Biochemistry
9th Edition
ISBN: 9781319114671
Author: Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher: W. H. Freeman
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Chapter 30, Problem 18P
Interpretation Introduction
Interpretation:
The amino acid sequence of the extra segment of protein formed in a thalassemic patient that has a mutation resulting in aberrant splicing should be determined.
Concept introduction:
RNA splicing is a process during RNA processing. In this processing, a recently formed precursor messenger RNA transcript is changed into a mature messenger RNA.
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AAAGAGAAAAGAAUA
to AAAGAGAAAUGAAUA.
Suppose the codon sequence
has a single base pair mutation
If the old protein sequence was Lys-Glu-Lys-Arg-Ile, what will be the new sequence encoded by the mutant gene?
(Use the 3-letter amino acid abbreviations with hyphens and no spaces in between, i.e. Ser-Asn-Tyr-Leu-Pro.)
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Hi, help please.
Which of the following is TRUE regarding RNA editing?
a .The coding sequence is altered in the chromosome
b. More than one answer choice is correct
c. The mRNA is altered by Guide RNAs
d. Translation first takes place, following by altering of the coding sequence
Complements. The sequence of part of an mRNA is
5'-AUGGGGAACAGCAAGAGUGGGGCCCUGUCCAAGGAG-3'
5'-AUGGGGAACAGCAAGAGUGGGGCCCUGUCCAAGGAG-3'
What is the sequence of the DNA coding strand? Of the DNA template
strand?
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- Be sure to answer all parts. Write a possible mRNA sequence that codes for each peptide. a. His-Cys-Tyr-Val-Ser 5¹- b. Phe-Val-Thr-Tyr-Glu 5'- 5'- c. Trp-Phe-Asn-Gln -3' U -3' с Table 26.2 The Genetic Code-Triplets in Messenger RNA First Base (5' end) -3' U UUU UUC UUA UUG CUU CUC CUA CUG AUL Phe Phe Leu Leu Leu Leu Leu Leu la C UCU UCC UCA UCG CCU CCC CCA CCG Second Base A UAU UAC UAA UAG CAU CAC CAA CAG Ser Ser Ser Ser Pro Pro Pro Pro Tyr 55 Tyr Stop Stop His His Gin Gin G UGU UGC UGA UGG CGU CGC CGA CGG Cys Cys Stop Trp Arg Arg Arg Arg Third Base (3¹ ond) DUAC DU AG с А Аarrow_forwardTrue or False. Explain. A) At no time during protein synthesis does an amino acid make direct contact with the mRNA being translated. B) Because the two strands of DNA are complementary, the mRNA of a gene can be synthesized using either strand as a template.arrow_forwardTranslation. Write the anti-codon sequence of the MRNA transcript. Translate the MRNA transcript into peptide sequence using both the 3 letter abbreviation and 1 letter abbreviation. ANTI-CODON 3' 5' SEQUENCE AMINO ACID N- C- SEQUENCE (3 letter terminus Abbreviation) Terminus AMINO ACID N- C- SEQUENCE (1 letter terminus Abbreviation) Terminusarrow_forward
- I am more confused. how about we start from begining, you post answers on here, and then we go from there? 1. Identify the open reading frame in the following DNA sequence, the protein that this gene encodes for, its function, and the source. 2. "Look carefully at the DNA sequence and identify the start site for transcription" 3. Click on the DNA sequence from the start site of transcription, select all of the sequence, and copy the sequence. Go to the National Center for Biotechnology Information (NCBI) website http://www.ncbi.nlm.nih.gov/. Click on BLAST on the right-hand side under “Popular Resources.” BLAST is a program that will allow you to find the protein sequence for the DNA sequence (gene) you submit. Next click on blastx (translated nucleotide protein). Paste the DNA sequence into the box under “Entry Query Sequence.” Scroll down and click BLAST. The search may take a few seconds; the page will keep updating until the search is completed. You do not need to enter any…arrow_forwardtRNA enzyme. Any given aminoacyl-tRNA synthetase: a. Attaches the amino acid to the 5′-end '5end of the tRNA b. Always recognizes only one specific tRNA c. Recognizes all tRNA molecules d. Forms an ester linkage between the amino acid and the tRNAarrow_forwardOpen reading frames... correspond to introns, which are not read by the ribosome during translation correspond to contiguous fragments of DNA sequence that do not contain a stop codon when read in a particular frame correspond to contiguous fragments of DNA sequence that do not contain a stop codon when read in any of six frames are often rich in acetylated histones which allow transcription occur when fragments of DNA sequence are highly similar between two species are recognized by ribosomes to initiate translationarrow_forward
- please help me with thi question. What advantages do CRISPR‑Cas systems have over restriction enzymes and engineered nucleases for editing DNA? The options are attached. Multiple answers can be chosenarrow_forwardprotein. You create a mouse line with Cas9 under control of a brain-specific enhancer, while the short guide RNA complementary to the first exon of Gene Y is expressed in all tissues. You subsequently sequence Gene Y in both brain and liver tissue. What would expect in each tissue? You can assume that the CRISPRICas9 system will impact both copies of Gene Y in cells, and that the first exon of Gene Y is necessary for Gene Ys function. a. Liver: Functional Gene Y; Brain: Functional Gene Y b. Liver: Nonfunctional Gene Y; Brain: Funtional Gene Y c. Liver: Functional Gene Y; Brain: Nonfunctional Gene Y d. Liver: Nonfunctional Gene Y; Brain: Nonfunctional Gene Yarrow_forwardYes or no only. rna seq can provide sequence and expression data do riboprobes synthesize bu in vitro transcription? does rna causes mutations and lose of function of specific genes?arrow_forward
- . The following synthetic polynucleotide is synthesized and used as a template for peptide synthesis in a cell-free system from E. coli. .AUAUAUAUAUAUAU-. What polypeptide would you expect to be produced? Precisely what information would this give you about the code?arrow_forward. Why is a nonsense suppressor tRNATyr, even though ithas a mutant anticodon that cannot recognize a tyrosinecodon, charged with tyrosine by Tyr tRNA synthetase?arrow_forwardPlease do answer all the questions. I'll definitely give a like You discovered a halophilic bacterium and want to characterize the mechanism involved in producing mature tRNA molecules from larger tRNA precursors. You isolated a large complex composed of a protein component and an RNA component that is capable of cleaving the larger tRNA precursor. To determine which one of the two components is responsible for catalysis, you perform an in vitro tRNA cleavage assay in the proper buffer conditions, including a low concentration of Mg2+ and 0.5 M bovine serum albumin (BSA). BSA is not specific for this reaction. The table below summarizes the results after performing eight separate reactions. The + symbol indicates the included reaction components. Q. Based on the results obtained, what can you conclude about the composition of the biological catalyst required for the maturation of tRNA? Q. Indicate which reactions helped you make your conclusion. Why? Q. Which reactions allowed you…arrow_forward
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