DeGarmo's Materials and Processes in Manufacturing
12th Edition
ISBN: 9781118987674
Author: J. T. Black, Ronald A. Kohser
Publisher: WILEY
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Chapter 25, Problem 6P
To determine
The approximate equation 25.5 obtained for MRR in drilling and the assumptions needed.
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Drilling, diameter = 0.375 inches, feed is 0.003 inches/tooth, number of teeth is 2,
rotation speed is 750 rev/min. Material is tough Copper alloy.
Find: MRR, power at the motor, power at the tool, and torque at the tool. Work
the problem in U.S. units and give the answers in U.S. units.
A 0.4-inch diameter bit is used in a vertical or vertical drill that operates at 300 rpm. If the feed is 0.005 in / rev, what is the MRR? What is the MRR if the drill diameter is doubled? What is the power required in the drill if the material is an annealed AISI 1080?
Why is speed important in a drilling operation?
What are the results of a drill bit with unequal lips?
Chapter 25 Solutions
DeGarmo's Materials and Processes in Manufacturing
Ch. 25 - What functions are performed by the flutes on a...Ch. 25 - What determines the rake angle of a drill? See...Ch. 25 - Basically, what determines what helix angle a...Ch. 25 - When a large-diameter hole is to be drilled, why...Ch. 25 - Equation 25.4 for the MRR for drilling can be...Ch. 25 - Are the recommended surface speeds for spade...Ch. 25 - What can happen when an improperly ground drill is...Ch. 25 - Why are many drilled holes oversize with respect...Ch. 25 - What are the two primary functions of a...Ch. 25 - What is the function of the margins on a twist...
Ch. 25 - What factors tend to cause a drill to drift off...Ch. 25 - The drill shown in Figure 25.13 has coolant...Ch. 25 - Prob. 13RQCh. 25 - Why do cutting fluids for drilling usually have...Ch. 25 - How does a gang-drilling machine differ from a...Ch. 25 - Prob. 16RQCh. 25 - How does the thrust force vary with feed? Why?Ch. 25 - Holding the workpiece by hand when drilling is not...Ch. 25 - Prob. 19RQCh. 25 - In terms of thrust, what is unusual about the...Ch. 25 - Prob. 21RQCh. 25 - Prob. 22RQCh. 25 - What are the primary purposes of reaming?Ch. 25 - What are the advantages of shell reamers?Ch. 25 - A drill that operated satisfactorily for drilling...Ch. 25 - What precautionary procedures should be used when...Ch. 25 - What is the advantage of a spade drill? Is it...Ch. 25 - Prob. 28RQCh. 25 - Why does drill feed increase with drill size?Ch. 25 - Suppose you specified a drilling feed rate that...Ch. 25 - Suppose you wanted to drill a 1.5-in.-diameter...Ch. 25 - How much time will be required to drill the hole...Ch. 25 - What is the metal removal rate when a...Ch. 25 - If the specific horsepower for the steel in...Ch. 25 - If the specific power of an AISI 1020 steel of...Ch. 25 - Prob. 6PCh. 25 - Assume that you are drilling eight holes, equally...Ch. 25 - What machining difficulties should this process...Ch. 25 - Why were the distances between the holes too...
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- A o 20 mm through hole is to be drilled in a 30 mm thick plate using a double fluted, 120° lip angle drill The drill tip is at a distance of 3 mm from the plate surface when cutting is started and an over travel of 2 mm is recommended as a margin to ensure drilling through the full thickness of the plate. If the drill rotates at 500 rev/min and the feed per tooth is 0.01 mm,find the machining time of the operation.arrow_forwardA cutting tool has a nose radius of 1.8mm find the feed rate for a theoretical surface roughness of 5 microns.arrow_forward3. Through hole of 12 mm diameter is to be drilled in a steel plate of 20 mm thickness, drilled spindle speed is 20 m/min, feed 0.25 mm/rev and drill point angle is 120°, the amount of material removed at the first 10 sec after full engagement of drill will be .. (a) 2300, (b) 2400, (c) 2500, (d) 2600, (e) 2700 mm /sec.arrow_forward
- 2. Through hole of 12 mm diameter is to be drilled in a steel plate of 20 mm thickness, drilled spindle speed is 20 m/min, feed 0.25 mm/rev and drill point angle is 120°, the amount of material removed at the first 10 sec after full engagement of drill will be mm/sec. (a) 2300, (b) 2400, (c) 2500, (d) 2600, (e) 2700arrow_forwardHandwritten solution recommended. (1) A twist drill bit is used to drill a hole of diameter 2.0 at 4578.1 rpm at a feed rate of 2.5 in/min. Calculate the MRR in in^3/min. Take "pi" = 3.14. Round your answer to the nearest tenth.arrow_forwardWhy is speed important in a drilling operation ? What are the results of a drill bit with unequal lips ? Why should you not hold work by hand when drilling ?arrow_forward
- Sketch a radial drilling machine? Explain the working, advantages and disadvantages of a radial drilling machinearrow_forwardA 12" through hole is to be drilled in a 1 inch thick steel plate. A standard twist drill having a nose angle of 120 degrees is to be used. The drill press is set to operate at a cutting speed of 20 feet per minute and a feed of 0.010 ipr. What is the machining time required to drill the hole?arrow_forwardThrough holes of 10 mm diameter are to be drilled in a steel plate of 20 mm thickness. Drill spindle speed is 300 rpm, feed 0.2 mm/rev and drill point angle is 120° .Assuming drill overtravel of 2 mm. Calculate the time for producing a hole.arrow_forward
- Define Formation pore pressure? Why its important in drilling operations ?How much is the usual pressure overbalance ?arrow_forwardQ1\ a) The operation of drilling is to be done with a 25.4 mm ( diameter) twist drill in a brass workpiece. The hole is a blind-hole with the point angle = 118°, and a depth of 50 mm . The speed of 25 m/min, feed of 0.25 mm/rev. Calculate: (1) the time of cutting to complete the drilling operation, and (2) metal removal rate during the operation.arrow_forwardCalculate the RPM for drilling at 600 SFM and feed rate (in/min) for a chip load of .010 (in/rev) material is aluminumarrow_forward
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