Concept explainers
Complete the following table by writing formulas for the compounds formed when the cations listed across the top combine with the anions listed along the side.
Interpretation:
The given cations combine with anions to form chemical formulas are to be analyzed.
Concept Introduction:
An ionic compound consists of metal cation and a non-metal anion. The rules that are used for determining the chemical formula of ionic compounds are as follows:
First, identify the symbol of the elements in the periodic table.
Identify the charges on the cation and the anion.
After that, the symbol of the cation is written followed by that of the anion.
It is very important that the compound is electrically neutral or the charges of anions and cations are neutralized in the compound.
Explanation of Solution
Given Information:Table is provided in the question.
Potassium cation
The potassium, iron(III), strontium, aluminum, cobalt(II), and lead(IV) cations are combined with iodide, oxide, sulfate, nitrite, acetate, and hypochlorite anions to form chemical formulae of ionic compounds that are shown in the above table.
Want to see more full solutions like this?
Chapter 3 Solutions
Introduction to Chemistry
- Nonearrow_forwardJON Determine the bund energy for UCI (in kJ/mol Hcl) using me balanced chemical equation and bund energies listed? का (My (9) +36/2(g)-(((3(g) + 3(g) A Hryn = -330. KJ bond energy и-н 432 bond bond C-1413 C=C 839 N-H 391 C=O 1010 S-H 363 б-н 467 02 498 N-N 160 N=N 243 418 C-C 341 C-0 358 C=C C-C 339 N-Br 243 Br-Br C-Br 274 193 614 (-1 214||(=olin (02) 799 C=N 615 AALarrow_forwardDetermine the bond energy for HCI ( in kJ/mol HCI) using he balanced cremiculequecticnand bund energles listed? also c double bond to N is 615, read numbets carefully please!!!! Determine the bund energy for UCI (in kJ/mol cl) using me balanced chemical equation and bund energies listed? 51 (My (9) +312(g)-73(g) + 3(g) =-330. KJ спод bond energy Hryn H-H bond band 432 C-1 413 C=C 839 NH 391 C=O 1010 S-1 343 6-H 02 498 N-N 160 467 N=N C-C 341 CL- 243 418 339 N-Br 243 C-O 358 Br-Br C=C C-Br 274 193 614 (-1 216 (=olin (02) 799 C=N 618arrow_forward
- Differentiate between single links and multicenter links.arrow_forwardI need help on my practice final, if you could explain how to solve this that would be extremely helpful for my final thursday. Please dumb it down chemistry is not my strong suit. If you could offer strategies as well to make my life easier that would be beneficialarrow_forwardNonearrow_forward
- World of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage LearningChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningChemistry: Matter and ChangeChemistryISBN:9780078746376Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl WistromPublisher:Glencoe/McGraw-Hill School Pub Co
- Introductory Chemistry: An Active Learning Approa...ChemistryISBN:9781305079250Author:Mark S. Cracolice, Ed PetersPublisher:Cengage LearningIntroductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning