Algebra 2
1st Edition
ISBN: 9780078884825
Author: McGraw-Hill/Glencoe
Publisher: Glencoe/McGraw-Hill School Pub Co
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Question
Chapter 2.6, Problem 49STP
a.
To determine
Find a regression equation for the data.
a.
Expert Solution
Answer to Problem 49STP
y=0.10x+30.34
Explanation of Solution
Given information:
The table shows the relationship between the total number of male students per school and the number of students who tried out for the football team.
Find a regression equation for the data.
Calculation:
Consider the table showing the relationship between the total number of male students per school and the number of students who tried out for the football team
Number−of−males−studentsNumber−of−Tryouts180462125127462401755138158990
Use the regression capabilities of the graphing utility to find the linear regression line for the data.
The least square regression line is expressed as
y=ax+b
Here a is the slope and b is the intercept.
Press 2nd0 to enter your calculator’s catalog. Scroll until you see diagnosticsOn.
Press ENTER until the calculator screen says “Done”.
Press y STAT key, select 1: EDIT and press ENTER to get a table as shown below
Put the values of 1 x at 3
L1 and y at L2
Press STAT key again, then choose CALC option
Select the LnReg (ax+b) option, Press ENTER to get the regression as shown below
Hence, the required linear regression line is: y=0.10x+30.34
b.
To determine
Determine the
b.
Expert Solution
Answer to Problem 49STP
0.987
Explanation of Solution
Given information:
The table shows the relationship between the total number of male students per school and the number of students who tried out for the football team.
Determine the
Calculation:
Hence, the correlation coefficient is 0.987
c.
To determine
How many students will try out for football at a school with 800 male students?
c.
Expert Solution
Answer to Problem 49STP
110
Explanation of Solution
Given information:
The table shows the relationship between the total number of male students per school and the number of students who tried out for the football team.
Predict how many students will try out for football at a school with 800 male students.
Calculation:
Consider the school with 800 male students
Substitute x=800 in y=0.10x+30.34 therefore,
y=0.10×800+30.34
=110.34
≈110
Hence, the number of students tried out for the football team is 110 .
Chapter 2 Solutions
Algebra 2
Ch. 2.1 - Prob. 1ACYPCh. 2.1 - Prob. 1BCYPCh. 2.1 - Prob. 2CYPCh. 2.1 - Prob. 3CYPCh. 2.1 - Prob. 4ACYPCh. 2.1 - Prob. 4BCYPCh. 2.1 - Prob. 1CYUCh. 2.1 - Prob. 2CYUCh. 2.1 - Prob. 3CYUCh. 2.1 - Prob. 4CYU
