Principles of Foundation Engineering (MindTap Course List)
9th Edition
ISBN: 9781337705028
Author: Braja M. Das, Nagaratnam Sivakugan
Publisher: Cengage Learning
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Chapter 3, Problem 3.24P
To determine
Find the penetration number
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Check out a sample textbook solutionStudents have asked these similar questions
A standard penetration test is carried out in sand where the efficiency of the hammer nH =70%. If the measured N-value at 30 ft depth is 24, find N60 and (N1)60. The unit weight of the sand is 115.0 lb/ft3. Assume nB = nS = nR =1.
3. Following are the results of a standard penetration test in fine dry sand.
N60
Depth (m)
1.5
7
13
3.0
18
4.5
22
6.0
7.5
24
For, the sand deposit, assume the mean grain size, D50, to be 0.26 mm and the
unit weight of sand to be 15.5kN/m3. Estimate the variation of relative density
with depth using the correlation developed by Cubrinovski and Ishihara.
Assume pas100kN/m2.
denined friction
Solve this problem graphically and then analytically. A CU triaxial
test was performed on a dense sand specimen at a confining pressure 03=40 kPa. The
consolidated undrained friction angle of the sand is =39°, and the effective friction angle
is d'=34°. Calculate: (a) the major principal stress at failure, o1, (b) the minor and the
major effective principal stresses at failure, o'3f and oʻır, and (c) the excess pore water
pressure at failure, (Aua)f.
Chapter 3 Solutions
Principles of Foundation Engineering (MindTap Course List)
Ch. 3 - Prob. 3.1PCh. 3 - Prob. 3.2PCh. 3 - Prob. 3.3PCh. 3 - Refer to Figure P3.3. Use Eqs. (3.10) and (3.11)...Ch. 3 - Prob. 3.5PCh. 3 - Prob. 3.6PCh. 3 - Prob. 3.7PCh. 3 - Prob. 3.8PCh. 3 - Prob. 3.9PCh. 3 - Prob. 3.10P
Ch. 3 - Prob. 3.11PCh. 3 - Prob. 3.12PCh. 3 - Prob. 3.13PCh. 3 - Prob. 3.14PCh. 3 - Prob. 3.15PCh. 3 - Prob. 3.16PCh. 3 - Prob. 3.17PCh. 3 - Prob. 3.18PCh. 3 - Prob. 3.19PCh. 3 - Prob. 3.20PCh. 3 - Prob. 3.21PCh. 3 - Prob. 3.22PCh. 3 - Prob. 3.23PCh. 3 - Prob. 3.24PCh. 3 - Prob. 3.25PCh. 3 - Prob. 3.26PCh. 3 - Prob. 3.27PCh. 3 - Prob. 3.28PCh. 3 - Prob. 3.29PCh. 3 - Prob. 3.30PCh. 3 - Prob. 3.31P
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- A cone penetration test result of a deposit of normally consolidated dry sand are given below. Estimate the drained friction angle of the sand using Kulhawy and Mayne's equation. The unit weight of the sand is 100 pcf. Depth ft 5.0 10.0 15.0 20.0 25.0 30.0 45 38 42 40 Tip resistance of cone, qc psi 300 600 800 1200 1400 1800arrow_forwardIn a deposit of normally consolidated dry sand a cone penetration test was conducted. Following are the result: Depth(m) Point resistance of cone, qc (MN/m²) 1.5 2.06 3.0 4.23 4.5 6.01 6.0 8.18 7.5 9.97 9.0 12.42 Assuming the dry unit weight of sand to be 16kN/m³, estimale the average peak friction angle, ф’, fo the sand. Use ф’=tan ¯1((0.38+0.27log(qc/ σ’o))arrow_forwardIn a standard penetration test in sands, the blow count measured at 14 m depth was 26. An automatic hammer released by a trip with an efficiency of 70% was used in the test. The unit weight of sand is 17.5 kN/m³. Determine: (a) N60 (N1) 60 using Peck, Hanson, and Thornburn (1974) correlation with Pa = 100 kPa. The most likely value of the friction angle (not the range). The possible range of relative density per Peck et al. (1974) The Young's Modulus. The table below presents two correlations proposed for estimating Young's Modulus. kg Leonards (1986) E .cm² E (kPa): = 8N60 = aPa (kPa)N60 Kulhawy & Mayne (1990) In the table a = 5 for fine sands, 10 for clean normally consolidated sands, and 15 for clean over consolidated sands. If a specific method is not specified, you may use any possible correlations. While doing so, you must clearly indicate which correlation was used.arrow_forward
