Concept explainers
17. (l) A tiger leaps horizontally from a 7.5-m-high rock with a speed of 3.0 m/s. How far from the base of the rock will she land?
To Determine:The distance from the base of the rock.
Solution:3.7 m
Explanation:
Given:
Height of the rock,
Initial speed of the tiger,
Formula Used:
Second equation of motion:
Where, u is the initial velocity, t is the time, a is acceleration and s is the displacement.
Calculations:
In horizontal direction, there is no acceleration. The time for the ball to reach the base can be calculated as follows:
In the same time, the ball will also cover the vertical displacement which is equal to the height of the building.
As the initial velocity in vertical direction is zero, therefore:
Substitute the given values and solve:
Conclusion:
Thus, the distance from the base of the rock where the tiger lands is 3.7 m.
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