Ch. 2.1 - Prob. 5CYUCh. 2.1 - Prob. 6CYUCh. 2.1 - Prob. 7CYUCh. 2.1 - Prob. 8CYUCh. 2.1 - Prob. 9CYUCh. 2.1 - Prob. 10CYUCh. 2.1 - Prob. 11PPSCh. 2.1 - Prob. 12PPSCh. 2.1 - Prob. 13PPSCh. 2.1 - Prob. 14PPSCh. 2.1 - Prob. 15PPSCh. 2.1 - Prob. 16PPSCh. 2.1 - Prob. 17PPSCh. 2.1 - Prob. 18PPSCh. 2.1 - Prob. 19PPSCh. 2.1 - Prob. 20PPSCh. 2.1 - Prob. 21PPSCh. 2.1 - Prob. 22PPSCh. 2.1 - Prob. 23PPSCh. 2.1 - Prob. 24PPSCh. 2.1 - Prob. 25PPSCh. 2.1 - Prob. 26PPSCh. 2.1 - Prob. 27PPSCh. 2.1 - Prob. 28PPSCh. 2.1 - Prob. 29PPSCh. 2.1 - Prob. 30PPSCh. 2.1 - Prob. 31PPSCh. 2.1 - Prob. 32PPSCh. 2.1 - Prob. 33PPSCh. 2.1 - Prob. 34PPSCh. 2.1 - Prob. 35HPCh. 2.1 - Prob. 36HPCh. 2.1 - Prob. 37HPCh. 2.1 - Prob. 38HPCh. 2.1 - Prob. 39HPCh. 2.1 - Prob. 40HPCh. 2.1 - Prob. 41HPCh. 2.1 - Prob. 42HPCh. 2.1 - Prob. 43HPCh. 2.1 - Prob. 44HPCh. 2.1 - Prob. 45STPCh. 2.1 - Prob. 46STPCh. 2.1 - Prob. 47STPCh. 2.1 - Prob. 48STPCh. 2.1 - Prob. 49STPCh. 2.1 - Prob. 50STPCh. 2.1 - Prob. 51STPCh. 2.1 - Prob. 52STPCh. 2.1 - Prob. 53STPCh. 2.1 - Prob. 54STPCh. 2.1 - Prob. 55STPCh. 2.1 - Prob. 56SCh. 2.1 - Prob. 57SCh. 2.1 - Prob. 58SCh. 2.1 - Prob. 59SCh. 2.1 - Prob. 60SCh. 2.1 - Prob. 61SCh. 2.1 - Prob. 62SCh. 2.1 - Prob. 63SCh. 2.1 - Prob. 64SCh. 2.1 - Prob. 1ECh. 2.1 - Prob. 2ECh. 2.1 - Prob. 3ECh. 2.1 - Prob. 4ECh. 2.1 - Prob. 5ECh. 2.2 - Prob. 1ACYPCh. 2.2 - Prob. 1BCYPCh. 2.2 - Prob. 2ACYPCh. 2.2 - Prob. 2BCYPCh. 2.2 - Prob. 3ACYPCh. 2.2 - Prob. 3BCYPCh. 2.2 - Prob. 4CYPCh. 2.2 - Prob. 1CYUCh. 2.2 - Prob. 2CYUCh. 2.2 - Prob. 3CYUCh. 2.2 - Prob. 4CYUCh. 2.2 - Prob. 5CYUCh. 2.2 - Prob. 6CYUCh. 2.2 - Prob. 7CYUCh. 2.2 - Prob. 8CYUCh. 2.2 - Prob. 9CYUCh. 2.2 - Prob. 10CYUCh. 2.2 - Prob. 11CYUCh. 2.2 - Prob. 12CYUCh. 2.2 - Prob. 13CYUCh. 2.2 - Prob. 14CYUCh. 2.2 - Prob. 15CYUCh. 2.2 - Prob. 16PPSCh. 2.2 - Prob. 17PPSCh. 2.2 - Prob. 18PPSCh. 2.2 - Prob. 19PPSCh. 2.2 - Prob. 20PPSCh. 2.2 - Prob. 21PPSCh. 2.2 - Prob. 22PPSCh. 2.2 - Prob. 23PPSCh. 2.2 - Prob. 24PPSCh. 2.2 - Prob. 25PPSCh. 2.2 - Prob. 26PPSCh. 2.2 - 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Prob. 76SCh. 2.2 - Prob. 1ECh. 2.2 - Prob. 2ECh. 2.2 - Prob. 3ECh. 2.2 - Prob. 4ECh. 2.2 - Prob. 5ECh. 2.2 - Prob. 6ECh. 2.3 - Prob. 1CYPCh. 2.3 - Prob. 2CYPCh. 2.3 - Prob. 3ACYPCh. 2.3 - Prob. 3BCYPCh. 2.3 - Prob. 4ACYPCh. 2.3 - Prob. 4BCYPCh. 2.3 - Prob. 1CYUCh. 2.3 - Prob. 2CYUCh. 2.3 - Prob. 3CYUCh. 2.3 - Prob. 4CYUCh. 2.3 - Prob. 5CYUCh. 2.3 - Prob. 6CYUCh. 2.3 - Prob. 7CYUCh. 2.3 - Prob. 8CYUCh. 2.3 - Prob. 9PPSCh. 2.3 - Prob. 10PPSCh. 2.3 - Prob. 11PPSCh. 2.3 - Prob. 12PPSCh. 2.3 - Prob. 13PPSCh. 2.3 - Prob. 14PPSCh. 2.3 - Prob. 15PPSCh. 2.3 - Prob. 16PPSCh. 2.3 - Prob. 17PPSCh. 2.3 - Prob. 18PPSCh. 2.3 - Prob. 19PPSCh. 2.3 - Prob. 20PPSCh. 2.3 - Prob. 21PPSCh. 2.3 - Prob. 22PPSCh. 2.3 - Prob. 23PPSCh. 2.3 - Prob. 24PPSCh. 2.3 - Prob. 25PPSCh. 2.3 - Prob. 26PPSCh. 2.3 - Prob. 27PPSCh. 2.3 - Prob. 28PPSCh. 2.3 - Prob. 29PPSCh. 2.3 - Prob. 30PPSCh. 2.3 - Prob. 31PPSCh. 2.3 - Prob. 32PPSCh. 2.3 - Prob. 33PPSCh. 2.3 - Prob. 34PPSCh. 