Principles of Foundation Engineering (MindTap Course List)
9th Edition
ISBN: 9781337705028
Author: Braja M. Das, Nagaratnam Sivakugan
Publisher: Cengage Learning
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Chapter 3, Problem 3.5P
To determine
Find the corrected penetration numbers at the various depths.
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3. Following are the results of a standard penetration test in fine dry sand.
N60
Depth (m)
1.5
7
13
3.0
18
4.5
22
6.0
7.5
24
For, the sand deposit, assume the mean grain size, D50, to be 0.26 mm and the
unit weight of sand to be 15.5kN/m3. Estimate the variation of relative density
with depth using the correlation developed by Cubrinovski and Ishihara.
Assume pas100kN/m2.
denined friction
The standard penetration test results of a sand deposit at a certain site are
given below in tabular form. The groundwater table in located at a depth
of 2 m below the ground surface. The dry and saturated unit weights of
sand are 17 kN/m³ and 19.0 kN/m', respectively. For an expected
10.8
earthquake magnitude M = 6 and maximum acceleration amax = 0.1 g,
will liquefaction occur?
Depth (m)
NF (blows/30 cm)
1.5
8
3.0
7
4.5
12
6.0
15
7.5
17
9.0
17
Following is the variation of the field standard penetration number (N60) in a sand deposit: The groundwater table is located at a depth of 6 m. Given: the dry unit weight of sand from 0 to a depth of 6 m is 18 kN/m3, and the saturated unit weight of sand for depth 6 to 12 m is 20.2 kN/m3. Use the relationship given in Eq. (3.13) to calculate the corrected penetration numbers.
Chapter 3 Solutions
Principles of Foundation Engineering (MindTap Course List)
Ch. 3 - Prob. 3.1PCh. 3 - Prob. 3.2PCh. 3 - Prob. 3.3PCh. 3 - Refer to Figure P3.3. Use Eqs. (3.10) and (3.11)...Ch. 3 - Prob. 3.5PCh. 3 - Prob. 3.6PCh. 3 - Prob. 3.7PCh. 3 - Prob. 3.8PCh. 3 - Prob. 3.9PCh. 3 - Prob. 3.10P
Ch. 3 - Prob. 3.11PCh. 3 - Prob. 3.12PCh. 3 - Prob. 3.13PCh. 3 - Prob. 3.14PCh. 3 - Prob. 3.15PCh. 3 - Prob. 3.16PCh. 3 - Prob. 3.17PCh. 3 - Prob. 3.18PCh. 3 - Prob. 3.19PCh. 3 - Prob. 3.20PCh. 3 - Prob. 3.21PCh. 3 - Prob. 3.22PCh. 3 - Prob. 3.23PCh. 3 - Prob. 3.24PCh. 3 - Prob. 3.25PCh. 3 - Prob. 3.26PCh. 3 - Prob. 3.27PCh. 3 - Prob. 3.28PCh. 3 - Prob. 3.29PCh. 3 - Prob. 3.30PCh. 3 - Prob. 3.31P
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- A soil profile is shown in Figure P3.2 along with the standard penetration numbers in the clay layer. Use Eqs. (3.8) and (3.9) to determine the variation of cu and OCR with depth. What is the average value of cu and OCR?arrow_forwardA standard penetration test is carried out in sand where the efficiency of the hammer nH =70%. If the measured N-value at 30 ft depth is 24, find N60 and (N1)60. The unit weight of the sand is 115.0 lb/ft3. Assume nB = nS = nR =1.arrow_forwardFollowing are the results of a standard penetration test in sand. Determine the corrected standard penetration number, (N1)60, at various depths. Note that the water table was not observed within a depth of 10.5 m below the ground surface. Assume that the average unit weight of sand is 17.3 kN/m3. Depth (m) N60 1.5 8 3.0 7 4.6 12 6.0 14 7.5 13arrow_forward
