Introduction to Java Programming and Data Structures, Comprehensive Version (11th Edition)
11th Edition
ISBN: 9780134670942
Author: Y. Daniel Liang
Publisher: PEARSON
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Chapter 30.4, Problem 30.4.4CP
Explanation of Solution
Purpose of given code:
The purpose of given code is to print all elements in array variable “int[] values” using “IntStream” class.
Explanation:
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a) FindMinIterative
public int FindMin(int[] arr) { int x = arr[0]; for(int i = 1; i < arr.Length; i++) { if(arr[i]< x) x = arr[i];
} return x; }
b) FindMinRecursive
public int FindMin(int[] arr, int length) { if(length == 1) return arr[0];
return Math.Min(arr[length - 1], Find(arr, length - 1));
}
What is the Big-O for this functions. Could you explain the recurisive more in details ?
Turn this into a flowchart/pseudo code.
//This is where the functions go void insertfront(int data);void insert(int data);void display();void deletedata(int data);void reverselist();void searchdata(int data);void swap();void datasort();void deleteList();
#include <iostream>#include <stdlib.h>using namespace std;
struct Node {int data;struct Node *next;};
struct Node* head = NULL;struct Node* rhead = NULL;int count1;
//insert in front for reversedlistvoid insertfront(int data){Node* new_node = (Node*) malloc(sizeof(Node)); new_node->data = data; new_node->next = rhead; rhead=new_node;}//insert at endvoid insert(int new_data){Node* ptr;ptr = head;Node* new_node = (Node*) malloc(sizeof(Node)); new_node->data = new_data; new_node->next = NULL;if (head == NULL) { head = new_node; } else{while (ptr->next!= NULL) { ptr = ptr->next;}ptr->next=new_node;}count1++;}//display listvoid display() {struct Node* ptr;ptr = head;if(head==NULL){cout<<"Sorry the list…
extern "C" int f(int *,int,int);
int a[2][2] = {{11,12},{21,22}};
void setup(){ Serial.begin(115200); while(!Serial); delay(500); int *arr = (int*)a; Serial.println(f(arr,2,2));
}
void loop(){
}
.global f
f: ldr r3,[r0] // get first element
mov r2,#0add r2,r3
mov r1, #3
lp:
add r0,#4 // add next elementldr r3,[r0]add r2,r3sub r1,#1
bgt lp
mov r0,r2
bx lr
Describe what operation is being performed in this code
Chapter 30 Solutions
Introduction to Java Programming and Data Structures, Comprehensive Version (11th Edition)
Ch. 30.1 - Prob. 30.1.1CPCh. 30.2 - Prob. 30.2.1CPCh. 30.2 - Prob. 30.2.2CPCh. 30.2 - Prob. 30.2.3CPCh. 30.2 - Prob. 30.2.4CPCh. 30.3 - Prob. 30.3.1CPCh. 30.3 - Prob. 30.3.2CPCh. 30.3 - Prob. 30.3.3CPCh. 30.3 - Prob. 30.3.4CPCh. 30.3 - Given an array names in Listing 30.1, write the...
Ch. 30.4 - Prob. 30.4.1CPCh. 30.4 - How do you create a parallel stream?Ch. 30.4 - Prob. 30.4.3CPCh. 30.4 - Prob. 30.4.4CPCh. 30.4 - Prob. 30.4.5CPCh. 30.4 - Write a statement to obtain an array of 1000...Ch. 30.5 - Prob. 30.5.1CPCh. 30.5 - Prob. 30.5.2CPCh. 30.5 - Prob. 30.5.3CPCh. 30.5 - Prob. 30.5.4CPCh. 30.6 - Prob. 30.6.1CPCh. 30.7 - Prob. 30.7.1CPCh. 30.8 - Can the following code be used to replace line 19...Ch. 30.8 - Prob. 30.8.2CPCh. 30.8 - Prob. 30.8.3CPCh. 30.8 - Prob. 30.8.4CPCh. 30.8 - Write the code to obtain a one-dimensional array...Ch. 30 - Prob. 30.1PECh. 30 - Prob. 30.2PECh. 30 - Prob. 30.3PECh. 30 - (Print distinct numbers) Rewrite Programming...Ch. 30 - Prob. 30.5PECh. 30 - Prob. 30.6PECh. 30 - Prob. 30.7PECh. 30 - Prob. 30.8PECh. 30 - Prob. 30.9PECh. 30 - Prob. 30.10PECh. 30 - Prob. 30.11PECh. 30 - (Sum the digits in an integer) Rewrite Programming...Ch. 30 - (Count the letters in a string) Rewrite...Ch. 30 - Prob. 30.14PECh. 30 - (Display words in ascending alphabetical order)...Ch. 30 - Prob. 30.16PECh. 30 - Prob. 30.17PECh. 30 - (Count the occurrences of words in a text file)...Ch. 30 - (Summary information) Suppose the file test.txt...
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