Algebra 1
Algebra 1
1st Edition
ISBN: 9780078884801
Author: McGraw-Hill/Glencoe
Publisher: Glencoe/McGraw-Hill School Pub Co
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Chapter 3.1, Problem 46PPS
To determine

Graph the equation 23x+y=−7 .

Expert Solution & Answer
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Answer to Problem 46PPS

Graph by using the x and y intercepts. They are x = − 10.5 and y = − 7

Explanation of Solution

Given:

The equation: 23x+y=−7

Concept Used:

The  x -intercepts are where the graph crosses the  x -axis, and the  y -intercepts are where the graph crosses the  y -axis.

Then, algebraically,

  • an  x -intercept is a point on the graph where  y  is zero, and
  • a  y -intercept is a point on the graph where  x  is zero.

More specifically,

  • an  x -intercept is a point in the equation where the  y -value is zero, and
  • a  y -intercept is a point in the equation where the  x -value is zero.

Calculation: The equation: 23x+y=−7

We can graph the equation by using x and y − intercept method. First we find the x and y intercept from the equation and then plot the points on the grid and join then to complete the graph.

Find the x − intercept, plug in y = 0 in the equation.

  23x+y=−723x  +0=−7   .[Plug  in  y=0]23  ·  3 x =   −7  ·  3  [ Multiply  both  sides by  3] 2x=−212x2  =  −212    [  Divide  each  side  by  2  ]x=−10.5 x − Intercept: x= − 10.5

Find the y − intercept, plug in x = 0 in the equation

  23x+y=−723  ·  0  +y=−7   .[Plug  in  x=0]y=−7 y − Intercept: y = − 7

Graph the line 23x+y=−7 with x and y intercepts points are (− 10.5, 0) and (0, − 7 )

  Algebra 1, Chapter 3.1, Problem 46PPS

Thus, x and y intercepts are x = − 10.5 and y = − 7

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Chapter 3 Solutions

Algebra 1

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