Algebra 2
Algebra 2
1st Edition
ISBN: 9780078884825
Author: McGraw-Hill/Glencoe
Publisher: Glencoe/McGraw-Hill School Pub Co
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Concept explainers

Family of Curves
A family of curves is a group of curves that are each described by a parametrization in which one or more variables are parameters. In general, the parameters have more complexity on the assembly of the curve than an ordinary linear transformation. These…
XZ Plane
In order to understand XZ plane, it's helpful to understand two-dimensional and three-dimensional spaces. To plot a point on a plane, two numbers are needed, and these two numbers in the plane can be represented as an ordered pair (a,b) where a and b are…
Euclidean Geometry
Geometry is the branch of mathematics that deals with flat surfaces like lines, angles, points, two-dimensional figures, etc. In Euclidean geometry, one studies the geometrical shapes that rely on different theorems and axioms. This (pure mathematics) ge…
Lines and Angles
In a two-dimensional plane, a line is simply a figure that joins two points. Usually, lines are used for presenting objects that are straight in shape and have minimal depth or width.
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Chapter 2.4, Problem 34PPS

(a)

To determine

To write: The equation y=55(23−x) in slope intercepts form.

(a)

Expert Solution
Check Mark

Answer to Problem 34PPS

The equation y=55(23−x) in slope intercepts form is y=−55x+1265 .

Explanation of Solution

Given:

The equation is y=55(23−x) .

Calculation:

Write the equation is slope intercept form as follows.

  y=55(23−x)=55⋅23−55x=1265−55x=−55x+1265

Therefore, the equation y=55(23−x) in slope intercepts form is y=−55x+1265 .

(b)

To determine

To find: The slope and y intercepts.

(b)

Expert Solution
Check Mark

Answer to Problem 34PPS

The slope and y intercepts are −55 and 1265 respectively.

Explanation of Solution

Given:

The equation is y=−55x+1265 .

Calculation:

Compare the equation y=−55x+1265 with y=mx+b .

The slope and y intercepts are as follows.

  m=−55b=1265

Therefore, the slope and y intercepts are −55 and 1265 respectively.

(c)

To determine

To find: The number of words that you have left to type after 20 minutes.

(c)

Expert Solution
Check Mark

Answer to Problem 34PPS

The number of words that you have left to type after 20 minutes are 165.

Explanation of Solution

Given:

The equation is y=−55x+1265 .

Calculation:

Substitute 20 for x in the equation y=−55x+1265 .

  y=−55(20)+1265=−1100+1265=165

Therefore, the number of words that you have left to type after 20 minutes are 165.

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Chapter 2.4, Problem 33PPS
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Chapter 2.4, Problem 35PPS

