College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Question
Chapter 28, Problem 1P
(a)
To determine
The wavelengths of the first three lines in the Lyman series for hydrogen.
(b)
To determine
The region of the electromagnetic spectrum in which the first lines of wavelengths are appeared.
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The wavelengths of the Lyman series for hydrogen are given by = RH(1-2), = 2, 3, 4, ...
1/2
(a) Calculate the wavelengths of the first three lines in this series.
nm
nm
nm
(b) Identify the region of the electromagnetic spectrum in which these lines appear.
O ultraviolet region
O infrared region
O x-ray region
O visible light region
O gamma ray region
3:09 O O O 63° A X •
N N O 5G „ll
Quizzes
a
(absorption)
Brackett
series
Paschen
series
Lyman
series
(emission)
Balmer series
Paschen
series
(emission)
n= 2
n=3
n=4
....
Lyman series
n-5
(a)
(b)
e These pictures refer to the energy levels
of a hydrogen atom.
You can find the error in both parts, (a) and
(b). The arrows labeled "emission" in (a), and
all the arrows in (b), indicate a transition in
which an electron jumps from a higher-
energy state to a lower-energy state. The
different "series" of emission lines are
characterized by the index n of the low-
energy state in which the electron ends up.
In particular, the Lyman series consists of all
transitions that end up in the n=1 energy
level, with an initial energy level that
corresponds to the label n = 2, 3, 4, 5, etc.
One of these values of n is not shown as an
arrow in the Lyman emission series in figures
(a) or (b). This is a significant error because
that particular spectral line is very important
in astronomy.
Pick the value…
The wavelengths of the Lyman series for hydrogen are given by = R
1
(a) Calculate the wavelengths of the first three lines in this series.
nm
nm
RH(1 - -/- 2 ), n =
n
nm
x-ray region
O infrared region
O ultraviolet region
‚n = 2, 3, 4, ...
(b) Identify the region of the electromagnetic spectrum in which these lines appear.
O visible light region
gamma ray region
Chapter 28 Solutions
College Physics
Ch. 28.3 - Prob. 28.1QQCh. 28.4 - Prob. 28.2QQCh. 28.5 - Prob. 28.3QQCh. 28 - Prob. 1CQCh. 28 - Prob. 2CQCh. 28 - Prob. 3CQCh. 28 - Prob. 4CQCh. 28 - Prob. 5CQCh. 28 - Prob. 6CQCh. 28 - Prob. 7CQ
Ch. 28 - Prob. 8CQCh. 28 - Prob. 9CQCh. 28 - Prob. 10CQCh. 28 - Prob. 11CQCh. 28 - Prob. 12CQCh. 28 - Prob. 13CQCh. 28 - Prob. 14CQCh. 28 - Prob. 15CQCh. 28 - Prob. 1PCh. 28 - Prob. 2PCh. 28 - Prob. 3PCh. 28 - Prob. 4PCh. 28 - Prob. 5PCh. 28 - Prob. 6PCh. 28 - Prob. 7PCh. 28 - Prob. 8PCh. 28 - Prob. 9PCh. 28 - Prob. 10PCh. 28 - Prob. 11PCh. 28 - Prob. 12PCh. 28 - Prob. 13PCh. 28 - Prob. 14PCh. 28 - Prob. 15PCh. 28 - Prob. 16PCh. 28 - Prob. 17PCh. 28 - Prob. 18PCh. 28 - Prob. 19PCh. 28 - Prob. 20PCh. 28 - Prob. 21PCh. 28 - Prob. 22PCh. 28 - Prob. 23PCh. 28 - Prob. 24PCh. 28 - Prob. 25PCh. 28 - Prob. 26PCh. 28 - Prob. 27PCh. 28 - Prob. 28PCh. 28 - Prob. 29PCh. 28 - Prob. 30PCh. 28 - Prob. 31PCh. 28 - Prob. 32PCh. 28 - Prob. 33PCh. 28 - Prob. 34PCh. 28 - Prob. 35PCh. 28 - Prob. 36PCh. 28 - Prob. 37PCh. 28 - Prob. 38PCh. 28 - Prob. 39PCh. 28 - Prob. 40PCh. 28 - Prob. 41PCh. 28 - Prob. 42PCh. 28 - Prob. 43PCh. 28 - Prob. 44PCh. 28 - Prob. 45PCh. 28 - Prob. 46APCh. 28 - Prob. 47APCh. 28 - Prob. 48APCh. 28 - Prob. 49APCh. 28 - Prob. 50APCh. 28 - Prob. 51APCh. 28 - Prob. 52APCh. 28 - Prob. 53APCh. 28 - Prob. 54AP
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
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- What is the de Brogue wavelength of a proton whose kinetic energy is 2.0 MeV? 10.0 MeV?arrow_forwardThe wavelengths of the Lyman series for hydrogen are given by 1 λ = RH 1 − 1 n2 ,n = 2, 3, 4, . . . (a) Calculate the wavelengths of the first three lines in this series. nm nm nm (b) Identify the region of the electromagnetic spectrum in which these lines appear. infrared regionvisible light region x-ray regionultraviolet regiongamma ray regionarrow_forwardThe wavelengths of the Brackett series for hydrogen are given by n = 5, 6, 7,.... (a) What are the wavelengths of the first three spectral emission lines in this series (in nm)? (Enter them in order of decreasing wavelength.) largest value nm nm smallest value nm (b) In which band of the electromagnetic spectrum do these lines appear? visible light region O infrared region O ultraviolet region O gamma ray region O x-ray regionarrow_forward
- The wavelengths of the Lyman series for hydrogen are given by: = RH(1-1), n = 2, 3, 4, ... For the second of this series; calculate the energy (in eV). Note: 1.60 x 10^-19 J = 1.0 eV O 4.10 x 10^3 eV 2.12 x 10^3 eV 3² O 1.21 x 10^3 eV 3.30 x 10^3 eVarrow_forwardThe wavelengths of the Lyman series for hydrogen are given by (a) Calculate the wavelengths of the first three lines in this series. (b) Identify the region of the electromagnetic spectrum in which these lines appeararrow_forwardThe wavelengths of the Lyman series for hydrogen are given by 1 R„(1 1 n = 2, 3, 4, ... H. n2 (a) Calculate the wavelengths of the first three lines in this series. (b) Identify the region of the electromagnetic spec- trum in which these lines appear.arrow_forward
- The light observed that is emitted by a hydrogen atom is explained by a simple model of its structure with one proton in its nucleus and an electron bound to it, but only with internal energies of the atom satisfying EH=−RH/n2EH=−RH/n2 where RHRH is the Rydberg constant and nn is an integer such as 1, 2, 3 ... and so on. When a hydrogen atom in an excited state emits light, the photon carries away energy and the atom goes into a lower energy state. Be careful about units. The Rydberg constant in eV is 13.605693009 eV That would be multiplied by the charge on the electron 1.602× 10-19 C to give 2.18× 10-18 J A photon with this energy would have a frequency f such that E=hf. Its wavelength would be λ = c/f = hc/E. Sometimes it is handy to measure the Rydberg constant in units of 1/length for this reason. You may see it given as 109737 cm-1 if you search the web, so be aware that's not joules. The following questions are intended to help you understand the connection between…arrow_forwardIt is possible that a muon be captured by a proton to form a muonic atom. A muon is identic to an electron, except when your mass, which is m = 105.7 MeV/c^2. What ia the smallest wave length for a Lyman series for this atom? Give your answer in pm.arrow_forwardThe shortest wavelength of the hydrogen Lyman series is 91.13 nm. Find the three longest wavelengths in this series.arrow_forward
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