Prob. 1ACYPCh. 3.1 - Prob. 1BCYPCh. 3.1 - Prob. 2CYPCh. 3.1 - Prob. 3CYPCh. 3.1 - Prob. 4ACYPCh. 3.1 - Prob. 4BCYP
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