Program:

//Definition of class "Sample"

public class Sample

{

    //Definition of class main

    public static void main(String[] args)

    {

        //Create a string

        String str = "Harry";

        //Get the length of the string

        int n = str.length();

        //Compute the inscription

        String mystery = str.substring(0, 1) +

        str...

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Chapter 2.5, Problem 28SC

Chapter 2.5, Problem 30SC

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int main(){ string str; int count = 0; // user input cout << "Enter string: "; cin >> str; int n = str.length(); // iterating over the string for (int i = 0; i < n - 1; i++) { // calling the fucntion to find the palidrome strings from the user input if (isPalindrome(0, i, str) && isPalindrome(i + 1, n - 1, str)) { // if 2 substring are palindrome then print them and increment count for (int x = 0; x < i + 1; x++) cout << str[x]; cout << " "; for (int x = i + 1; x < n; x++) cout << str[x]; count++; // break the loop after printing the palindrom string break; } } // if count is 0 then no palindrome subtring pair found if (count == 0) cout << "NO";} change this code to stdio.h string.h

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s1='18'; s2='1'; s3='2022'; s=int(s1)+int(s2)+int(s3); print(s)

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Program: //Definition of class "Sample" public class Sample { //Definition of class main public static void main(String[] args) { //Create a string String str = "Harry"; //Get the length of the string int n = str.length(); //Compute the inscription String mystery = str.substring(0, 1) + str...

Solution Summary: The author explains how the class "Sample" creates a string namely, "Harry", gets the length of the string, and then concatenates the resulting one-character strings.

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Program: //Definition of class "Sample" public class Sample { //Definition of class main public static void main(String[] args) { //Create a string String str = "Harry"; //Get the length of the string int n = str.length(); //Compute the inscription String mystery = str.substring(0, 1) + str...

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Chapter 2 Solutions