Steel Design (Activate Learning with these NEW titles from Engineering!)
6th Edition
ISBN: 9781337094740
Author: Segui, William T.
Publisher: Cengage Learning
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Question
Chapter 3, Problem 3.4.3P
To determine
(a)
The design strength.
To determine
(b)
The allowable strength.
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A double-angle shape is shown in the figure. The steel is
A36, and the holes are for 2-inch-diameter bolts.
Assume that A₂ = 0.75An.
Ae
1
2
Determine the design tensile strength for LRFD.
Determine the allowable strength for ASD.
CIVIL ENGINEERING
- STEEL DESIGN
AL
Section
2L5 x 3 x 516 LLBB
A 15" x 3/8" bar of A572 Gr. 50 steel is used as a tension member. It is connected to a gusset plate with 7/8-in diameter bolts as shown in the figure. Use s = 2.0 and g = 3.0.a) Determine the design tensile strength of the section based on yielding of the gross area.b) Determine the critical net area of the connection shown.
Tensile Strength
A PL 3/8 x 7 tension member is connected with three 1-inch-diameter
bolts, as shown in Figure P3.2-1. The steel is A36. Assume that Ae = An
%3D
and compute the following.
a. The design strength for LRFD.
b. The allowable strength for ASD.
PL %x7
O o o
Chapter 3 Solutions
Steel Design (Activate Learning with these NEW titles from Engineering!)
Ch. 3 - Prob. 3.2.1PCh. 3 - Prob. 3.2.2PCh. 3 - Prob. 3.2.3PCh. 3 - Prob. 3.2.4PCh. 3 - Prob. 3.2.5PCh. 3 - Prob. 3.2.6PCh. 3 - Prob. 3.3.1PCh. 3 - Prob. 3.3.2PCh. 3 - Prob. 3.3.3PCh. 3 - Prob. 3.3.4P
Ch. 3 - Prob. 3.3.5PCh. 3 - Prob. 3.3.6PCh. 3 - Prob. 3.3.7PCh. 3 - Prob. 3.3.8PCh. 3 - Prob. 3.4.1PCh. 3 - Prob. 3.4.2PCh. 3 - Prob. 3.4.3PCh. 3 - Prob. 3.4.4PCh. 3 - Prob. 3.4.5PCh. 3 - Prob. 3.4.6PCh. 3 - Prob. 3.5.1PCh. 3 - Prob. 3.5.2PCh. 3 - Prob. 3.5.3PCh. 3 - Prob. 3.5.4PCh. 3 - Prob. 3.6.1PCh. 3 - Prob. 3.6.2PCh. 3 - Prob. 3.6.3PCh. 3 - Select an American Standard Channel shape for the...Ch. 3 - Prob. 3.6.5PCh. 3 - Use load and resistance factor design and select a...Ch. 3 - Select a threaded rod to resist a service dead...Ch. 3 - Prob. 3.7.2PCh. 3 - Prob. 3.7.3PCh. 3 - Prob. 3.7.4PCh. 3 - Prob. 3.7.5PCh. 3 - Prob. 3.7.6PCh. 3 - Prob. 3.8.1PCh. 3 - Prob. 3.8.2PCh. 3 - Prob. 3.8.3PCh. 3 - Prob. 3.8.4PCh. 3 - Prob. 3.8.5P
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- A double-angle shape is shown in the figure. The steel is A36, and the holes are for 1/2-inch-diameter bolts. Assume the Ae = 0.75An. Section 215 x 3 x %6 LLBB Determine the design tensile strength for LRFD. Select one: а. 66 b. 156 c. 78 d. 132arrow_forwardQuestion 4 Complete the table below for the steel sections shown. All sections are bending about their horizontal axis. Section Location hep Ney Slenderness (show calculations) of element bf Flange te ld ++ tw be = 800 mm Web tf = 20 mm d = 1440 mm tw = 16 mm Grade 300, heavily 入。= Whole Asp= Asy= welded plates section br Flange tr d Web bf = 800 mm te = 20 mm d = 1420 mm tw = 16 mm Grade 300, heavily welded plates 入。= Whole Asp= Asy= sectionarrow_forwardA C8 × 11.5 is connected to a gusset plale with 22 mm diameter bolts as shown. The steel is A572 Grade 50. If the member is subjected to dead load and live load only, what is the total scrvice load capacity if the live-to-dead load ratio is 3? Assume that Ae = 0.85Ap. a. Use LRFD. b. Use ASD. Properties of A572 Grade 50: Fy = 345 MPa C8 × 11.5 Fu = 448 MPa Properties of C8 x 11.5: Ag = 2,181 mm? br = 57.4 mm d= 203.2 mm Lw = 5.6 mm lf = 9.9 mmarrow_forward
- The given angle bar L125x75x12 with Ag = 2,269 sq.mm. is connected to a gusset plate using 20 mm diameter bolts as shown in the figure. Using A36 steel with Fy = 248 MPa and Fu = 400 MPa, determine the following: 2. Determine the nominal tensile strength of the 12 mm thick, A36 angle bar shown based on: a. Gross yielding b. Tensile rupture Bolts used for the connection are 20 mm in diameter. O O O O O O O Effective net area of the tension member if the shear lag factor is 0.80. Select the correct response: 1,516.1 1,354.4 1,431.2 1,221.6arrow_forwardAn A36 tension member shown in the figure is connected with three 19 mm diamter bolts. Diameter of hole = 22mm. Properties of 150 mm x 100 mm x 12.5 mm angle A = 3065 mm2 y = 50.55 mm Fy = 248 MPa Fu = 400 MPa Determine the design strength due to yielding in the gross section. (kN)arrow_forwardA bolted lap joint is shown in the figure below. The bolts are 19mm in diameter. Effective diameter of the holes is 23mm. The plates are 12 mm thick, x1 = 33 mm, x2 = 76 mm, x3 = 50 mm. Yield strength of plate, Fy = 248 MPa Ultimate tensile strength of plate, Fu = 400 MPa Required: Using allowable strength design: 1. Find the safe load “P” based on gross area yielding. 2. Find the safe load “P” based on net area rupture. 3. Find the safe load “P” based on block shear.arrow_forward
- A double-angle shape is shown in the figure. The steel is A36, and the holes are for 1/2-inch-diameter bolts. Assume the Ae = 0.75An.a) Determine the allowable tensile strength for ASD.b) Determine the design tensile strength for LRFD.arrow_forward4. Calculate the design strength (ocPn) of W24X76 with length of 12 ft. and pinned ends. A572 Grade50 steel is used. E=29x103 ksi. Show your work in detail. ASTM Classification A36 A572 Grade 50 A992 Grade 50 A500 Grade B (HSS rect, sq) A500 Grade B (HSS round) A53 Grade B Yield Strength F, (ksi) 36 50 50 46 42 35 Ultimate Strength F (ksi) 58 65 65 58 58 60arrow_forwardTwo plates each with thickness t = 16 mm are bolted together with 6 – 22 mm diameter bolts forming a lap connection. Bolt spacing are as follows: S1 = 40 mm, S2 = 80 mm, S3 = 100 mm. Bolt hole diameter = 25 mm. Using A36 steel having Fy = 248 MPa and Fu = 400 MPa. P P S - P S2 S2 DETERMINE: 1. Determine the allowable load Pa based on bearing at bolt holes. (ASD) 2. Determine the ultimate load Pu based on block shear.arrow_forward
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