Concept explainers
(a)
The emf across
(a)
Answer to Problem 52CP
The emf across
Explanation of Solution
Given info: The battery emf is
Initially switch s is closed so the total current distribute in two current one is flow in the right loop and another current flow in the left loop.
Write the expression for the total current by Kirchhoff junction rule.
Here,
Write the expression for the current in the right loop.
Here,
Since for the steady state condition
Substitute
Substitute
Write the expression for the current in the left loop.
Substitute
Substitute
Write the expression for the voltage across the inductor by Kirchhoff loop rule after
Rearrange the term for
Substitute
Conclusion:
Therefore, the emf across
(b)
The point of the coil that have higher potential.
(b)
Answer to Problem 52CP
The point
Explanation of Solution
Given info: The battery emf is
Since the current flow upwards to downward direction in the inductor coil due to some reactance of the coil the voltage drop across the inductor coil hence the point
Write the expression for the voltage drop across the inductor coil.
Here,
Conclusion:
Therefore, the point
(c)
To draw: The graph of currents in
(c)
Answer to Problem 52CP
The graph of currents in
Explanation of Solution
Given info: The battery emf is
The currents in
In
Figure (I)
(d)
The time at which the value of current in
(d)
Answer to Problem 52CP
The time at which the value of current in
Explanation of Solution
Given info: The battery emf is
Formula to calculate the current in the circuit after
Substitute
Take log and solve the equation further,
Conclusion:
Therefore, the time at which the value of current in
Want to see more full solutions like this?
Chapter 31 Solutions
Physics for Scientists and Engineers with Modern Physics
- Consider the circuit in Figure P32.18, taking = 6.00 V, L = 8.00 mH, and R = 4.00 . (a) What is the inductive time constant of the circuit? (b) Calculate the current in the circuit 250 s after the switch is closed. (c) What is the value of the final steady-state current? (d) After what time interval does the current reach 80.0% of its maximum value?arrow_forwardShow that Equation 32.28 in the text Ls Kirchhoffs loop rule as applied to the circuit in Figure P32.56 with the switch thrown to position b.arrow_forwardA thin wire = 30.0 cm long is held parallel to and d = 80.0 cm above a long, thin wire carrying I = 200 A and fixed in position (Fig. P30.47). The 30.0-cm wire is released at the instant t = 0 and falls, remaining parallel to the current-carrying wire as it falls. Assume the falling wire accelerates at 9.80 m/s2. (a) Derive an equation for the emf induced in it as a function of time. (b) What is the minimum value of the emf? (c) What is the maximum value? (d) What is the induced emf 0.300 s after the wire is released? Figure P30.47arrow_forward
- Figure CQ20.7 shows a slidewire generator with motional cmf 0 when the wire at A slides across the top and bottom rails at constant velocity v0. (a) When the wire reaches B so that the area enclosed by the circuit is doubled, determine the ratio of the new cmf to the original cmf, /0. (b) If the wire's speed is doubled so that v = 2v0 determine the ratio /0. Figure CQ20.7arrow_forwardEach of the three situations in Figure P32.68 shows a resistor in a circuit in which currents are induced. Using Lenzs law, determine whether the current in each situation is from a to b or from b to a. a. If the current I in the wire in Figure P32.68A is increased from zero to I, what is the direction of the current induced across the resistor R? b. The switch in Figure P32.68B is initially closed and is thrown open at t = 0. What is the direction of the current induced across the resistor R immediately afterward? c. A bar magnet is brought close to the circuit shown in Figure P32.68C. What is the direction of the current induced across the resistor R?arrow_forward(i) When a particular inductor is connected to a source of sinusoidally varying emf with constant amplitude and a frequency of 60.0 Hz, the rms current is 3.00 A. What is the rms current if the source frequency is doubled? (a) 12.0 A (b) 6.00 A (c) 4.24 A (d) 3.00 A (e) 1.50 A (ii) Repeat part (i) assuming the load is a capacitor instead of an inductor. (iii) Repeat part (i) assuming the load is a resistor instead of an inductor.arrow_forward
- Physics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning
- Physics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning