Chapter 3, Problem 3.75P

Interpretation Introduction

Interpretation:Mass of ${\text{NaH}}_{\text{2}}{\text{PO}}_4$ required to react with $\text{43}\text{.74 mL}$ of $\text{0}\text{.285 M NaOH}$ is to be calculated.

Concept introduction:The formula to evaluate moles from molarity is as follows:

  $n=MV$

Where,

• $V$represents volume.
• $M$represents molarity.
• $n$represents number of moles.

The formula to convert moles to mass in grams is as follows:

  $\text{Mass}=\left(\text{Number of moles}\right)\left(\text{molar mass}\right)$