Algebra 1
Algebra 1
1st Edition
ISBN: 9780078884801
Author: McGraw-Hill/Glencoe
Publisher: Glencoe/McGraw-Hill School Pub Co
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Maximization
Have you ever seen a bridge in the shape of a parabola? Where is its maximum on the bridge? The maximum of that bridge is the highest point on that bridge. The process of finding the maximum of the bridge here is called the maximization.
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Chapter 3.1, Problem 48PPS
To determine

Graph the equation 3y−7=4x+1 .

Expert Solution & Answer
Check Mark

Answer to Problem 48PPS

Graph by using the x and y intercepts. They are x = − 2and y = 2.667

Explanation of Solution

Given:

The equation: 3y−7=4x+1

Concept Used:

The  x -intercepts are where the graph crosses the  x -axis, and the  y -intercepts are where the graph crosses the  y -axis.

Then, algebraically,

  • an  x -intercept is a point on the graph where  y  is zero, and
  • a  y -intercept is a point on the graph where  x  is zero.

More specifically,

  • an  x -intercept is a point in the equation where the  y -value is zero, and
  • a  y -intercept is a point in the equation where the  x -value is zero.

Calculation: The equation: 3y−7=4x+1

We can graph the equation by using x and y − intercept method. First we find the x and y intercept from the equation and then plot the points on the grid and join then to complete the graph.

Find the x − intercept, plug in y = 0 in the equation.

  3y−7=4x+13  ·  0  −7=4x+1  .[Plug  in  y=0]−7=4x+1−7−1=4x−8=4x−84  =  4x4x=−2 x − Intercept: x = − 2

Find the y − intercept, plug in x = 0 in the equation

  3y−7=4x+13y−7=4  ·  0  +1  .[Plug  in  x=0]3y−7+7=1+73y=83y3  =  83y=2.667 y − Intercept: y = 2.667

Graph the line 3y−7=4x+1 with x and y intercepts points are (− 2, 0) and (0, 2.667)

  Algebra 1, Chapter 3.1, Problem 48PPS

Thus, x and y intercepts are x = −2 and y = 2.667

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Chapter 3 Solutions

Algebra 1

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