Organic Chemistry (6th Edition)
6th Edition
ISBN: 9781260119107
Author: Janice Gorzynski Smith
Publisher: McGraw Hill Education
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Chapter 26, Problem 66P
Interpretation Introduction
Interpretation: The structures of A-C are to be predicted.
Concept introduction: The optically active compounds should not have plane of symmetry and center of symmetry. A point is said to be center of symmetry, if same molecules are present in the opposite direction to each other. If plane passes through the center of the molecule and the molecule is divided into two equal halves, then the molecule is said to have a plane of symmetry.
Kilani-Fischer synthesis results in the formation of two epimers. Two compounds which are neither superimposable nor mirror images to each other and the configuration of one of their stereogenic centers is different are known as epimers.
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A D-aldopentose A is reduced to an optically active alditol. Upon Kiliani–Fischer synthesis, A is converted to two D-aldohexoses, B and C. B is oxidized to an optically inactive aldaric acid. C is oxidized to an optically active aldaric acid. What are the structures of A–C?
A D-aldohexose A is formed from an aldopentose B by the Kiliani-Fischer synthesis. Reduction of
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D-Aldopentose A is oxidized to an optically inactive aldaric acid. On Wohl degradation, A forms an aldotetrose B that is oxidized to an optically active aldaric acid. What are the structures of A and B?
Chapter 26 Solutions
Organic Chemistry (6th Edition)
Ch. 26.2 - Prob. 1PCh. 26.2 - Prob. 2PCh. 26.2 - Label each stereogenic center as R or S. a. b. c....Ch. 26.2 - Convert the ball-and-stick model to a Fischer...Ch. 26.2 - Prob. 5PCh. 26.2 - Prob. 6PCh. 26.3 - Prob. 7PCh. 26.3 - Prob. 8PCh. 26.4 - Prob. 9PCh. 26.4 - Prob. 10P
Ch. 26.6 - Prob. 11PCh. 26.6 - Prob. 12PCh. 26.6 - Prob. 13PCh. 26.6 - Prob. 14PCh. 26.6 - Prob. 15PCh. 26.7 - Prob. 16PCh. 26.7 - Draw a stepwise mechanism for the following...Ch. 26.7 - Prob. 18PCh. 26.8 - Prob. 19PCh. 26.9 - Prob. 20PCh. 26.9 - Prob. 21PCh. 26.9 - Draw the products formed when D-arabinose is...Ch. 26.9 - Prob. 23PCh. 26.10 - Prob. 24PCh. 26.10 - Prob. 25PCh. 26.10 - Prob. 26PCh. 26.10 - Prob. 27PCh. 26.11 - Prob. 28PCh. 26.11 - Prob. 29PCh. 26.12 - Prob. 30PCh. 26.12 - Prob. 31PCh. 26.13 - Prob. 32PCh. 26.13 - Prob. 33PCh. 26.13 - Problem-28.35
Draw the structures of the...Ch. 26.13 - Prob. 35PCh. 26 - 28.37 Convert each ball-and-stick model to a...Ch. 26 - Prob. 37PCh. 26 - Prob. 38PCh. 26 - 28.40 Convert each compound to a Fischer...Ch. 26 - Prob. 40PCh. 26 - Prob. 41PCh. 26 - 28.43 Draw a Haworth projection for each compound...Ch. 26 - Prob. 43PCh. 26 - 28.45 Draw both pyranose anomers of each...Ch. 26 - Prob. 45PCh. 26 - 28.50 Draw the products formed when D-altrose is...Ch. 26 - 28.58 Draw a stepwise mechanism for the following...Ch. 26 - Prob. 62PCh. 26 - Prob. 63PCh. 26 - Prob. 64PCh. 26 - Prob. 65PCh. 26 - Prob. 66PCh. 26 - Prob. 67PCh. 26 - Prob. 68PCh. 26 - Prob. 69PCh. 26 - Prob. 70P
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- Sugar X is known to be a d-aldohexose. On oxidation with HNO3, X gives an optically inactive aldaric acid. WhenX is degraded to an aldopentose, oxidation of the aldopentose gives an optically active aldaric acid. Determine thestructure of Xarrow_forwardAldohexoses A and B are formed from aldopentose C via a Kiliani–Fischer synthesis. Nitric acid oxidizes A to an optically active aldaric acid, B to an optically inactive aldaric acid, and C to an optically active aldaric acid. Wohl degradation of C forms D, which is oxidized by nitric acid to an optically active aldaric acid. Wohl degradation of D forms (+)-glyceraldehyde. Identify A, B, C, and D.arrow_forwardPropose structural formulas for the following polysaccharides. Q.) Alginic acid, isolated from seaweed, is used as a thickening agent in ice cream and other foods. Alginic acid is a polymer of d-mannuronic acid in the pyranose form joined by b-1,4-glycosidic bonds.arrow_forward
- When d-glucose is reduced with sodium borohydride, optically active glucitol results.When optically active d-galactose is reduced, however, the product is optically inactive.Explain this loss of optical activityarrow_forwardIdentify the sugar in each description. a. An aldopentose that is not d-arabinose forms d-arabinitol when it is reduced with NaBH4. b. A sugar that is not D-altrose forms d-altraric acid when it is oxidized with nitric acid. c. A ketose that, when reduced with NaBH4, forms d-altritol and d-allitol.arrow_forwardDraw the structure of: (a) a polysaccharide formed by joining D-mannose units in 1->4-ß-glycosidic linkages; (b) a polysaccharide formed by joining D-glucose units in 1->6-a-glycosidic linkages. The polysaccharide in (b) is dextran, a component of dental plaque.arrow_forward
- Cellobiose, a disaccharide obtained by the hydrolysis of cellulose, is composed of two glucose units joined together in a 1→4-β-glycoside bond. What is the structure of cellobiose?arrow_forwardCarbohydrates a. Compound Z is an aldopentose. If Z is oxidized with nitric acid the product is optically active. If Z undergoes one Ruff degradation and the product of that degradation is reduced to the alditol using H₂/Ni the resulting product is optically inactive. If compound Z undergoes two Ruff degradations, D-glyceraldehyde (shown below) is obtained. Draw the usual Fischer projection of Z (aldehyde at the top). (Hint: work backwards from D- glyceraldehyde.) H HIC OH CH₂OH D-Glyceraldehydearrow_forward
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