Organic Chemistry (6th Edition)
Organic Chemistry (6th Edition)
6th Edition
ISBN: 9781260119107
Author: Janice Gorzynski Smith
Publisher: McGraw Hill Education
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Chapter 26, Problem 63P
Interpretation Introduction

Interpretation: The stepwise mechanism for the isomerization of D-glucose to form the given compounds is to be drawn.

Concept introduction: Carbohydrates are naturally occurring organic compounds. The monosaccharide glucose is called an Aldohexose as it contains six carbon atoms as well as an aldehyde functional group and fructose is known as ketohexose as it contains six carbons with a ketone functional group.

Glucose and mannose are C2 epimers that is they differ in position of hydroxyl group at second carbon atom.

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Draw the two aldohexoses and one ketohexose that can be derived from the enol shownbelow
All are true or false  a)In solution, glucose is in the cyclic acetal form only. b)The driving force for the Wittig reaction is the elimination of triphenylphosphine oxide c)1H NMR spectroscopy, you can tell the difference between an aldehyde and a ketone because an aldehyde has a proton signal between 9–10 ppm. d)When an aldehyde is reacted with excess ethanol with an acid as a catalyst it is called hemiacetal e) You can't use acidic conditions (such as aqueous hydrochloric acid) for the addition of a Grignard reagent to a ketone because the ketone will be protonated and thus unreactive
Draw the hemiketal AND ketal product (include side products):

Chapter 26 Solutions

Organic Chemistry (6th Edition)

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