
To Find: the vertices of the

Answer to Problem 21PPS
(5,7.5),(−5.348,−0.261) and (1.161,−2.865)
Explanation of Solution
Given
Given inequalities are.
−3x+4y≤15,2y+5x>−12 and 10y+60≥27x .
Calculation:
Drawing the graph of inequality −3x+4y≤15 .
On simplifying −3x+4y≤15 .
−3x+4y≤154y≤15+3xy≤154+34x
Plot the coordinates of equation y=154+34x .
xy0154−50
Shade the region below the line as y≤154+34x .
Drawing the graph of inequality 2y+5x>−12 .
On simplifying 2y+5x>−12 .
2y+5x>−122y>−12−5xy>−6−52x
Plot the coordinates of equation y=−6−52x .
xy0−6−1250
Shade the region above the line as y>−6−52x .
Drawing the graph of inequality 10y+60≥27x .
On simplifying 10y+60≥27x .
10y+60≥27x10y≥27x−60y≥2.7x−6
Plot the coordinates of equation y=2.7x−6 .
xy0−62.220
Shade the region above the line as y≥2.7x−6 .
From the above graph, vertices of triangle formed are (5,7.5),(−5.348,−0.261) and (1.161,−2.865)
So,the answer is (5,7.5),(−5.348,−0.261) and (1.161,−2.865)
Chapter 3 Solutions
Glencoe Algebra 2 Student Edition C2014
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