Chapter 3, Problem 154QRT

Interpretation Introduction

Interpretation:

A $\text{9}\text{.360-g}$ sample of the window cleaner was diluted with $\text{35}\text{.778 g}$ water and $\text{4}\text{.188 g}$ of this diluted solution was titrated using $\text{13}\text{.58 mL of 0}\text{.1093-M HCl}$. The mass percent of ammonia has to be calculated.

Concept introduction:

The mass percent can be calculated by using following formula

  $Masspercent=\frac{Actualmassofproduct}{Theoreticalmassofproduct}\times 100$