Organic Chemistry
Organic Chemistry
2nd Edition
ISBN: 9781118452288
Author: David R. Klein
Publisher: WILEY
Question
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Chapter 3, Problem 44PP

(a)

Interpretation Introduction

Interpretation:

The equation and the curved arrow mechanism should be drawn for the reaction of the given bases with water.

Concept introduction:

Reaction of base with H2O is an acid-base reaction.

According to Bronsted-Lowery acid–base theory, proton acceptor is base and proton donor is treated as acid. Here water molecule acts as base and donates the proton to the base by giving hydroxide ion.

Example:

B-+H2OBH+OH-B-=base

To draw: The curved arrow mechanism for given base and water.

(b)

Interpretation Introduction

Interpretation:

The equation and the curved arrow mechanism should be drawn for the reaction of the given bases with water.

Concept introduction:

Reaction of base with H2O is an acid-base reaction.

According to Bronsted-Lowery acid–base theory, proton acceptor is base and proton donor is treated as acid. Here water molecule acts as base and donates the proton to the base by giving hydroxide ion.

Example:

B-+H2OBH+OH-B-=base

To draw: The curved arrow mechanism for given acid and water.

(c)

Interpretation Introduction

Interpretation:

The equation and the curved arrow mechanism should be drawn for the reaction of the given bases with water.

Concept introduction:

Reaction of base with H2O is an acid-base reaction.

According to Bronsted-Lowery acid–base theory, proton acceptor is base and proton donor is treated as acid. Here water molecule acts as base and donates the proton to the base by giving hydroxide ion.

Example:

B-+H2OBH+OH-B-=base

To draw: the curved arrow mechanism for given acid and water.

(d)

Interpretation Introduction

Interpretation:

The equation and the curved arrow mechanism should be drawn for the reaction of the given bases with water.

Concept introduction:

Reaction of base with H2O is an acid-base reaction.

According to Bronsted-Lowery acid–base theory, proton acceptor is base and proton donor is treated as acid. Here water molecule acts as base and donates the proton to the base by giving hydroxide ion.

Example:

B-+H2OBH+OH-B-=base

To draw: the curved arrow mechanism for given acid and water.

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