2.3 - Prob. 35PPSCh. 2.3 - Prob. 36HPCh. 2.3 - Prob. 37HPCh. 2.3 - 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Prob. 5PPSCh. 2.5 - Prob. 6PPSCh. 2.5 - Prob. 7PPSCh. 2.5 - Prob. 8PPSCh. 2.5 - Prob. 9PPSCh. 2.5 - Prob. 10PPSCh. 2.5 - Prob. 11PPSCh. 2.5 - Prob. 12HPCh. 2.5 - Prob. 13HPCh. 2.5 - Prob. 14HPCh. 2.5 - Prob. 15HPCh. 2.5 - Prob. 16HPCh. 2.5 - Prob. 17HPCh. 2.5 - Prob. 18HPCh. 2.5 - Prob. 19HPCh. 2.5 - Prob. 20HPCh. 2.5 - Prob. 21STPCh. 2.5 - Prob. 22STPCh. 2.5 - Prob. 23STPCh. 2.5 - Prob. 24STPCh. 2.5 - Prob. 25STPCh. 2.5 - Prob. 26STPCh. 2.5 - Prob. 27STPCh. 2.5 - Prob. 28STPCh. 2.5 - Prob. 29STPCh. 2.5 - Prob. 30SCh. 2.5 - Prob. 31SCh. 2.5 - Prob. 32SCh. 2.5 - Prob. 1ECh. 2.5 - Prob. 2ECh. 2.5 - Prob. 3ECh. 2.5 - Prob. 4ECh. 2.6 - Prob. 1CYPCh. 2.6 - Prob. 2ACYPCh. 2.6 - Prob. 2BCYPCh. 2.6 - Prob. 3CYPCh. 2.6 - Prob. 4ACYPCh. 2.6 - Prob. 4BCYPCh. 2.6 - Prob. 1CYUCh. 2.6 - Prob. 2CYUCh. 2.6 - Prob. 3CYUCh. 2.6 - Prob. 4CYUCh. 2.6 - Prob. 5CYUCh. 2.6 - Prob. 6CYUCh. 2.6 - Prob. 7CYUCh. 2.6 - Prob. 8CYUCh. 2.6 - Prob. 9CYUCh. 2.6 - Prob. 10CYUCh. 2.6 - Prob. 11CYUCh. 2.6 - Prob. 12PPSCh. 2.6 - 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Prob. 2ACYPCh. 2.7 - Prob. 2BCYPCh. 2.7 - Prob. 3ACYPCh. 2.7 - Prob. 3BCYPCh. 2.7 - Prob. 4ACYPCh. 2.7 - Prob. 4BCYPCh. 2.7 - Prob. 5CYPCh. 2.7 - Prob. 1CYUCh. 2.7 - Prob. 2CYUCh. 2.7 - Prob. 3CYUCh. 2.7 - Prob. 4CYUCh. 2.7 - Prob. 5CYUCh. 2.7 - Prob. 6CYUCh. 2.7 - Prob. 7CYUCh. 2.7 - Prob. 8CYUCh. 2.7 - Prob. 9CYUCh. 2.7 - Prob. 10PPSCh. 2.7 - Prob. 11PPSCh. 2.7 - Prob. 12PPSCh. 2.7 - Prob. 13PPSCh. 2.7 - Prob. 14PPSCh. 2.7 - Prob. 15PPSCh. 2.7 - Prob. 16PPSCh. 2.7 - Prob. 17PPSCh. 2.7 - Prob. 18PPSCh. 2.7 - Prob. 19PPSCh. 2.7 - Prob. 20PPSCh. 2.7 - Prob. 21PPSCh. 2.7 - Prob. 22PPSCh. 2.7 - Prob. 23PPSCh. 2.7 - Prob. 24PPSCh. 2.7 - Prob. 25PPSCh. 2.7 - Prob. 26PPSCh. 2.7 - Prob. 27PPSCh. 2.7 - Prob. 28PPSCh. 2.7 - Prob. 29PPSCh. 2.7 - Prob. 30PPSCh. 2.7 - Prob. 31PPSCh. 2.7 - Prob. 32PPSCh. 2.7 - Prob. 33PPSCh. 2.7 - Prob. 34PPSCh. 2.7 - Prob. 35PPSCh. 2.7 - Prob. 36PPSCh. 2.7 - Prob. 37PPSCh. 2.7 - Prob. 38PPSCh. 2.7 - Prob. 39PPSCh. 2.7 - Prob. 40PPSCh. 2.7 - Prob. 41PPSCh. 2.7 - Prob. 42PPSCh. 2.7 - 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Prob. 29SGRCh. 2 - Prob. 30SGRCh. 2 - Prob. 31SGRCh. 2 - Prob. 32SGRCh. 2 - Prob. 33SGRCh. 2 - Prob. 34SGRCh. 2 - Prob. 35SGRCh. 2 - Prob. 36SGRCh. 2 - Prob. 37SGRCh. 2 - Prob. 38SGRCh. 2 - Prob. 39SGRCh. 2 - Prob. 40SGRCh. 2 - Prob. 41SGRCh. 2 - Prob. 42SGRCh. 2 - Prob. 43SGRCh. 2 - Prob. 44SGRCh. 2 - Prob. 45SGRCh. 2 - Prob. 46SGRCh. 2 - Prob. 47SGRCh. 2 - Prob. 48SGRCh. 2 - Prob. 49SGRCh. 2 - Prob. 50SGRCh. 2 - Prob. 51SGRCh. 2 - Prob. 52SGRCh. 2 - Prob. 53SGRCh. 2 - Prob. 54SGRCh. 2 - Prob. 55SGRCh. 2 - Prob. 56SGRCh. 2 - Prob. 57SGRCh. 2 - Prob. 58SGRCh. 2 - Prob. 59SGRCh. 