College Physics
2nd Edition
ISBN: 9780134601823
Author: ETKINA, Eugenia, Planinšič, G. (gorazd), Van Heuvelen, Alan
Publisher: Pearson,
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Chapter 28, Problem 16CQ
To determine
The importance of studying atomic models that are not accurate.
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Students have asked these similar questions
what would be the atomic number of an element that would result from beta particle emission from 46 35X?
46 is on top, 35 on bottom.
By READING the N vs t graph shown below, determine No & the half-life.
N (x10¹ atoms)
120
90.
60.
30.
1
2
3 4 5 6 7 8 9 10
t(y)
No =
half-life =
atoms
It is handy to have an equation to quickly determine the number of atoms
left in a radioactive sample as a function of time. For this we can divide
the initial amount by two for every half-life of time, the following equation
does exactly that:
No
No 2 1/2
(21/2)
where Nois the initial number of atoms at t=0, t is time passed and
is the half-life. Use the above equation to help you answer the question
below.
Substance X has a half-life of 10 years, if you start with 1000 grams, how
much will be left after 100 years? (Give your answer in units of grams)
Chapter 28 Solutions
College Physics
Ch. 28 - Prob. 1RQCh. 28 - Prob. 2RQCh. 28 - Prob. 3RQCh. 28 - Prob. 4RQCh. 28 - Prob. 5RQCh. 28 - Prob. 6RQCh. 28 - Prob. 7RQCh. 28 - Prob. 8RQCh. 28 - Prob. 1MCQCh. 28 - Prob. 2MCQ
Ch. 28 - Prob. 3MCQCh. 28 - Prob. 4MCQCh. 28 - Prob. 5MCQCh. 28 - Prob. 6MCQCh. 28 - Prob. 7MCQCh. 28 - Prob. 8MCQCh. 28 - Prob. 9MCQCh. 28 - Prob. 10MCQCh. 28 - Prob. 11MCQCh. 28 - Prob. 12MCQCh. 28 - Prob. 13CQCh. 28 - Prob. 14CQCh. 28 - Prob. 15CQCh. 28 - Prob. 16CQCh. 28 - Prob. 17CQCh. 28 - Prob. 18CQCh. 28 - Prob. 19CQCh. 28 - Prob. 20CQCh. 28 - Prob. 21CQCh. 28 - Prob. 22CQCh. 28 - Prob. 23CQCh. 28 - Prob. 24CQCh. 28 - Prob. 25CQCh. 28 - Prob. 26CQCh. 28 - Prob. 27CQCh. 28 - Prob. 28CQCh. 28 - Prob. 29CQCh. 28 - Prob. 30CQCh. 28 - Prob. 31CQCh. 28 - Prob. 32CQCh. 28 - Prob. 33CQCh. 28 - Prob. 34CQCh. 28 - Prob. 1PCh. 28 - Prob. 2PCh. 28 - Prob. 3PCh. 28 - Prob. 4PCh. 28 - Prob. 5PCh. 28 - Prob. 6PCh. 28 - Prob. 7PCh. 28 - Prob. 8PCh. 28 - Prob. 9PCh. 28 - Prob. 10PCh. 28 - Prob. 11PCh. 28 - Prob. 12PCh. 28 - Prob. 13PCh. 28 - Prob. 14PCh. 28 - Prob. 15PCh. 28 - Prob. 16PCh. 28 - Prob. 17PCh. 28 - Prob. 18PCh. 28 - Prob. 19PCh. 28 - Prob. 20PCh. 28 - Prob. 21PCh. 28 - Prob. 22PCh. 28 - 28.4 Lasers (a) A laser pulse emits 2.0 J of...Ch. 28 - Prob. 24PCh. 28 - Prob. 25PCh. 28 - Prob. 26PCh. 28 - Prob. 27PCh. 28 - Prob. 28PCh. 28 - Prob. 29PCh. 28 - Prob. 30PCh. 28 - Prob. 31PCh. 28 - Prob. 32PCh. 28 - Prob. 33PCh. 28 - Prob. 34PCh. 28 - Prob. 35PCh. 28 - Prob. 36PCh. 28 - Prob. 37PCh. 28 - Prob. 38PCh. 28 - Prob. 39PCh. 28 - Prob. 40PCh. 28 - Prob. 41PCh. 28 - Prob. 42PCh. 28 - Prob. 43PCh. 28 - Prob. 44PCh. 28 - Prob. 45PCh. 28 - Prob. 46PCh. 28 - Prob. 47PCh. 28 - Prob. 48PCh. 28 - Prob. 49PCh. 28 - Prob. 50PCh. 28 - Prob. 51PCh. 28 - Prob. 52PCh. 28 - Prob. 53PCh. 28 - Prob. 54PCh. 28 - Prob. 55PCh. 28 - Prob. 56PCh. 28 - Prob. 57PCh. 28 - Prob. 58PCh. 28 - Prob. 59GPCh. 28 - Prob. 60GPCh. 28 - Prob. 61GPCh. 28 - Prob. 62GPCh. 28 - Prob. 63GPCh. 28 - Prob. 64GPCh. 28 - Prob. 65GPCh. 28 - Prob. 66GPCh. 28 - Prob. 67GPCh. 28 - Prob. 68RPPCh. 28 - Prob. 69RPPCh. 28 - Prob. 70RPPCh. 28 - Prob. 71RPPCh. 28 - Prob. 72RPPCh. 28 - Prob. 73RPPCh. 28 - Prob. 74RPPCh. 28 - Prob. 75RPPCh. 28 - Prob. 76RPPCh. 28 - Prob. 77RPPCh. 28 - Prob. 78RPP
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- The atomic weight of cadmium is 112.41, and its density is 8.65 g/cm3. Using Figure 14.3, estimate the attenuation distance of a thermal neutron beam in cadmium. (The attenuation distance is the distance traveled after which the intensity of the beam is reduced to 1/e of its initial value, where e is the base of the natural logarithms.)arrow_forwardData from the appendices and the periodic table may be needed for these problems. 44. An old camp?re is uncovered during an archaeological dig. Its charcoal is found to contain less than 1/1000 the normal amount of 14C. Estimate the minimum age at the charcoal, noting that 210 = 1024.arrow_forwardSilver has two stable isotopes. The nucleus, 47107Ag , has atomic mass 106.905095 g/mol with an abundance of 51.83% ; whereas 47107Aghas atomic mass 108.904754 g/mol with an abundance of 48.17% . Find the atomic mass of the element silver.arrow_forward
- Enter the correct nuclide symbol in each open tan rectangle in Figure P43.25, which shows the sequences of decays in the natural radioactive series starting with the long-lived isotope uranium-235 and ending with the stable nucleus lead-207. Figure P43.25arrow_forwardChoose the BEST answer to the following. A certain element emits 1 alpha particle, and its products then emit 2 beta particles in succession. The atomic number of the resulting element is changed by (a) zero. (b) minus 1. (c) minus 2. (d) plus 1.arrow_forwardWhen a nucleus decays by emitting an alpha particle, what is the atomic number of the resulting nucleus? What is the resulting atomic mass?arrow_forward
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