Introduction to Java Programming and Data Structures, Comprehensive Version (11th Edition)
Introduction to Java Programming and Data Structures, Comprehensive Version (11th Edition)
11th Edition
ISBN: 9780134670942
Author: Y. Daniel Liang
Publisher: PEARSON
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Chapter 30.5, Problem 30.5.2CP

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Purpose of given code:

The purpose of given code is to print resultant element in array variable “m” with “IntStream” class using aggregate functions. It multiples all the values in array with stream object “e1*e2” using “reduce()” method...

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This question is in Java. We are required to map over some data and incement by 10.  import.java.util.stream.Collectors; import.java.util.stream.Stream public class IncrementTheData implements Assignment {public Object solution(ArrayList<Integer> nums) {  Stream.of(1,2,3,4,5,6) .map(not sure what would go in here) .collectors(Collectors.toList())return null;}} //So this is as far as I got with this question. The instructions are vague but I think I'm on the right track. Am I?
void ExtractMinimumWeightPath(int path[MAX], int weights[MAX][MAX], int pathWeights[MAX][MAX], int rowc, int colc){int rowsCount = rowc;int colsCount = colc;path[rowsCount];int col = 0;int i = 0;for(i=1;i<colsCount;i++){if(pathWeights[rowsCount-1][i]<pathWeights[rowsCount-1][col]){col = i;}} int row = rowsCount-1;do{path[row] = col + 1;if (col>0 && pathWeights[row-1][col-1] + weights[row][col] == pathWeights[row][col]){col = col - 1;} else if (col < colsCount-1 && pathWeights[row-1][col+1] + weights[row][col] == pathWeights[row][col]){col = col + 1;}row--;} while(row>0);path[0] = col + 1;}   This is a code in C,  I need to change the code as much as possible, but on condition to perform the same work as this. Changing the var names and the loops is enough
int binsearch (int X , int V [] , int n )  {      int low , high , mid , i ;      low = 0;      high = n - 1;            for ( i = 0; i < high ; i ++)      {          if( V[ i ] > V [ i +1])          return -2;      }                    while ( low <= high )          {              mid = ( low + high )/2;              if ( X < V [ mid ])              high = mid - 1;              else              if ( X > V [ mid ])              low = mid + 1;              else              return mid ;          }              return -1;  }   This code takes as input a sorted array V of size n, and an integer X, if X exists in the array it will return the index of X, else it will return -1. 1. Draw a CFG for binsearch(). 2. From the CFG, identify a set of entry–exit paths to satisfy the complete statement coverage criterion. 3. Identify additional paths, if necessary, to satisfy the complete branch coverage criterion. 4. For each path identified above, derive their path predicate…

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Introduction to Java Programming and Data Structures, Comprehensive Version (11th Edition)

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