2 - Prob. 60SGRCh. 2 - Prob. 61SGRCh. 2 - Prob. 62SGRCh. 2 - Prob. 1PTCh. 2 - Prob. 2PTCh. 2 - Prob. 3PTCh. 2 - Prob. 4PTCh. 2 - Prob. 5PTCh. 2 - Prob. 6PTCh. 2 - Prob. 7PTCh. 2 - Prob. 8PTCh. 2 - Prob. 9PTCh. 2 - Prob. 10PTCh. 2 - Prob. 11PTCh. 2 - Prob. 12PTCh. 2 - Prob. 13PTCh. 2 - Prob. 14PTCh. 2 - Prob. 15PTCh. 2 - Prob. 16PTCh. 2 - Prob. 17PTCh. 2 - Prob. 18PTCh. 2 - Prob. 19PTCh. 2 - Prob. 20PTCh. 2 - Prob. 1ECh. 2 - 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- Use the graph of y = f(x) to answer the following. 3- 2 -4 -2 -1 1 2 3 4 -1 2 m -3- + (d) Find all x for which f(x) = -2. If there is more than one value, separate them with commas or write your answer in interval notation, if necessary. Select "None", if applicable. Value(s) of x for which f(x)=-2: | (0,0) (0,0) (0,0) (0,0) 0,0... -00 None (h) Determine the range of f. The range is (0,0) Garrow_forwardWhat is g(f(4))arrow_forward10) Multiply (8m + 3)² A) 8m²+11m+6 B) m² + 48m+9 C) 64m²+48m+9 D) 16m²+11m+6arrow_forward
- Let R be field and X= R³/s Vector space over R M=(a,b,c)labic, e Rra+b= 3- <3 Show that Ms and why with proof. 1) is convexset and affine set of botost ii) is blanced set and symmetirs set of x iii) is hy per space and hyper plane ofx or hot iii) find f:MR st kerf = M 18/103 and finnd fiM→R/{0} st M= {xEX, f(t) = x, texiαER? jiii) show that Mis Maxsubspace or not and Mis a max. affine set or not.arrow_forwardFind The partial fraction decomposition for each The following 2× B) (x+3) a 3 6 X-3x+2x-6arrow_forward1) Find the partial feraction decomposition for each of 5- X 2 2x+x-1 The following: 3 B) 3 X + 3xarrow_forward
- Kate, Luke, Mary and Nancy are sharing a cake. The cake had previously been divided into four slices (s1, s2, s3 and s4). The following table shows the values of the slices in the eyes of each player. What is fair share to nancy? S1 S2 S3 S4 Kate $4.00 $6.00 $6.00 $4.00 Luke $5.30 $5.00 $5.25 $5.45 Mary $4.25 $4.50 $3.50 $3.75 Nancy $6.00 $4.00 $4.00 $6.00arrow_forwardKate, Luke, Mary and Nancy are sharing a cake. The cake had previously been divided into four slices (s1, s2, s3 and s4). The following table shows the values of the slices in the eyes of each player. S1 S2 S3 S4 Kate $4.00 $6.00 $6.00 $4.00 Luke $5.30 $5.00 $5.25 $5.45 Mary $4.25 $4.50 $3.50 $3.75 Nancy $6.00 $4.00 $4.00 $6.00 how much is the cak worth to maryarrow_forwardKate, Luke, Mary and Nancy are sharing a cake. The cake had previously been divided into four slices (s1, s2, s3 and s4). The following table shows the values of the slices in the eyes of each player. What is the threshold of fair share for Luke? S1 S2 S3 S4 Kate $4.00 $6.00 $6.00 $4.00 Luke $5.30 $5.00 $5.25 $5.45 Mary $4.25 $4.50 $3.50 $3.75 Nancy $6.00 $4.00 $4.00 $6.00arrow_forward
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