- 2- Subsurface geotechnical investigations carried out in a deposit of sand provided the field standard penetration numbers N60 as given in the table below. During the geotechnical investigations, it is also observed that underground water table is encountered at a depth of 2.0 m below the ground surface. Laboratory tests have shown that physical properties of deposit of sand are as: Dry unit weight = 17.6 kN/m³ and saturated unit weight = 19.6 kN/m³. Determine, for an earthquake magnitude of 8.25, if liquefaction will occur at the site. Assume that maximum peak ground acceleration at the site is: amax = 0.25g. (6 points) DEPTH (M) N60 (BLOWS/30CM) 3 5 6 7 9 11 12 14 18 21 Note: the gravitational acceleration could be taken as 9.81 m/s².arrow_forward2- Subsurface geotechnical investigations carried out in a deposit of sand provided the field standard penetration numbers N60 as given in the table below. During the geotechnical investigations, it is also observed that underground water table is encountered at a depth of 2.0 m below the ground surface. Laboratory tests have shown that physical properties of deposit of sand are as: Dry unit weight = 17.6 kN/m³ and saturated unit weight = 19.6 kN/m. Determine, for an earthquake magnitude of 8.25, if liquefaction will occur at the site. Assume that maximum peak ground acceleration at the site is: amax = 0.25g. DEPTH (M) N60 (BLOWS/30CM) 6. 7 9 11 12 14 18 21 Note: the gravitational acceleration could be taken as 9.81 m/s.arrow_forward21 The results of a constant head permeability test for a fine sand are as follows: Diameter of the sample = 37 cm Length of sample = 92 cm Constant head difference = 78 cm Time of collection = 337 secs Weight of water collected = 375 grams Find the seepage velocity in cm/min. if the void ratio is 0.6. Round off to four decimal places.arrow_forward
- The results of a constant head permeability test for a fine sand are as follows: Diameter of the sample = 31 cm Length of sample = 98 cm Constant head difference = 52 cm Time of collection = 364 secs Weight of water collected = 448 grams Find the seepage velocity in cm/min. if the void ratio is 0.33. Round off to four decimal places. Answer: 0.3943arrow_forwardA standard penetration test was carried out in a normallyconsolidated sand at 25 ft depth where the N60 was determinedto be 28. The unit weight of the sand is 110 lb/ft3, andthe grain-size distribution suggests that D50 5 1.2 mm andCu 5 3.2. The age of the soil since deposition is approximately5000 years. Determine the relative density using thedifferent correlations discussed in Section 3.15arrow_forwardP-1 A soil profile is shown in Figure along with the standard penetration numbers in the clay layer. Use provided equations to Dry sand y = 16.5 kN/m³ 1.5 m Groundwater table Sand 1.5 m N60 Ysat = 19 kN/m³ determine the variation of 1.5 m • 8 Cu and OCR and preconsolidation pressure o', with depth. What is the average value of c, and OCR? Clay 1.5 m Ysat = 16.8 kN/m³ * A•8 1.5 m • 9 1.5 m 10 Sand 0.689 0.29N0.72 Pa Си N60 OCR = 0.193 o = 0.47NPa %3D %3D Shahid Chamran University of Abvaz 1 ר ר ררפarrow_forward
- The following are the results of a standard penetration test in sand. Determine the corrected standard penetration numbers, (N,), at the various depths given. Note that the water table was not observed within a depth of 12 m below the ground surface. Assume that the average unit weight of sand is 15.5 kN/m³. Depth (m) 1.5 8 3 7 4.5 12 14 7.5 13arrow_forwardPROBLEM 2: During a constant-head permeability test on a sand sample, 260 x 10° mm³ of water were collected in 2 minutes. If the sample had a length of 100 mm, a diameter of 40 mm and a maintained head of 200mm. What is its coefficient of permeability? a. 0.769 mm/s b. 0.967 mm/s c. 1.321 mm/s d. 0.862 mm/sarrow_forwardThe results of a constant-head permeability test for a fine sand sample having a diameter of 70 mm and a length of 140 mm are as follows (refer to Figure 7.5):• Constant-head difference = 550 mm• Water collected in 7 min = 450 cm3• Void ratio of sand = 0.8Determine:a. Hydraulic conductivity, k (cm/sec)b. Seepage velocityarrow_forward
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