Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN: 9780133923605
Author: Robert L. Boylestad
Publisher: PEARSON
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Textbook Question
Chapter 26, Problem 10P
Find the rms value of the following nonsinusoidal waves:
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Students have asked these similar questions
What is the phase relationship between the following waveforms?
v = 10 V sin(@t + 60°)
i= 2 mA sin(@t – 15°)
-
2. Draw the phasor and wave diagram of the following sinusoidal current:
Ii leads l2 by 35°, l4 leads l3 by 45°, Is lags l2 by 35°, l3 lags I, by 20°. Use l2 as reference.
Average values of current are all equal to 40 A.
Problem 3
Compute the average and rms voltage of the waveform shown in the figure below.
6V -
t
4 ms
4 ms
4 ms
4 ms
-3 V
Chapter 26 Solutions
Introductory Circuit Analysis (13th Edition)
Ch. 26 - For the waveforms in Fig. 26.32, determine whether...Ch. 26 - If the Fourier series for the waveform in Fig....Ch. 26 - Prob. 3PCh. 26 - Sketch the following nonsinusoidal waveforms with ...Ch. 26 - Sketch the following nonsinusoidal waveforms with...Ch. 26 - Sketch the Fourier spectrum for the waveforms of...Ch. 26 - Sketch the Fourier spectrum for the waveform of...Ch. 26 - Sketch the Fourier spectrum for the waveform of...Ch. 26 - Find the average and effective values of the...Ch. 26 - Find the rms value of the following nonsinusoidal...
Ch. 26 - Find the total average power to a circuit whose...Ch. 26 - Prob. 12PCh. 26 - The Fourier series representation for the input...Ch. 26 - Prob. 14PCh. 26 - Prob. 15PCh. 26 - Prob. 16PCh. 26 - The input voltage in Fig. 26.36(a) to the circuit...Ch. 26 - Find the Fourier series expression for the voltage...Ch. 26 - Perform the indicated operations on the following...Ch. 26 - Prob. 20PCh. 26 - Find the nonsinusoidal expression for the voltage...Ch. 26 - Plot a half-rectified waveform with a peak value...
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- Segments of two sinusoids are shown in the plot below. Determine the phase difference between the two waveforms. Amplitude 0.5 0 -0.5 0 O 900° 00° 090° 0.5 1 Time (seconds) 1.5arrow_forwardP.4: Find the rms value for the following sinusoidal waveforms a. v = 20 sin 754t b. v = 7.07 sin 377t c. i = 0.006 sin(400t + 20°) d. i 16 x 10-3 sin(377t - 10°)arrow_forwardSegments of two sinusoids are shown in the plot below. Determine the phase difference between the two waveforms. Amplitude 0 2 -2 -4 0 180° 90 ° Oo° 0.5 Time (seconds) 1 1arrow_forward
- coil of watt meter is connected in series.arrow_forwardD Question 6 For the sine wave shown below determine the RMS voltage. The Horizontal scale "time base" is 5ms/div, the Vertical scale is 9Volt/div. (Volt) +V Time (s) -V RMS voltage = ( Vacarrow_forwardDIRECTIONS: Draw the following sinusoidal waveforms: 1. e= 220sin(ωt -500) 2. i = -30 cos (ωt + π/4) 3. e = 220 sin(- 400) and i = 30 cos(ωt +600)arrow_forward
- P.3: Find the rms value for the following sinusoidal waveforms a. v= 120 sin(377t + 60°) b. i=6x 10³ sin(2# 1000r) c. u=8 x 10-6 sin(2# 5000 + 30°) P.4: Find the rms value for the following sinusoidal waveforms a. v= 20 sin 754r b. v= 7.07 sin 377r c. i=0.006 sin(400r + 20°) d. i 16 x 10³ sin(377r - 10%) P.5: Write the sinusoidal expressions for voltages and currents having the following rms values at a frequency of 60 Hz with zero phase shifts: a. 4.8 V b. 50 mA c. 2 kVarrow_forwardTwo sinusoidal waveforms are represented by equations as follows: X= sinwt y= sinwt+60° Which of the following statement is correct? O y lags x by 60° O x lags y by 60° x and y are in phase O y leads x by 60°arrow_forwardProblem 54: Express the following phasor currents and voltages as sine waves for f = 60 Hz. Notice that all these phasors are given in rms. a. I= 40 A Z20° b. V = 120 V Z10° c. I= 8 x 10-³AZ – 110° d. V = 6000 VZ– 180°arrow_forward
- For the given waveforms, waveform D • Ithe waveform E. lags leads D Degrees 30 60 90 180 210 360 540 720/ Marrow_forwardThe 12V 50 Hz source has what RMS value?arrow_forwardConvert the following phasors into sinusoidal waveforms a. Vi = 20+j15 V, w= 10 rad/s b. V1 = 6(8-j3) V, w= 20K rad/s c. I1 = 12-j5+4/j A, w= 3K rad/s d. I 330+j810 mA, w= 50 rad/s 2200-j560arrow_forward
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