Chapter 2 Solutions

Algebra 2

Ch. 2.1 - Prob. 1ACYPCh. 2.1 - Prob. 1BCYPCh. 2.1 - Prob. 2CYPCh. 2.1 - Prob. 3CYPCh. 2.1 - Prob. 4ACYPCh. 2.1 - Prob. 4BCYPCh. 2.1 - Prob. 1CYUCh. 2.1 - Prob. 2CYUCh. 2.1 - Prob. 3CYUCh. 2.1 - Prob. 4CYU
Ch. 2.1 - Prob. 5CYUCh. 2.1 - Prob. 6CYUCh. 2.1 - Prob. 7CYUCh. 2.1 - Prob. 8CYUCh. 2.1 - Prob. 9CYUCh. 2.1 - Prob. 10CYUCh. 2.1 - Prob. 11PPSCh. 2.1 - Prob. 12PPSCh. 2.1 - Prob. 13PPSCh. 2.1 - Prob. 14PPSCh. 2.1 - Prob. 15PPSCh. 2.1 - Prob. 16PPSCh. 2.1 - Prob. 17PPSCh. 2.1 - Prob. 18PPSCh. 2.1 - Prob. 19PPSCh. 2.1 - Prob. 20PPSCh. 2.1 - Prob. 21PPSCh. 2.1 - Prob. 22PPSCh. 2.1 - Prob. 23PPSCh. 2.1 - Prob. 24PPSCh. 2.1 - Prob. 25PPSCh. 2.1 - Prob. 26PPSCh. 2.1 - Prob. 27PPSCh. 2.1 - Prob. 28PPSCh. 2.1 - Prob. 29PPSCh. 2.1 - Prob. 30PPSCh. 2.1 - Prob. 31PPSCh. 2.1 - Prob. 32PPSCh. 2.1 - Prob. 33PPSCh. 2.1 - Prob. 34PPSCh. 2.1 - Prob. 35HPCh. 2.1 - Prob. 36HPCh. 2.1 - Prob. 37HPCh. 2.1 - Prob. 38HPCh. 2.1 - Prob. 39HPCh. 2.1 - Prob. 40HPCh. 2.1 - Prob. 41HPCh. 2.1 - Prob. 42HPCh. 2.1 - Prob. 43HPCh. 2.1 - Prob. 44HPCh. 2.1 - Prob. 45STPCh. 2.1 - Prob. 46STPCh. 2.1 - Prob. 47STPCh. 2.1 - Prob. 48STPCh. 2.1 - Prob. 49STPCh. 2.1 - Prob. 50STPCh. 2.1 - Prob. 51STPCh. 2.1 - Prob. 52STPCh. 2.1 - 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Prob. 76SCh. 2.2 - Prob. 1ECh. 2.2 - Prob. 2ECh. 2.2 - Prob. 3ECh. 2.2 - Prob. 4ECh. 2.2 - Prob. 5ECh. 2.2 - Prob. 6ECh. 2.3 - Prob. 1CYPCh. 2.3 - Prob. 2CYPCh. 2.3 - Prob. 3ACYPCh. 2.3 - Prob. 3BCYPCh. 2.3 - Prob. 4ACYPCh. 2.3 - Prob. 4BCYPCh. 2.3 - Prob. 1CYUCh. 2.3 - Prob. 2CYUCh. 2.3 - Prob. 3CYUCh. 2.3 - Prob. 4CYUCh. 2.3 - Prob. 5CYUCh. 2.3 - Prob. 6CYUCh. 2.3 - Prob. 7CYUCh. 2.3 - Prob. 8CYUCh. 2.3 - Prob. 9PPSCh. 2.3 - Prob. 10PPSCh. 2.3 - Prob. 11PPSCh. 2.3 - Prob. 12PPSCh. 2.3 - Prob. 13PPSCh. 2.3 - Prob. 14PPSCh. 2.3 - Prob. 15PPSCh. 2.3 - Prob. 16PPSCh. 2.3 - Prob. 17PPSCh. 2.3 - Prob. 18PPSCh. 2.3 - Prob. 19PPSCh. 2.3 - Prob. 20PPSCh. 2.3 - Prob. 21PPSCh. 2.3 - Prob. 22PPSCh. 2.3 - Prob. 23PPSCh. 2.3 - Prob. 24PPSCh. 2.3 - Prob. 25PPSCh. 2.3 - Prob. 26PPSCh. 2.3 - Prob. 27PPSCh. 2.3 - Prob. 28PPSCh. 2.3 - Prob. 29PPSCh. 2.3 - Prob. 30PPSCh. 2.3 - Prob. 31PPSCh. 2.3 - Prob. 32PPSCh. 2.3 - Prob. 33PPSCh. 2.3 - Prob. 34PPSCh. 2.3 - Prob. 35PPSCh. 2.3 - Prob. 36HPCh. 2.3 - Prob. 37HPCh. 2.3 - 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Prob. 5PPSCh. 2.5 - Prob. 6PPSCh. 2.5 - Prob. 7PPSCh. 2.5 - Prob. 8PPSCh. 2.5 - Prob. 9PPSCh. 2.5 - Prob. 10PPSCh. 2.5 - Prob. 11PPSCh. 2.5 - Prob. 12HPCh. 2.5 - Prob. 13HPCh. 2.5 - Prob. 14HPCh. 2.5 - Prob. 15HPCh. 2.5 - Prob. 16HPCh. 2.5 - Prob. 17HPCh. 2.5 - Prob. 18HPCh. 2.5 - Prob. 19HPCh. 2.5 - Prob. 20HPCh. 2.5 - Prob. 21STPCh. 2.5 - Prob. 22STPCh. 2.5 - Prob. 23STPCh. 2.5 - Prob. 24STPCh. 2.5 - Prob. 25STPCh. 2.5 - Prob. 26STPCh. 2.5 - Prob. 27STPCh. 2.5 - Prob. 28STPCh. 2.5 - Prob. 29STPCh. 