- A direct shear test, when conducted on a remolded sample of sand, gave the following observations at the time of failure: Normal load = 288 N shear load = 173 N. The cross sectional area of the sample = 36 cm.sq. 1. Determine the angle of internal friction. (Select] 2. The magnitude of the major principal stress in the zone of failure. [Select] 3. Determine the magnitude of the deviator stress if a sample of the same sand with the same void ratio as given above was tested in a tri-axial apparatus with a confining pressure of 60 kPa. ( Select ]arrow_forward2. SPT test was performed at a shallow site composed of uniform granular soil with a unit weight = 20 kN/m³ (shown below are N60). a) Convert to (N1)60. b) Estimate the range of friction angles at depths between 20 and 40 ft. Use various correlations. Compare the differences. SPT N-values (bpf) 10 20 30 40 50 10 Silty Sand (SM): Piedmont Residuum 30 40 50 60 Depth (feet)arrow_forwardA direct shear test, when conducted on a remolded sample of sand, gave the following observations at the time of failure: Normal load = 288 N; shear load = 173 N. The cross-sectional area of the sample = 36 cm2. Determine the angle of internal friction in degrees. a. 29 b. 27 c. 33 d. 31arrow_forward
- Stress, kPa 8. Following data are given for a direct shear test conducted on dry sand: Dimension of the cylindrical specimen: diameter = 71 mm; height = 25 mm; Normal stress 250 kN/m²; shear force at failure: 560 N. Complete the following a) What is the orientation of the failure plane in the specimen? b) Determine the effective stress angle of friction.arrow_forward7.12 A sand specimen was subjected to a drained shear test using hollow cylin- der test equipment. Failure was caused by increasing the inside pressure while keeping the outside pressure constant. At failure, o, = 193 kN/m² and o; = 264 kN/m². The inside and outside radii of the specimen were 40 and 60 mm, respectively. (a) Calculate the soil friction angle. (b) Calculate the axial stress on the specimen at failure.arrow_forwardA dilatometer test was conducted in a clay deposit. The groundwater table was locatedat a depth of 3 m below the surface. At a depth of 8 m below the surface, the contact pressure spod was 280 kN/m2 and the expansion stress sp1d was 350 kN/m2. Determinethe following:a. Coefficient of at-rest earth pressure, Kob. Overconsolidation ratio, OCRc. Modulus of elasticity, EsAssume s 9o at a depth of 8 m to be 95 kN/m2 and ms 5 0.35.arrow_forward
- A direct shear test, when conducted on a remolded sample of sand, gave the following observations at the time of failure: Normal load = 288 N; shear load = 173 N. The cross-sectional area of the sample = 36 cm2. Determine the angle of internal friction in degrees. Include free body diagram. a.33 b.31 c.27 d.29arrow_forwardProblem # 5. The angle of friction of compacted dry sand is 37°. In a direct shear test on the sand, normal stress of 150 kN/m^2 was applied. The size of the specimen was 50mm x 50mm 30 mm (height): a. Compute the shearing stress.b. What shear force will cause will cause shear failure?c. Determine the shear stress at a depth 3m. If the void ratio of the soil is 0.60. Sp. Gr. of sand is 2.70.arrow_forwardhe following results were obtained from a direct shear test conducted on pure sand: Sample height and diameter = 30 mm and 75 mm respectively. Normal stress = 100 kN/m2 Shear force at failure = 185 N a) Determine the angle of friction for the soil. Round off to one decimal i.e. 99.5! b) What would be the shear force (in N) at failure if the normal stress is 175 kN/m2? Round off to the nearest figure i.e. 300.55 to 301! c) What would be the principal stress at failure? Consider a and barrow_forward
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