#include #include <ștdlib.h> #include int main() { int i, j; printf("Columns I JIn"); for (i = 1; i< 4; ++i) { printf("Outer %6d\n", i); for (j = 0; j < i; ++j) { printf(" Inner%10d\n", j); } } /* heading of outer for loop */ %3D /* heading of inner loop */ return (0); Create a new code modifying it to use "while loop" instead of the "for loop"

#include #include <ștdlib.h> #include int main() { int i, j; printf("Columns I JIn"); for (i = 1; i< 4; ++i) { printf("Outer %6d\n", i); for (j = 0; j < i; ++j) { printf(" Inner%10d\n", j); } } /* heading of outer for loop / %3D / heading of inner loop */ return (0); Create a new code modifying it to use "while loop" instead of the "for loop"

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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#include #include #include #define SIZE 5 int nums [SIZE] = [5,0,6,1,2); int main() { int i; pid_t pid; pid= fork(); if (pid == 0) { for (i = 0; i 0) { wait (NULL); } for (i = 0; i < SIZE; i++) printf("PARENT: %d\n", nums [i] + 1); /* LINE Y */ return 0; From the above-given program, please state what will be the output at lines X and Y. Explanation in detail required for output at both lines X and Y.
int sum = 0; for (int i 0; i < 5; i++){ sum += i; } cout << sum;
int main(){ long long int total; long long int init; scanf("%lld %lld", &total, &init); getchar(); long long int max = init; long long int min = init; int i; for (i = 0; i < total; i++) { char op1 = '0'; char op2 = '0'; long long int num1 = 0; long long int num2 = 0; scanf("%c %lld %c %lld", &op1, &num1, &op2, &num2); getchar(); long long int maxr = max; long long int minr = min; if (op1 == '+') { long long int sum = max + num1; maxr = sum; minr = sum; long long int res = min + num1; if (res > maxr) { max = res; } if (res < minr) { minr = res; } } else { long long int sum = max * num1; maxr = sum; minr = sum; long long int res = min * num1;…
#include <stdio.h>int main(){int d;int s[20],i, r, p, lg=0,m;char c;printf("Enter number of salesman(max 20): ");scanf("%d", &d);for(i=0; i<d; i++){ printf("\n salesman %d sales: ");scanf("%d", &s[i]);}for(i=0; i<d; i++){for(r=i+1; j<d; r++){if(s[i] > s[r]){p= s[i];s[i] = s[r];s[j] = p;}}}printf("\nsalesman lowest to highest: ");for(i=0; i<d; i++){printf("%d\t", s[i]);}for(i=0;i<m;i++){printf("\n highest sales: %d ",lg);if(lg<=s[i])lg=s[i];break;}getch();} >>> the upper part output should be like this enter number of salesman (max 20): 5 salesman 1 500 salesman 2 300 salesman 3 1000 salesman 4 200 salesman 5 1000 in the lower part the lowest to highest the output should become like this salesman 4 200 salesman 2 300 salesman 1 500 salesman 3 1000 salesman 5 1000 highest total sales : 2000
#include void main(void) { int c =2 ^3; cout<< c; }
CFG: Example 1 • Draw the CFG for the following code: int f(int n){ } int m = n* n; if (n < 0) else return 0; return m;
#include using namespace std; int main() { int numbers[10]; int i; for (i=0;i>numbers[i]; int numbers2[10],j,k; for(i=0;ic) { max1=rep; c=top; } } cout<
in c language !! typedef struct {long restaurant_id;char restaurant_name[10];char description[120];double rate;char cuisine[30]; opening_year;long capacity;char city[30];char address[60];char owner[30];} RECORD_t, *RECORD; RECdelete (unsigned long restaurant_id, RECORD *restaurant_array, unsigned long *p_size){int rec;int index;// index <- find the index of the RECORD with given restaurant_id in restaurant_array ????? (I DIDNT)if (index is valid)rec=restaurant_array[index];elserec=NULL;return rec;}
void funOne(int a, int& b, char v); void main() { int num1=10; char ch='A'; funOne(num1, 15,ch)<
#include <stdio.h>#include <string.h>#define SIZE 6struct Cake {char name[50];float price;};int searchChoice(char *choice, struct Cake data[]);void displayChoice(int index, struct Cake data[]);int main() {char choice[50];int index;//Answer for Part (i) – Declare and initialise array stockprintf("What is your choice of cake? ");gets(choice);index = searchChoice(choice, stock);displayChoice(index, stock);return 0;}//Answer for Part (ii) – Function definition for searchChoice//Answer for Part (iii) – Function definition for displayChoice
int* p: int a[3]{1, 2, 3}; p = a; What is the value of *(p+2)?
Match the C-function on the left to the Intel assemble function on the right. W: cmpl $4 movl %edi , %edi jmp .L4(,%rdi,8) %edi .L3: movl $17, %eax ret .15: movl $3, %eax int A ( int x , int y) { int a ; if ( x == 0 ) else i f ( x == 1 ) a = 3 ; else i f ( x == 2 ) a = 2 0 ; else i f ( x == 3 ) a = 2 ; else i f ( x == 4 ) a = 1 ; ret .L6: a = 17; movl $20, %eax ret .L7: movl $2, %eax ret else a = 0; .L8: return a ; movl $1, %eax .L2: ret . section .rodata . L4: .quad .L3 .quad .L5 .quad .L6 .quad .L7 .quad .L8 X: testl %edi, %edi je cmpl je cmpl je стр1 je cmpl .L16 $1, %edi .L17 $2, %edi .L18 $3, %edi int B (int x, int y) { int a; switch (x) { .L19 $4, %edi %al movzbl %al, %eax case 0: a = 17; break; sete break; case 1: a = 3; case 2: a = 20; break; case 3: a = 2; break; case 4: a = 1; a = 0; } return a; ret .L16: break; movl $17, %eax ret .L17: movl $3, %eax } ret .L18: movl $20, %eax ret .L19: movl ret $2, %eax