College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Chapter 28, Problem 14CQ
To determine
The reason behind ionization energies are explained in terms of atomic structure.
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a) Calculate the excitation energies for the 1s → 3p electron transition for the H-atom
and for the He+-ion. Calculate the energy values in joules.
b) What is the ionization energy (in eV) of H-atom in the 4d-state?
Note: En
=
2n²
Eh, 1Eh
= 27.2114eV =
2625.500kJ/mol = 4.35974394-10-18 J
A hypothetical atom has only two atomic energy levels, separated by 3.2 eV. Suppose that at a certain altitude in the atmosphere of a star there are 6.1 * 1013/cm3 of these atoms in the higher-energy state and 2.5 * 1015/cm3 in the lower-energy state. What is the temperature of the star’s atmosphere at that altitude?
The K series of the discrete spectrum of tungsten contains wavelengths of 0.0185 nm, 0.0209 nm, and 0.0215 nm. The K-shell ionization energy is 69.5 keV. Determine the ionization energies of the L,
M, and N shells.
kev
EL
= 11.83
kev
2.4
Your incorrect answer may have resulted from roundoff error. Make sure you keep extra significant figures in intermediate steps of your calculation. ke
EN
EM
= 10.17
%D
Chapter 28 Solutions
College Physics
Ch. 28.3 - Prob. 28.1QQCh. 28.4 - Prob. 28.2QQCh. 28.5 - Prob. 28.3QQCh. 28 - Prob. 1CQCh. 28 - Prob. 2CQCh. 28 - Prob. 3CQCh. 28 - Prob. 4CQCh. 28 - Prob. 5CQCh. 28 - Prob. 6CQCh. 28 - Prob. 7CQ
Ch. 28 - Prob. 8CQCh. 28 - Prob. 9CQCh. 28 - Prob. 10CQCh. 28 - Prob. 11CQCh. 28 - Prob. 12CQCh. 28 - Prob. 13CQCh. 28 - Prob. 14CQCh. 28 - Prob. 15CQCh. 28 - Prob. 1PCh. 28 - Prob. 2PCh. 28 - Prob. 3PCh. 28 - Prob. 4PCh. 28 - Prob. 5PCh. 28 - Prob. 6PCh. 28 - Prob. 7PCh. 28 - Prob. 8PCh. 28 - Prob. 9PCh. 28 - Prob. 10PCh. 28 - Prob. 11PCh. 28 - Prob. 12PCh. 28 - Prob. 13PCh. 28 - Prob. 14PCh. 28 - Prob. 15PCh. 28 - Prob. 16PCh. 28 - Prob. 17PCh. 28 - Prob. 18PCh. 28 - Prob. 19PCh. 28 - Prob. 20PCh. 28 - Prob. 21PCh. 28 - Prob. 22PCh. 28 - Prob. 23PCh. 28 - Prob. 24PCh. 28 - Prob. 25PCh. 28 - Prob. 26PCh. 28 - Prob. 27PCh. 28 - Prob. 28PCh. 28 - Prob. 29PCh. 28 - Prob. 30PCh. 28 - Prob. 31PCh. 28 - Prob. 32PCh. 28 - Prob. 33PCh. 28 - Prob. 34PCh. 28 - Prob. 35PCh. 28 - Prob. 36PCh. 28 - Prob. 37PCh. 28 - Prob. 38PCh. 28 - Prob. 39PCh. 28 - Prob. 40PCh. 28 - Prob. 41PCh. 28 - Prob. 42PCh. 28 - Prob. 43PCh. 28 - Prob. 44PCh. 28 - Prob. 45PCh. 28 - Prob. 46APCh. 28 - Prob. 47APCh. 28 - Prob. 48APCh. 28 - Prob. 49APCh. 28 - Prob. 50APCh. 28 - Prob. 51APCh. 28 - Prob. 52APCh. 28 - Prob. 53APCh. 28 - Prob. 54AP
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- (a) What is the minimum value of l for a subshell that contains 11 electrons? (b) If this subshell is in the n = 5 shell, what is the spectroscopic notation for this atom?arrow_forwardWhat are the possible values of m for an electron in the n = 4 state?arrow_forwardFor an electron in a hydrogen atom in the n=2 state, compute: (a) the angular momentum; (b) the kinetic energy; (c) the potential energy; and (d) the total energy.arrow_forward
- A photon can excite a hydrogen atom makes a from the n = (2.0000x10^0) state to the n = (8.00x10^0) state, what is the energy of this photon? Give your answer in the unit if eV with 3 s.f. %3D %3D Note: Your answer is assumed to be reduced to the highest power possible. Your Answer:arrow_forwardQ4. Calculate the values of electron and hole concentrations in cm³ at 300 K for intrinsic Ge, Si and GaAs, given: Quantity me/mo m/mo Eg (eV) mo e kB h Ge 0.55 0.31 0.66 9.1×10-³1 kg 1.6×10-¹9 C 1.38×10-23 J/K 1.054×10-34 Js Si 1.10 0.56 1.12 Ge 0.068 0.500 1.43arrow_forwardA doubly ionized lithium atom (Li++) is one that has had two of its three electrons removed. The energy levels of the remaining single-electron ion are closely related to those of the hydrogen atom. The nuclear charge for lithium is +3e instead of just +e. How are the energy levels related to those of hydrogen? How is the radius of the ion in the ground level related to that of the hydrogen atom? Explain.arrow_forward
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