2.5 - Prob. 30SCh. 2.5 - Prob. 31SCh. 2.5 - Prob. 32SCh. 2.5 - Prob. 1ECh. 2.5 - Prob. 2ECh. 2.5 - Prob. 3ECh. 2.5 - Prob. 4ECh. 2.6 - Prob. 1CYPCh. 2.6 - Prob. 2ACYPCh. 2.6 - Prob. 2BCYPCh. 2.6 - Prob. 3CYPCh. 2.6 - Prob. 4ACYPCh. 2.6 - Prob. 4BCYPCh. 2.6 - Prob. 1CYUCh. 2.6 - Prob. 2CYUCh. 2.6 - Prob. 3CYUCh. 2.6 - Prob. 4CYUCh. 2.6 - Prob. 5CYUCh. 2.6 - Prob. 6CYUCh. 2.6 - Prob. 7CYUCh. 2.6 - Prob. 8CYUCh. 2.6 - Prob. 9CYUCh. 2.6 - Prob. 10CYUCh. 2.6 - Prob. 11CYUCh. 2.6 - Prob. 12PPSCh. 2.6 - 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Prob. 2ACYPCh. 2.7 - Prob. 2BCYPCh. 2.7 - Prob. 3ACYPCh. 2.7 - Prob. 3BCYPCh. 2.7 - Prob. 4ACYPCh. 2.7 - Prob. 4BCYPCh. 2.7 - Prob. 5CYPCh. 2.7 - Prob. 1CYUCh. 2.7 - Prob. 2CYUCh. 2.7 - Prob. 3CYUCh. 2.7 - Prob. 4CYUCh. 2.7 - Prob. 5CYUCh. 2.7 - Prob. 6CYUCh. 2.7 - Prob. 7CYUCh. 2.7 - Prob. 8CYUCh. 2.7 - Prob. 9CYUCh. 2.7 - Prob. 10PPSCh. 2.7 - Prob. 11PPSCh. 2.7 - Prob. 12PPSCh. 2.7 - Prob. 13PPSCh. 2.7 - Prob. 14PPSCh. 2.7 - Prob. 15PPSCh. 2.7 - Prob. 16PPSCh. 2.7 - Prob. 17PPSCh. 2.7 - Prob. 18PPSCh. 2.7 - Prob. 19PPSCh. 2.7 - Prob. 20PPSCh. 2.7 - Prob. 21PPSCh. 2.7 - Prob. 22PPSCh. 2.7 - Prob. 23PPSCh. 2.7 - Prob. 24PPSCh. 2.7 - Prob. 25PPSCh. 2.7 - Prob. 26PPSCh. 2.7 - Prob. 27PPSCh. 2.7 - Prob. 28PPSCh. 2.7 - Prob. 29PPSCh. 2.7 - Prob. 30PPSCh. 2.7 - Prob. 31PPSCh. 2.7 - Prob. 32PPSCh. 2.7 - Prob. 33PPSCh. 2.7 - Prob. 34PPSCh. 2.7 - Prob. 35PPSCh. 2.7 - Prob. 36PPSCh. 2.7 - Prob. 37PPSCh. 2.7 - Prob. 38PPSCh. 2.7 - Prob. 39PPSCh. 2.7 - Prob. 40PPSCh. 2.7 - Prob. 41PPSCh. 2.7 - Prob. 42PPSCh. 2.7 - 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Prob. 16QCCh. 2 - Prob. 1MCQCh. 2 - Prob. 2MCQCh. 2 - Prob. 3MCQCh. 2 - Prob. 4MCQCh. 2 - Prob. 5MCQCh. 2 - Prob. 6MCQCh. 2 - Prob. 7MCQCh. 2 - Prob. 8MCQCh. 2 - Prob. 9MCQCh. 2 - Prob. 10MCQCh. 2 - Prob. 11MCQCh. 2 - Prob. 12MCQCh. 2 - Prob. 13MCQCh. 2 - Prob. 14MCQCh. 2 - Prob. 15MCQCh. 2 - Prob. 16MCQCh. 2 - Prob. 17MCQCh. 2 - Prob. 18MCQCh. 2 - Prob. 19MCQCh. 2 - Prob. 20MCQCh. 2 - Prob. 21MCQCh. 2 - Prob. 22MCQCh. 2 - Prob. 23MCQCh. 2 - Prob. 24MCQCh. 2 - Prob. 25MCQCh. 2 - Prob. 1SGRCh. 2 - Prob. 2SGRCh. 2 - Prob. 3SGRCh. 2 - Prob. 4SGRCh. 2 - Prob. 5SGRCh. 2 - Prob. 6SGRCh. 2 - Prob. 7SGRCh. 2 - Prob. 8SGRCh. 2 - Prob. 9SGRCh. 2 - Prob. 10SGRCh. 2 - Prob. 11SGRCh. 2 - Prob. 12SGRCh. 2 - Prob. 13SGRCh. 2 - Prob. 14SGRCh. 2 - Prob. 15SGRCh. 2 - Prob. 16SGRCh. 2 - Prob. 17SGRCh. 2 - Prob. 18SGRCh. 2 - Prob. 19SGRCh. 2 - Prob. 20SGRCh. 2 - Prob. 21SGRCh. 2 - Prob. 22SGRCh. 2 - Prob. 23SGRCh. 2 - Prob. 24SGRCh. 2 - Prob. 25SGRCh. 2 - Prob. 26SGRCh. 2 - Prob. 27SGRCh. 2 - Prob. 28SGRCh. 2 - 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Prob. 2ECh. 2 - Prob. 1STPCh. 2 - Prob. 2STPCh. 2 - Prob. 3STPCh. 2 - Prob. 4STPCh. 2 - Prob. 5STPCh. 2 - Prob. 6STPCh. 2 - Prob. 7STPCh. 2 - Prob. 8STPCh. 2 - Prob. 9STPCh. 2 - Prob. 10STPCh. 2 - Prob. 11STPCh. 2 - Prob. 12STP

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