21st Century Astronomy
6th Edition
ISBN: 9780393428063
Author: Kay
Publisher: NORTON
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Chapter 3, Problem 19QP
To determine
Draw the geocentric model and heliocentric model of Earth, Venus and Sun and why telescope is necessary to distinguish between those models.
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Round off your answers to 4 decimal digits and box your final answers.
The table below presents the semi-major axis (a) and Actual orbital period for all of the major planets in the solar system. Cube for each planet the semi-major axis in Astronomical Units. Then take the square root of this number to get the Calculated orbital period of each planet. Fill in the final row of data for each planet.
Table of Data for Kepler’s Third Law:
Table of Data for Kepler’s Third Law:
Planet aau = Semi-Major Axis (AU) Actual Planet Calculated Planet
Period (Yr) Period (Yr)
__________ ______________________ ___________ ________________
Mercury 0.39 0.24
Venus 0.72 0.62
Earth 1.00 1.00
Mars 1.52 1.88
Jupiter…
Give me the right answer please and thank you, take your timeCalculate the amount of time it takes for light reflected off the surface of a distant planet to reach us.1. Sunlight takes about 8.3 minutes to travel from the Sun to Earth. What is the Sun-Earth distance in AU? (Give your answer rounded to the nearest AU).2.Light is reflected off the surface of a planet 5.2 AU away from us. How long does it take this light to reach us from the planet? Give your answer in minutes, rounded to exactly one decimal place.
Chapter 3 Solutions
21st Century Astronomy
Ch. 3.1 - Prob. 3.1ACYUCh. 3.1 - Prob. 3.1BCYUCh. 3.2 - Prob. 3.2CYUCh. 3.3 - Prob. 3.3CYUCh. 3.4 - Prob. 3.4CYUCh. 3 - Prob. 1QPCh. 3 - Prob. 2QPCh. 3 - Prob. 3QPCh. 3 - Prob. 4QPCh. 3 - Prob. 5QP
Ch. 3 - Prob. 6QPCh. 3 - Prob. 7QPCh. 3 - Prob. 8QPCh. 3 - Prob. 9QPCh. 3 - Prob. 10QPCh. 3 - Prob. 11QPCh. 3 - Prob. 12QPCh. 3 - Prob. 13QPCh. 3 - Prob. 14QPCh. 3 - Prob. 15QPCh. 3 - Prob. 16QPCh. 3 - Prob. 17QPCh. 3 - Prob. 18QPCh. 3 - Prob. 19QPCh. 3 - Prob. 20QPCh. 3 - Prob. 21QPCh. 3 - Prob. 22QPCh. 3 - Prob. 23QPCh. 3 - Prob. 24QPCh. 3 - Prob. 25QPCh. 3 - Prob. 26QPCh. 3 - Prob. 27QPCh. 3 - Prob. 28QPCh. 3 - Prob. 29QPCh. 3 - Prob. 30QPCh. 3 - Prob. 31QPCh. 3 - Prob. 32QPCh. 3 - Prob. 33QPCh. 3 - Prob. 34QPCh. 3 - Prob. 35QPCh. 3 - Prob. 36QPCh. 3 - Prob. 37QPCh. 3 - Prob. 38QPCh. 3 - Prob. 39QPCh. 3 - Prob. 40QPCh. 3 - Prob. 41QPCh. 3 - Prob. 42QPCh. 3 - Prob. 43QPCh. 3 - Prob. 44QPCh. 3 - Prob. 45QP
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- Mars is 1.5 times as far away from the Sun as Earth. Earth’s axis is tilted at 23.5o compared to the ecliptic. The axis of Mars is tilted at 25o compared to the ecliptic. The atmosphere on Earth is 100 times as thick as the atmosphere on Mars. Which of the following statements is true? 1.)Mars is so cold that the water there is ice, while Earth does not have any ice 2.)When it is summer in Earth’s northern hemisphere, it is winter on Mars’ southern hemisphere 3.) Earth has seasons, Mars does not 4.) All of the water on Mars is frozen, while Earth has water in solid, liquid and gas formarrow_forwardWhy might Tycho Brahe have hesitated to hire Kepler? Why do you suppose he appointed Kepler his scientific heir? What is limited about Keplers third law P2 = a3, where P is the time in units of years a planet takes to orbit the Sun and a is the planets average distance from the Sun in units of AU? (Hint: Look at the units.) What does this tell you about Kepler and his laws?arrow_forwardShow with a simple diagram how the lower parts of a ship disappear first as it sails away from you on a spherical Earth. Use the same diagram to show why lookouts on old sailing ships could see farther from the masthead than from the deck. Would there be any advantage to posting lookouts on the mast if Earth were flat? (Note that these nautical arguments for a spherical Earth were quite familiar to Columbus and other mariners of his time.)arrow_forward
- The timing of Moonrise is later every day. Let’s understand why: a) Moonrise occurs when you, as you sit on the rotating Earth, turn to the point where you can just see the Moon appear over the horizon. Draw a picture to illustrate what this would look like. Draw the Earth, Moon, and you standing on the Earth to indicate this scenario. (You’ve seen my artistic skills in class, I’m not asking you to do anything better than that. Just label/make clear what is shown). Take this as Day 1.In 24 hours, you would return back to that exact point on the Earth. However, the Moon will also have moved forward in its orbit (it orbits the Earth in the same direction that the Earth is spinning). How far along in its orbit does the Moon move? That is, assume the Moon is orbiting in a circular orbit; in going from Day 1 to Day 2, how many degrees does thee Moon move forward? Indicate (very roughly) via a drawing.b) Because the Moon advanced in its orbit, you now must wait…arrow_forwardWe need to create a scale model of the solar system (by shrinking the sun down to the size of a basketball or ~30cm). First, we will need to scale down actual solar system dimensions (planet diameters and average orbital radiuses) by converting our units. There are two blank spaces in the table below. We will effectively fill in the missing data in the next set of questions. Use the example below to help you. Example: What is the scaled diameter of Mercury if the Sun is scaled to the size of a basketball (30 cm)? The actual diameter of Mercury is 4879 km The Sun's diameter is 1392000 km If the Sun is to be reduced to the size of a basketball, then the conversion we need for this equation will be: 30cm1392000km Here is how we run the conversion: 4879km×30cm1392000km=0.105cm or 0.11cm if we were to round our answer. This means that if the sun in our model is the size of a basketball, Mercury is the size of a grain of sand. We can also see by looking at the table, that we would…arrow_forwardLet's use Kepler's laws for the inner planets. Use the following distances from the sun to calculate the orbital period for each of these planets. Express your answer in terms of Earth years to two significant figures. Answer for the highlighted planet in each question. Note: Use Kepler's law directly. Don't just Google the answers, as they will be a little bit different. When you have calculated them, only submit the value for Earth. Planet Distance from the sun Period of orbit around the sun Earth 150 million km ___ Earth years Mercury 58 million km ___ Earth years Venus 108 million km ___ Earth years Mars 228 million km ___ Earth yearsarrow_forward
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