Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN: 9780133923605
Author: Robert L. Boylestad
Publisher: PEARSON
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Chapter 26, Problem 21P

Find the nonsinusoidal expression for the voltage oe of the diagram in Fig. 26.39.

v 1 = 20 - 200sin 600t + 100cos 1200t + 75sin 1800t

v 2 = 10 + 150sin (600t + 30 o ) +50sin (1800t + 60 )

Chapter 26, Problem 21P, Find the nonsinusoidal expression for the voltage oe of the diagram in Fig. 26.39.

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I need help creating a graph in Excel for the tables below. It needs to be Vce vs Ic and plots the Ib average for each table. The averages are below. Please show step by step.  V1 = 4V V2 (V) Ib (µA) Ic (mA) Ie (mA) Vce (mV) Beta 0 11.5 -0.00794 -0.00356 7.94 -0.000690434783 1 11.1 0.701 -0.712 299 0.0631531532 2 11.1 0.711 -0.722 1290 0.0640540541 Table 1: V1 = 4, V2= 0-2 V   V1 = 6V V2 (V) Ib (µA) Ic (mA) Ie (mA) Vce (mV) Beta 0 18.1 -0.0105 -0.00761 10.5 -0.000580110497 1 17.8 0.856 -0.874 144 0.0480898876 2 17.8 1.20 -1.22 797 0.0674157303 3 17.8 1.22 -1.25 1780 0.0685393258 Table 2: V1 = 6, V2= 0-3 V   V1 = 8V V2 (V) Ib (µA) Ic (mA) Ie (mA) Vce (mV) Beta 0 24.7 -0.0123 -0.0125 12.3 -0.000497975709 1 24.5 0.878 -0.903 122 0.0358367347 2 24.4 1.71 -1.73 291 0.0700819672 4 24.4…
A voltage wave of 250 kHz has a Vmax-5 V and Vmin=-35 V. The duty cycle of this wave is 0.875. This voltage waveform has been applied across a 2.5 µH inductor for a very long time so that steady state has been achieved. Diagrams of the wave parameters and circuit are shown in this figure: L What is the average voltage of this wave? Average voltage = 35 V Voltage (arb, unit) 1.25 Minimum current: -3.5€ Amps 1 0.75 0.5 0.25 0 4.25 05 Have you integrated the wave over full cycle? 4.75 4 -1.25 Vmax 0.5 Vmin What is the average current flowing through the inductor? Average current = 3.56 A 15 Period/s On average, there is no power consumed by the inductor. Have you considered this? What are the maximum and minimum currents that flow through the inductor? Maximum current: 0.50 Amps D= 25 TH TH Have you used the relationship for current and voltage in an inductor? Have you considered the slope of the current wave?
Solve for Beta : www m Vcc= 12V VCE= 6V RB= 470 Kiloohms Rc= 1500 ohms RE= 1000 ohms
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