
Concept explainers
The direction in which the plane head.

Answer to Problem 49P
27.16° south of west
Explanation of Solution
Given:
Speed of plane, vp=620 km/hrAngle, θ = 35°Speed of wind, vw=95 km/hr
Formula Used:
Relative velocity
vpw=vp−vw
Calculation:
Consider the given situation.
vpw=vpcos35°−[vpsin35°−vw]vpw=620cos35°−[620sin35°−95]vpw=507.87i−[260.61]jvpw=507.87i−260.61j
Now,
tanθ=260.61207.81θ=27.16° south of west
Conclusion:
Therefore, the direction is 27.16° south of west
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